如果两个值都不存在,我如何推入数组?这是我的数组:
[
{ name: "tom", text: "tasty" },
{ name: "tom", text: "tasty" },
{ name: "tom", text: "tasty" },
{ name: "tom", text: "tasty" },
{ name: "tom", text: "tasty" }
]
如果我试图再次推入数组的名字:“tom”或文本:“tasty”,我不希望发生任何事情…但如果这两个都不存在那么我就输入。push()
我该怎么做呢?
推动动态
var a = [
{name:"bull", text: "sour"},
{name: "tom", text: "tasty" },
{name: "Jerry", text: "tasty" }
]
function addItem(item) {
var index = a.findIndex(x => x.name == item.name)
if (index === -1) {
a.push(item);
}else {
console.log("object already exists")
}
}
var item = {name:"bull", text: "sour"};
addItem(item);
用简单的方法
var item = {name:"bull", text: "sour"};
a.findIndex(x => x.name == item.name) == -1 ? a.push(item) : console.log("object already exists")
如果数组只包含基元类型/简单数组
var b = [1, 7, 8, 4, 3];
var newItem = 6;
b.indexOf(newItem) === -1 && b.push(newItem);
我有这个问题,我做了一个简单的原型,使用它,如果你喜欢它
Array.prototype.findOrPush = function(predicate, fallbackVal) {
let item = this.find(predicate)
if(!item){
item = fallbackVal
this.push(item)
}
return item
}
let arr = [{id: 1}]
let item = arr.findOrPush(e => e.id == 2, {id: 2})
console.log(item) // {id: 2}
// will not push and just return existing value
arr.findOrPush(e => e.id == 2, {id: 2})
conslog.log(arr) // [{id: 1}, {id: 2}]
使用数组是很容易做到的。函数findIndex,它以函数作为参数:
var arrayObj = [{name:"bull", text: "sour"},
{ name: "tom", text: "tasty" },
{ name: "tom", text: "tasty" }
]
var index = arrayObj.findIndex(x => x.name=="bob");
// here you can check specific property for an object whether it exist in your array or not
index === -1 ? arrayObj.push({your_object}) : console.log("object already exists")
可以使用带有回调函数及其"this"参数的findIndex方法。
注意:旧的浏览器不知道findIndex,但是一个polyfill是可用的。
示例代码(注意,在原始问题中,只有当一个新对象的数据都不在之前的推送对象中时,它才会被推送):
var a=[{name:"tom", text:"tasty"}], b;
var magic=function(e) {
return ((e.name == this.name) || (e.text == this.text));
};
b={name:"tom", text:"tasty"};
if (a.findIndex(magic,b) == -1)
a.push(b); // nothing done
b={name:"tom", text:"ugly"};
if (a.findIndex(magic,b) == -1)
a.push(b); // nothing done
b={name:"bob", text:"tasty"};
if (a.findIndex(magic,b) == -1)
a.push(b); // nothing done
b={name:"bob", text:"ugly"};
if (a.findIndex(magic,b) == -1)
a.push(b); // b is pushed into a