这个问题有点老了，但我的选择是

    let finalTab = [{id: 1, name: 'dupont'}, {id: 2, name: 'tintin'}, {id: 3, name:'toto'}]; // Your array of object you want to populate with distinct data
    const tabToCompare = [{id: 1, name: 'dupont'}, {id: 4, name: 'tata'}]; // A array with 1 new data and 1 is contain into finalTab
    
    finalTab.push(
      ...tabToCompare.filter(
        tabToC => !finalTab.find(
          finalT => finalT.id === tabToC.id)
      )
    ); // Just filter the first array, and check if data into tabToCompare is not into finalTab, finally push the result of the filters

    console.log(finalTab); // Output : [{id: 1, name: 'dupont'}, {id: 2, name: 'tintin'}, {id: 3, name: 'toto'}, {id: 4, name: 'tata'}];

当你希望通过对象的特定属性进行搜索时，我使用了map和reduce来做到这一点，因为直接进行对象相等通常会失败。

var newItem = {'unique_id': 123};
var searchList = [{'unique_id' : 123}, {'unique_id' : 456}];

hasDuplicate = searchList
   .map(function(e){return e.unique_id== newItem.unique_id})
   .reduce(function(pre, cur) {return pre || cur});

if (hasDuplicate) {
   searchList.push(newItem);
} else {
   console.log("Duplicate Item");
}

这里你有一种方法可以在一行中为两个数组做这件事:

const startArray = [1,2,3,4]
const newArray = [4,5,6]

const result = [...startArray, ...newArray.filter(a => !startArray.includes(a))]

console.log(result);
//Result: [1,2,3,4,5,6]

简单的代码，如果'indexOf'返回'-1'，这意味着元素不在数组中，那么条件'=== -1'检索true/false。

'&&'操作符表示'and'，因此如果第一个条件为真，则将其推入数组。

array.indexOf(newItem) === -1 && array.push(newItem);

如果不在列表中，则添加

对于一个简单值的列表，它是一行程序…

[...new Set([...someArray, someElement])]

JavaScript的用法:

var myArray = ['bill','bob']
var alreadyIn = [...new Set([...myArray, 'bob'])] // ['bill','bob']
var notAlreadyIn = [...new Set([...myArray, 'peter'])] // ['bill','bob','peter']

TypeScript文本(注意include vs includes):

interface Array<T> {
  include(element: T): Array<T>
}
Array.prototype.include = function (element: any): any[] {
  return [...new Set([...this, obj])]
}

.．.但对于对象来说，情况就复杂多了

[...new Set([...someArray.map((o) => JSON.stringify(o)),
    JSON.stringify(someElement)]).map((o) => JSON.parse(o))

TypeScript文本处理任何事情:

Array.prototype.include = function (element: any): any[] {
  if (element && typeof element === 'object')
    return [
      ...new Set([
        ...this.map((o) => JSON.stringify(o)),
        JSON.stringify(element),
      ]),
    ].map((o) => JSON.parse(o))
  else return [...new Set([...this, element])]
}

我更喜欢使用原生js Array.prototype.some()，即使在jqenv中 文档:w3s some or mdn some

let arr = [
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" }
];
let oneMore = { name: "tom", text: "tasty" };
!arr.some(i => i.name == oneMore.name && i.text == oneMore.text)
  && arr.push(oneMore);