我有一个问题的元数据从服务器返回不同大小的单位。我使用了@Alicejim response，并试图让它更通用。在这里分享代码，也许会帮助到一些人。

enum SizeUnits {
   Bytes = 'Bytes',
   KB = 'KB',
   MB = 'MB',
   GB = 'GB',
   TB = 'TB',
   PB = 'PB',
   EB = 'EB',
   ZB = 'ZB',
   YB = 'YB'
}
function convertSizeUnites(size: number, sourceSizeUnits: SizeUnits, targetSizeUnits: SizeUnits) {
    const i = Object.keys(SizeUnits).indexOf(sourceSizeUnits);
    const sizeInBytes = size * Math.pow(1024, i);
    const j = Object.keys(SizeUnits).indexOf(targetSizeUnits);
    return sizeInBytes / Math.pow(1024, j);
}
function formatSize(size: number, measureUnit: SizeUnits, decimals = 2) {
    if (size === 0) return '0 Bytes';
    const sizeInBytes = convertSizeUnites(size, measureUnit, SizeUnits.Bytes);
    const dm = decimals < 0 ? 0 : decimals;
    const i = Math.floor(Math.log(sizeInBytes) / Math.log(1024));
    return parseFloat((sizeInBytes / Math.pow(1024, i)).toFixed(dm)) + ' ' + 
    Object.keys(SizeUnits)[i];
}

function bytes2Size(byteVal){
    var units=["Bytes", "KB", "MB", "GB", "TB"];
    var kounter=0;
    var kb= 1024;
    var div=byteVal/1;
    while(div>=kb){
        kounter++;
        div= div/kb;
    }
    return div.toFixed(1) + " " + units[kounter];
}

只是稍微修改了@zayarTun答案的代码，以包括一个额外的参数，表示结果中的小数数(如果小数为零，则不需要显示像15.00 KB这样的结果，而是15 KB就足够了，这就是为什么我在parseFloat()中包装结果值)

  bytesForHuman(bytes, decimals = 2) {
    let units = ['B', 'KB', 'MB', 'GB', 'TB', 'PB']

    let i = 0
    
    for (i; bytes > 1024; i++) {
        bytes /= 1024;
    }

    return parseFloat(bytes.toFixed(decimals)) + ' ' + units[i]
  }

由此可见:(来源)

Unminified and es6’ed:(社区)

function formatBytes(bytes, decimals = 2) { if (!+bytes) return '0 Bytes' const k = 1024 const dm = decimals < 0 ? 0 : decimals const sizes = ['Bytes', 'KB', 'MB', 'GB', 'TB', 'PB', 'EB', 'ZB', 'YB'] const i = Math.floor(Math.log(bytes) / Math.log(k)) return `${parseFloat((bytes / Math.pow(k, i)).toFixed(dm))} ${sizes[i]}` } // Demo code document.body.innerHTML += `<input type="text" oninput="document.querySelector('p').innerHTML=formatBytes(this.value)" value="1000"><p>1000 Bytes</p>`

简化版(由StackOverflow社区提供，由JSCompress提供)

function formatBytes(a,b=2){if(!+a)return"0 Bytes";const c=0>b?0:b,d=Math.floor(Math.log(a)/Math.log(1024));return`${parseFloat((a/Math.pow(1024,d)).toFixed(c))} ${["Bytes","KB","MB","GB","TB","PB","EB","ZB","YB"][d]}`}

用法:

// formatBytes(bytes, decimals)

formatBytes(1024)       // 1 KB
formatBytes('1024')     // 1 KB
formatBytes(1234)       // 1.21 KB
formatBytes(1234, 3)    // 1.205 KB
formatBytes(0)          // 0 Bytes
formatBytes('0')        // 0 Bytes

PS:更改k = 1000或大小=["…如你所愿(比特或字节)

const byteConversion = (bytes: number, decimals = 2) => {
if (bytes === 0) return '0 B';

const kiloByte = 1000;
const decimal = decimals < 0 ? 0 : decimals;
const sizes = ['B', 'KB', 'MB', 'GB', 'TB', 'PB', 'EB', 'ZB', 'YB'];

const i: number = Math.floor(Math.log(bytes) / Math.log(kiloByte));

return `${parseFloat((bytes / kiloByte ** i).toFixed(decimal))} ${sizes[i]}`;

};

我正在更新@ al冰岛的答案。由于小数点对于1,2位数的数字很重要，所以我舍入了第一个小数点并保留第一个小数点。对于3位数的数字，我舍入个位数，忽略所有小数点后的位置。

getMultiplers : function(bytes){
    var unit = 1000 ;
    if (bytes < unit) return bytes ;
    var exp = Math.floor(Math.log(bytes) / Math.log(unit));
    var pre = "kMGTPE".charAt(exp-1);
    var result = bytes / Math.pow(unit, exp);
    if(result/100 < 1)
        return (Math.round( result * 10 ) / 10) +pre;
    else
        return Math.round(result) + pre;
}