将数据从活动类发送到片段的更好方法是通过setter方法传递。就像

FragmentClass fragmentClass = new FragmentClass();
fragmentClass.setMyList(mylist);
fragmentClass.setMyString(myString);
fragmentClass.setMyMap(myMap);

并且很容易从类中获得这些数据。

你也可以从片段访问活动数据:

活动:

public class MyActivity extends Activity {

    private String myString = "hello";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_my);
        ...
    }

    public String getMyData() {
        return myString;
    }
}

片段:

public class MyFragment extends Fragment {

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {

        MyActivity activity = (MyActivity) getActivity();
        String myDataFromActivity = activity.getMyData();
        return view;
    }
}

Very old post, still I dare to add a little explanation that would had been helpful for me. Technically you can directly set members of any type in a fragment from activity. So why Bundle? The reason is very simple - Bundle provides uniform way to handle:-- creating/opening fragment -- reconfiguration (screen rotation) - just add initial/updated bundle to outState in onSaveInstanceState() -- app restoration after being garbage collected in background (as with reconfiguration). You can (if you like experiments) create a workaround in simple situations but Bundle-approach just doesn't see difference between one fragment and one thousand on a backstack - it stays simple and straightforward. That's why the answer by @Elenasys is the most elegant and universal solution. And that's why the answer given by @Martin has pitfalls

从Activity中，你用Bundle发送数据为:

Bundle bundle = new Bundle();
bundle.putString("data", "Data you want to send");

// Your fragment
MyFragment obj = new MyFragment();
obj.setArguments(bundle);

并在Fragment的onCreateView方法中获取数据:

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) 
{
    String data = getArguments().getString("data");// data which sent from activity  
    return inflater.inflate(R.layout.myfragment, container, false);
}

如果你将片段(具体子类)的引用传递给异步任务，你就可以直接访问片段。

将片段引用传递给异步任务的一些方法:

如果你的异步任务是一个完全成熟的类(类FooTask扩展AsyncTask)，那么将你的片段传递到构造函数中。 如果您的异步任务是一个内部类，只需在异步任务定义的范围内声明一个最终的Fragment变量，或者作为外部类的字段。您将能够从内部类访问它。

这个答案可能太迟了。但它对未来的读者是有用的。

我有一些标准。我已经为从意图中选择文件编写了代码。并将选定的文件传递到特定片段进行进一步处理。我有许多片段具有文件选择的功能。当时，每次检查条件，获取片段并传递值都是很恶心的。因此，我决定使用接口传递值。

步骤1:在Main Activity上创建接口。

   public interface SelectedBundle {
    void onBundleSelect(Bundle bundle);
   }

步骤2:在同一个活动上创建selectebundle引用

   SelectedBundle selectedBundle;

步骤3:在同一个活动中创建方法

   public void setOnBundleSelected(SelectedBundle selectedBundle) {
       this.selectedBundle = selectedBundle;
   }

步骤4:需要初始化selectebundle引用，这些引用都是片段需要文件选择器功能。你把这段代码放在fragment onCreateView(..)方法上

    ((MainActivity)getActivity()).setOnBundleSelected(new MainActivity.SelectedBundle() {
          @Override
         public void onBundleSelect(Bundle bundle) {
            updateList(bundle);
        }
     });

第5步:我的情况下，我需要通过图像Uri从HomeActivity片段。所以，我在onActivityResult方法上使用了这个功能。

来自MainActivity的onActivityResult，使用接口将值传递给片段。

注意:您的情况可能不同。你可以从你的HomeActivity的任何地方调用它。

 @Override
 protected void onActivityResult(int requestCode, int resultCode, Intent  data) {
       selectedBundle.onBundleSelect(bundle);
  }

这一切。在FragmentClass上实现你需要的每个片段。你很棒。你做到了。哇……