var大小=[“字节”,“知识库”,“m”,“g”,“结核”,“铅”、“海尔哥哥”,“ZB”,“YB”); 函数formatBytes(字节，小数){ For (var I = 0, r = bytes, b = 1024;R > b;I ++) r /= b; 返回' ${parseFloat(r.toFixed(decimal))} ${SIZES[i]} '; ｝

这对我很有用。

bytesForHuman(bytes) {
    let units = ['B', 'KB', 'MB', 'GB', 'TB', 'PB']

    let i = 0
    
    for (i; bytes > 1024; i++) {
        bytes /= 1024;
    }

    return bytes.toFixed(1) + ' ' + units[i]
}

我有一个问题的元数据从服务器返回不同大小的单位。我使用了@Alicejim response，并试图让它更通用。在这里分享代码，也许会帮助到一些人。

enum SizeUnits {
   Bytes = 'Bytes',
   KB = 'KB',
   MB = 'MB',
   GB = 'GB',
   TB = 'TB',
   PB = 'PB',
   EB = 'EB',
   ZB = 'ZB',
   YB = 'YB'
}
function convertSizeUnites(size: number, sourceSizeUnits: SizeUnits, targetSizeUnits: SizeUnits) {
    const i = Object.keys(SizeUnits).indexOf(sourceSizeUnits);
    const sizeInBytes = size * Math.pow(1024, i);
    const j = Object.keys(SizeUnits).indexOf(targetSizeUnits);
    return sizeInBytes / Math.pow(1024, j);
}
function formatSize(size: number, measureUnit: SizeUnits, decimals = 2) {
    if (size === 0) return '0 Bytes';
    const sizeInBytes = convertSizeUnites(size, measureUnit, SizeUnits.Bytes);
    const dm = decimals < 0 ? 0 : decimals;
    const i = Math.floor(Math.log(sizeInBytes) / Math.log(1024));
    return parseFloat((sizeInBytes / Math.pow(1024, i)).toFixed(dm)) + ' ' + 
    Object.keys(SizeUnits)[i];
}

由此可见:(来源)

Unminified and es6’ed:(社区)

function formatBytes(bytes, decimals = 2) { if (!+bytes) return '0 Bytes' const k = 1024 const dm = decimals < 0 ? 0 : decimals const sizes = ['Bytes', 'KB', 'MB', 'GB', 'TB', 'PB', 'EB', 'ZB', 'YB'] const i = Math.floor(Math.log(bytes) / Math.log(k)) return `${parseFloat((bytes / Math.pow(k, i)).toFixed(dm))} ${sizes[i]}` } // Demo code document.body.innerHTML += `<input type="text" oninput="document.querySelector('p').innerHTML=formatBytes(this.value)" value="1000"><p>1000 Bytes</p>`

简化版(由StackOverflow社区提供，由JSCompress提供)

function formatBytes(a,b=2){if(!+a)return"0 Bytes";const c=0>b?0:b,d=Math.floor(Math.log(a)/Math.log(1024));return`${parseFloat((a/Math.pow(1024,d)).toFixed(c))} ${["Bytes","KB","MB","GB","TB","PB","EB","ZB","YB"][d]}`}

用法:

// formatBytes(bytes, decimals)

formatBytes(1024)       // 1 KB
formatBytes('1024')     // 1 KB
formatBytes(1234)       // 1.21 KB
formatBytes(1234, 3)    // 1.205 KB
formatBytes(0)          // 0 Bytes
formatBytes('0')        // 0 Bytes

PS:更改k = 1000或大小=["…如你所愿(比特或字节)

我只是想分享我的想法。我遇到了这个问题，所以我的解决方案是这样的。这将把低单位转换为高单位，反之亦然，只需提供参数toUnit和fromUnit

export function fileSizeConverter(size: number, fromUnit: string, toUnit: string ): number | string {
  const units: string[] = ['B', 'KB', 'MB', 'GB', 'TB'];
  const from = units.indexOf(fromUnit.toUpperCase());
  const to = units.indexOf(toUnit.toUpperCase());
  const BASE_SIZE = 1024;
  let result: number | string = 0;

  if (from < 0 || to < 0 ) { return result = 'Error: Incorrect units'; }

  result = from < to ? size / (BASE_SIZE ** to) : size * (BASE_SIZE ** from);

  return result.toFixed(2);
}

我从这里得到了灵感

使用位操作将是一个更好的解决方案。试试这个

function formatSizeUnits(bytes)
{
    if ( ( bytes >> 30 ) & 0x3FF )
        bytes = ( bytes >>> 30 ) + '.' + ( bytes & (3*0x3FF )) + 'GB' ;
    else if ( ( bytes >> 20 ) & 0x3FF )
        bytes = ( bytes >>> 20 ) + '.' + ( bytes & (2*0x3FF ) ) + 'MB' ;
    else if ( ( bytes >> 10 ) & 0x3FF )
        bytes = ( bytes >>> 10 ) + '.' + ( bytes & (0x3FF ) ) + 'KB' ;
    else if ( ( bytes >> 1 ) & 0x3FF )
        bytes = ( bytes >>> 1 ) + 'Bytes' ;
    else
        bytes = bytes + 'Byte' ;
    return bytes ;
}