分割方法

data = input_string
df = pd.DataFrame([x.split(';') for x in data.split('\n')])
print(df)

分割方法

data = input_string
df = pd.DataFrame([x.split(';') for x in data.split('\n')])
print(df)

Emample:

text = [ ['This is the NLP TASKS ARTICLE written by Anjum**'] ,['IN this article I”ll be explaining various DATA-CLEANING techniques '], ['So stay tuned for FURther More && '],['Nah I dont think he goes to usf ; he lives around']]
df = pd.DataFrame({'text':text})

输出

对象:获取字符串make dataframe。

解决方案

def str2frame(estr, sep = ',', lineterm = '\n', set_header = True):
    dat = [x.split(sep) for x in estr.split(lineterm)][1:-1]
    df = pd.DataFrame(dat)
    if set_header:
        df = df.T.set_index(0, drop = True).T # flip, set ix, flip back
    return df

例子

estr = """
sym,date,strike,genus
APPLE,20MAY20,50.0,Malus
ORANGE,22JUL20,50.0,Rutaceae
"""

df = str2frame(estr)

print(df)
0     sym     date strike     genus
1   APPLE  20MAY20   50.0     Malus
2  ORANGE  22JUL20   50.0  Rutaceae

一种简单的方法是使用StringIO。StringIO (python2)或io。StringIO (python3)并将其传递给pandas。read_csv函数。例句:

import sys
if sys.version_info[0] < 3: 
    from StringIO import StringIO
else:
    from io import StringIO

import pandas as pd

TESTDATA = StringIO("""col1;col2;col3
    1;4.4;99
    2;4.5;200
    3;4.7;65
    4;3.2;140
    """)

df = pd.read_csv(TESTDATA, sep=";")

在一行中，但首先导入io

import pandas as pd
import io   

TESTDATA="""col1;col2;col3
1;4.4;99
2;4.5;200
3;4.7;65
4;3.2;140
"""

df = pd.read_csv(io.StringIO(TESTDATA), sep=";")
print(df)