在你的活动中声明静态变量

public static HashMap<String,ContactsModal> contactItems=new HashMap<String, ContactsModal>();

然后在你的片段中像这样做

ActivityName.contactItems.put(Number,contactsModal);

只是偶然发现了这个问题，而上面的大多数方法都是有效的。 我只是想补充一点，你可以使用事件总线库，特别是在组件(活动或片段)还没有创建的情况下，它适用于所有规模的android项目和许多用例。我个人在我在playstore上的几个项目中使用过它。

将数据从活动类发送到片段的更好方法是通过setter方法传递。就像

FragmentClass fragmentClass = new FragmentClass();
fragmentClass.setMyList(mylist);
fragmentClass.setMyString(myString);
fragmentClass.setMyMap(myMap);

并且很容易从类中获得这些数据。

Very old post, still I dare to add a little explanation that would had been helpful for me. Technically you can directly set members of any type in a fragment from activity. So why Bundle? The reason is very simple - Bundle provides uniform way to handle:-- creating/opening fragment -- reconfiguration (screen rotation) - just add initial/updated bundle to outState in onSaveInstanceState() -- app restoration after being garbage collected in background (as with reconfiguration). You can (if you like experiments) create a workaround in simple situations but Bundle-approach just doesn't see difference between one fragment and one thousand on a backstack - it stays simple and straightforward. That's why the answer by @Elenasys is the most elegant and universal solution. And that's why the answer given by @Martin has pitfalls

我在这里@ stackoverflow.com找到了很多答案，但这绝对是正确的答案:

“发送数据从活动碎片在android”。

活动:

        Bundle bundle = new Bundle();
        String myMessage = "Stackoverflow is cool!";
        bundle.putString("message", myMessage );
        FragmentClass fragInfo = new FragmentClass();
        fragInfo.setArguments(bundle);
        transaction.replace(R.id.fragment_single, fragInfo);
        transaction.commit();

片段:

读取片段中的值

        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        Bundle bundle = this.getArguments();
        String myValue = bundle.getString("message");
        ...
        ...
        ...
        }

或者只是

        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        String myValue = this.getArguments().getString("message");
        ...
        ...
        ...
        }

有时你可以在你的活动中接收Intent，你需要将信息传递给你的工作片段。 给出的答案是OK，如果你需要启动片段，但如果它仍在工作，setArguments()不是很有用。 如果传递的信息将导致与UI交互，则会出现另一个问题。在这种情况下，你不能调用像myfragment.passData()这样的东西，因为android会迅速告诉只有创建视图的线程可以与之交互。

所以我的建议是使用接收器。这样，您可以从任何地方发送数据，包括活动，但是工作将在片段的上下文中完成。

在你的片段的onCreate():

protected DataReceiver dataReceiver;
public static final String REC_DATA = "REC_DATA";

@Override
public void onCreate(Bundle savedInstanceState) {


    data Receiver = new DataReceiver();
    intentFilter = new IntentFilter(REC_DATA);

    getActivity().registerReceiver(dataReceiver, intentFilter);
}

private class DataReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {

        int data= intent.getIntExtra("data", -1);

        // Do anything including interact with your UI
    }
}

在你的活动:

// somewhere
Intent retIntent = new Intent(RE_DATA);
retIntent.putExtra("data", myData);
sendBroadcast(retIntent);