如果两个值都不存在,我如何推入数组?这是我的数组:

[
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" }
]

如果我试图再次推入数组的名字:“tom”或文本:“tasty”,我不希望发生任何事情…但如果这两个都不存在那么我就输入。push()

我该怎么做呢?


当前回答

这个问题有点老了,但我的选择是

    let finalTab = [{id: 1, name: 'dupont'}, {id: 2, name: 'tintin'}, {id: 3, name:'toto'}]; // Your array of object you want to populate with distinct data
    const tabToCompare = [{id: 1, name: 'dupont'}, {id: 4, name: 'tata'}]; // A array with 1 new data and 1 is contain into finalTab
    
    finalTab.push(
      ...tabToCompare.filter(
        tabToC => !finalTab.find(
          finalT => finalT.id === tabToC.id)
      )
    ); // Just filter the first array, and check if data into tabToCompare is not into finalTab, finally push the result of the filters

    console.log(finalTab); // Output : [{id: 1, name: 'dupont'}, {id: 2, name: 'tintin'}, {id: 3, name: 'toto'}, {id: 4, name: 'tata'}];

其他回答

我想我在这里回答太迟了,然而这是我最终想出的一个邮件管理器我写。好的,这就是我需要的。

窗口。ListManager = []; $(' #添加').click(函数(){ / /你的功能 let data =Math.floor(Math.random() * 5) + 1 如果(window.ListManager.includes(数据)){ Console.log("数据存在于列表") 其他}{ window.ListManager.push(数据); } $(' #结果')。text (window.ListManager); }); < script src = " https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js " > < /脚本> <标题>独特列表< / h1 > < p id = "结果" > < / p > </button> . <button id="add">添加到列表中

使用数组是很容易做到的。函数findIndex,它以函数作为参数:

var arrayObj = [{name:"bull", text: "sour"},
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" }
]
var index = arrayObj.findIndex(x => x.name=="bob"); 
// here you can check specific property for an object whether it exist in your array or not

index === -1 ? arrayObj.push({your_object}) : console.log("object already exists")
 
someArray = [{a: 'a1 value', b: {c: "c1 value"},
             {a: 'a2 value', b: {c: "c2 value"}]
newObject = {a: 'a2 value', b: {c: "c2 value"}}

//New object which needs check for duplicity

let isExists = checkForExists(newObject) {
    return someArray.some(function(el) {
        return el.a === newObject.a && el.b.c === newObject.b.c;
    });
}
// write your logic here 
// if isExists is true then already object in an array else you can add

对于字符串数组(但不是对象数组),你可以通过调用.indexOf()来检查一个项是否存在,如果不存在,则将该项推入数组:

var newItem = "NEW_ITEM_TO_ARRAY"; var array = ["OLD_ITEM_1", "OLD_ITEM_2"]; array.indexOf(newItem) === -1 ?array.push(newItem): console.log("此项已存在"); console.log(数组)

我知道这是一个非常老的问题,但如果你使用ES6,你可以使用一个非常小的版本:

[1,2,3].filter(f => f !== 3).concat([3])

非常简单,首先添加一个过滤器,删除项目-如果它已经存在,然后通过concat添加它。

下面是一个更现实的例子:

const myArray = ['hello', 'world']
const newArrayItem

myArray.filter(f => f !== newArrayItem).concat([newArrayItem])

如果你的数组包含对象,你可以像这样调整过滤器函数:

someArray.filter(f => f.some(s => s.id === myId)).concat([{ id: myId }])