这个解决方案建立在以前的解决方案的基础上，但同时考虑了公制和二进制单位:

function formatBytes(bytes, decimals, binaryUnits) {
    if(bytes == 0) {
        return '0 Bytes';
    }
    var unitMultiple = (binaryUnits) ? 1024 : 1000; 
    var unitNames = (unitMultiple === 1024) ? // 1000 bytes in 1 Kilobyte (KB) or 1024 bytes for the binary version (KiB)
        ['Bytes', 'KiB', 'MiB', 'GiB', 'TiB', 'PiB', 'EiB', 'ZiB', 'YiB']: 
        ['Bytes', 'KB', 'MB', 'GB', 'TB', 'PB', 'EB', 'ZB', 'YB'];
    var unitChanges = Math.floor(Math.log(bytes) / Math.log(unitMultiple));
    return parseFloat((bytes / Math.pow(unitMultiple, unitChanges)).toFixed(decimals || 0)) + ' ' + unitNames[unitChanges];
}

例子:

formatBytes(293489203947847, 1);    // 293.5 TB
formatBytes(1234, 0);   // 1 KB
formatBytes(4534634523453678343456, 2); // 4.53 ZB
formatBytes(4534634523453678343456, 2, true));  // 3.84 ZiB
formatBytes(4566744, 1);    // 4.6 MB
formatBytes(534, 0);    // 534 Bytes
formatBytes(273403407, 0);  // 273 MB

根据al冰岛m的答案，我在小数点后去掉了0:

function formatBytes(bytes, decimals) {
    if(bytes== 0)
    {
        return "0 Byte";
    }
    var k = 1024; //Or 1 kilo = 1000
    var sizes = ["Bytes", "KB", "MB", "GB", "TB", "PB"];
    var i = Math.floor(Math.log(bytes) / Math.log(k));
    return parseFloat((bytes / Math.pow(k, i)).toFixed(decimals)) + " " + sizes[i];
}

var大小=[“字节”,“知识库”,“m”,“g”,“结核”,“铅”、“海尔哥哥”,“ZB”,“YB”); 函数formatBytes(字节，小数){ For (var I = 0, r = bytes, b = 1024;R > b;I ++) r /= b; 返回' ${parseFloat(r.toFixed(decimal))} ${SIZES[i]} '; ｝

function bytes2Size(byteVal){
    var units=["Bytes", "KB", "MB", "GB", "TB"];
    var kounter=0;
    var kb= 1024;
    var div=byteVal/1;
    while(div>=kb){
        kounter++;
        div= div/kb;
    }
    return div.toFixed(1) + " " + units[kounter];
}

我使用递归和分配水平变量为适当的单位。

函数getReadableByte(count, decimal=0, level=0) { 让unitList =[“字节”,“知识库”,“m”,“g”、“肺结核”,“PT”); if (count >= 1024.0 && (level+1 < unitList.length)) { 返回getReadableByte(count/1024, decimal， ++level) ｝ 返回' ${小数?(count).toFixed(decimal): Math.round(count)}${unitList[level]} ' ｝ 2) console.log (getReadableByte (120)

function bytesToSize(bytes) { var sizes = ['B', 'K', 'M', 'G', 'T', 'P']; for (var i = 0; i < sizes.length; i++) { if (bytes <= 1024) { return bytes + ' ' + sizes[i]; } else { bytes = parseFloat(bytes / 1024).toFixed(2) } } return bytes + ' P'; } console.log(bytesToSize(234)); console.log(bytesToSize(2043)); console.log(bytesToSize(20433242)); console.log(bytesToSize(2043324243)); console.log(bytesToSize(2043324268233)); console.log(bytesToSize(2043324268233343));