试试这个

if ([[UIScreen mainScreen] respondsToSelector:@selector(displayLinkWithTarget:selector:)] &&
    ([UIScreen mainScreen].scale == 2.0))
{
    // Retina display
    NSLog(@"---------------Retina display");
} else {
    // non-Retina display
    NSLog(@"---------------non-Retina display");
}

+(BOOL)iPhoneRetina{
    return ([[UIScreen mainScreen] respondsToSelector:@selector(displayLinkWithTarget:selector:)] && ([UIScreen mainScreen].scale == 2.0))?1:0;
}

这是对Matt MC的回答的重复。只是UIScreen上的一个类别。

#import "UIScreen+Util.h"

@implementation UIScreen (Util)

+ (BOOL) isRetinaDisplay {
    static BOOL retina = NO;
    static BOOL alreadyChecked = NO;
    if (!alreadyChecked) {
        UIScreen *mainScreen = self.mainScreen;
        if (mainScreen) {
            retina = mainScreen.scale > 1.0;
            alreadyChecked = YES;
        }
    }
    return retina;
}

@end

@sickp的答案是正确的。为了简化操作，将这一行添加到共享中。pch文件:

#define IS_RETINA ([[UIScreen mainScreen] respondsToSelector:@selector(displayLinkWithTarget:selector:)] && ([UIScreen mainScreen].scale >= 2.0))

然后在任何文件中你都可以这样做:

if(IS_RETINA)
{
   // etc..
}

比较浮点值是否相等总是让人感觉有点不可靠。 两者我都喜欢

[UIScreen mainScreen].scale > 1.0;

or

[UIScreen mainScreen].scale < 2.0;

以上答案的Swift版本，>= 2.0规模，因此它包括iPhone 6+和其他未来的高于retina规模的设备:

 if UIScreen.mainScreen().respondsToSelector(Selector("scale")) && UIScreen.mainScreen().scale >= 2.0 {
    // code executed only on Retina device
}