我有几个按钮作为路径。每次改变路线时,我都想确保激活的按钮发生了变化。
有没有办法在react路由器v4中监听路由变化?
我有几个按钮作为路径。每次改变路线时,我都想确保激活的按钮发生了变化。
有没有办法在react路由器v4中监听路由变化?
当前回答
用钩子:
import { useEffect } from 'react'
import { withRouter } from 'react-router-dom'
import { history as historyShape } from 'react-router-prop-types'
const DebugHistory = ({ history }) => {
useEffect(() => {
console.log('> Router', history.action, history.location)
}, [history.location.key])
return null
}
DebugHistory.propTypes = { history: historyShape }
export default withRouter(DebugHistory)
导入并呈现为<DebugHistory>组件
其他回答
withRouter,历史。listen,和useEffect (React Hooks)一起工作得很好:
import React, { useEffect } from 'react'
import { withRouter } from 'react-router-dom'
const Component = ({ history }) => {
useEffect(() => history.listen(() => {
// do something on route change
// for my example, close a drawer
}), [])
//...
}
export default withRouter(Component)
侦听器回调将在路由更改时触发,并返回历史记录。listen是一个关闭处理程序,可以很好地与useEffect一起使用。
用钩子:
import { useEffect } from 'react'
import { withRouter } from 'react-router-dom'
import { history as historyShape } from 'react-router-prop-types'
const DebugHistory = ({ history }) => {
useEffect(() => {
console.log('> Router', history.action, history.location)
}, [history.location.key])
return null
}
DebugHistory.propTypes = { history: historyShape }
export default withRouter(DebugHistory)
导入并呈现为<DebugHistory>组件
对于功能组件,请尝试使用props.location中的useEffect。
import React, {useEffect} from 'react';
const SampleComponent = (props) => {
useEffect(() => {
console.log(props.location);
}, [props.location]);
}
export default SampleComponent;
import React, { useEffect } from 'react';
import { useLocation } from 'react-router';
function MyApp() {
const location = useLocation();
useEffect(() => {
console.log('route has been changed');
...your code
},[location.pathname]);
}
用钩子
对于react Hooks,我使用useEffect
import React from 'react'
const history = useHistory()
const queryString = require('query-string')
const parsed = queryString.parse(location.search)
const [search, setSearch] = useState(parsed.search ? parsed.search : '')
useEffect(() => {
const parsedSearch = parsed.search ? parsed.search : ''
if (parsedSearch !== search) {
// do some action! The route Changed!
}
}, [location.search])
在这个例子中,当路由改变时,我向上滚动:
import React from 'react'
import { useLocation } from 'react-router-dom'
const ScrollToTop = () => {
const location = useLocation()
React.useEffect(() => {
window.scrollTo(0, 0)
}, [location.key])
return null
}
export default ScrollToTop