我有一个这样的字符串:

abc=foo&def=%5Basf%5D&xyz=5

如何将其转换为这样的JavaScript对象?

{
  abc: 'foo',
  def: '[asf]',
  xyz: 5
}

当前回答

ES6有一个非常简单而不正确的答案:

console.log(
  Object.fromEntries(new URLSearchParams(`abc=foo&def=%5Basf%5D&xyz=5`))
);

但是这一行代码不包括多个相同的键,你必须使用更复杂的东西:

function parseParams(params) {
  const output = [];
  const searchParams = new URLSearchParams(params);

  // Set will return only unique keys()
  new Set([...searchParams.keys()])
    .forEach(key => {
      output[key] = searchParams.getAll(key).length > 1 ?  
        searchParams.getAll(key) : // get multiple values
        searchParams.get(key); // get single value
    });

  return output;
}

console.log(
   parseParams('abc=foo&cars=Ford&cars=BMW&cars=Skoda&cars=Mercedes')
)

代码将生成如下结构:

[
  abc: "foo"
  cars: ["Ford", "BMW", "Skoda", "Mercedes"]
]

其他回答

有一个名为YouAreI.js的轻量级库,它经过测试,使这个非常简单。

YouAreI = require('YouAreI')
uri = new YouAreI('http://user:pass@www.example.com:3000/a/b/c?d=dad&e=1&f=12.3#fragment');

uri.query_get() => { d: 'dad', e: '1', f: '12.3' }

下面是硅制品方法的一个更简化的版本。

下面的函数可以从USVString或Location解析查询字符串。

/** * Returns a plain object representation of a URLSearchParams object. * @param {USVString} search - A URL querystring * @return {Object} a key-value pair object from a URL querystring */ const parseSearch = (search) => [...new URLSearchParams(search).entries()] .reduce((acc, [key, val]) => ({ ...acc, // eslint-disable-next-line no-nested-ternary [key]: Object.prototype.hasOwnProperty.call(acc, key) ? Array.isArray(acc[key]) ? [...acc[key], val] : [acc[key], val] : val }), {}); /** * Returns a plain object representation of a URLSearchParams object. * @param {Location} location - Either a document or window location, or React useLocation() * @return {Object} a key-value pair object from a URL querystring */ const parseLocationSearch = (location) => parseSearch(location.search); console.log(parseSearch('?foo=bar&x=y&ids=%5B1%2C2%2C3%5D&ids=%5B4%2C5%2C6%5D')); .as-console-wrapper { top: 0; max-height: 100% !important; }

下面是上面代码的一行代码(125字节):

f是parsearchch

f=s=>[...new URLSearchParams(s).entries()].reduce((a,[k,v])=>({...a,[k]:a[k]?Array.isArray(a[k])?[...a[k],v]:[a[k],v]:v}),{})

Edit

下面是一个序列化和更新的方法:

const parseSearch = (search) => [...new URLSearchParams(search).entries()] .reduce((acc, [key, val]) => ({ ...acc, // eslint-disable-next-line no-nested-ternary [key]: Object.prototype.hasOwnProperty.call(acc, key) ? Array.isArray(acc[key]) ? [...acc[key], val] : [acc[key], val] : val }), {}); const toQueryString = (params) => `?${Object.entries(params) .flatMap(([key, values]) => Array.isArray(values) ? values.map(value => [key, value]) : [[key, values]]) .map(pair => pair.map(val => encodeURIComponent(val)).join('=')) .join('&')}`; const updateQueryString = (search, update) => (parsed => toQueryString(update instanceof Function ? update(parsed) : { ...parsed, ...update })) (parseSearch(search)); const queryString = '?foo=bar&x=y&ids=%5B1%2C2%2C3%5D&ids=%5B4%2C5%2C6%5D'; const parsedQuery = parseSearch(queryString); console.log(parsedQuery); console.log(toQueryString(parsedQuery) === queryString); const updatedQuerySimple = updateQueryString(queryString, { foo: 'baz', x: 'z', }); console.log(updatedQuerySimple); console.log(parseSearch(updatedQuerySimple)); const updatedQuery = updateQueryString(updatedQuerySimple, parsed => ({ ...parsed, ids: [ ...parsed.ids, JSON.stringify([7,8,9]) ] })); console.log(updatedQuery); console.log(parseSearch(updatedQuery)); .as-console-wrapper { top: 0; max-height: 100% !important; }

在Mike Causer回答的基础上,我创建了这个函数,它考虑了具有相同键的多个参数(foo=bar&foo=baz)和逗号分隔的参数(foo=bar,baz,bin)。它还允许您搜索某个查询键。

function getQueryParams(queryKey) {
    var queryString = window.location.search;
    var query = {};
    var pairs = (queryString[0] === '?' ? queryString.substr(1) : queryString).split('&');
    for (var i = 0; i < pairs.length; i++) {
        var pair = pairs[i].split('=');
        var key = decodeURIComponent(pair[0]);
        var value = decodeURIComponent(pair[1] || '');
        // Se possui uma vírgula no valor, converter em um array
        value = (value.indexOf(',') === -1 ? value : value.split(','));

        // Se a key já existe, tratar ela como um array
        if (query[key]) {
            if (query[key].constructor === Array) {
                // Array.concat() faz merge se o valor inserido for um array
                query[key] = query[key].concat(value);
            } else {
                // Se não for um array, criar um array contendo o valor anterior e o novo valor
                query[key] = [query[key], value];
            }
        } else {
            query[key] = value;
        }
    }

    if (typeof queryKey === 'undefined') {
        return query;
    } else {
        return query[queryKey];
    }
}

示例输入: foo.html吗?博兹,foo = bar&foo = baz&foo =鹿角的第二叉,buz&bar = 1, 2, 3

示例输出

{
    foo: ["bar","baz","bez","boz","buz"],
    bar: ["1","2","3"]
}

我也遇到了同样的问题,尝试了这里的解决方案,但没有一个真正有效,因为我在URL参数中有数组,像这样:

?param[]=5&param[]=8&othr_param=abc&param[]=string

所以我最终写了我自己的JS函数,它使一个数组的参数在URI:

/**
 * Creates an object from URL encoded data
 */
var createObjFromURI = function() {
    var uri = decodeURI(location.search.substr(1));
    var chunks = uri.split('&');
    var params = Object();

    for (var i=0; i < chunks.length ; i++) {
        var chunk = chunks[i].split('=');
        if(chunk[0].search("\\[\\]") !== -1) {
            if( typeof params[chunk[0]] === 'undefined' ) {
                params[chunk[0]] = [chunk[1]];

            } else {
                params[chunk[0]].push(chunk[1]);
            }


        } else {
            params[chunk[0]] = chunk[1];
        }
    }

    return params;
}

使用phpjs

function parse_str(str, array) {
  //       discuss at: http://phpjs.org/functions/parse_str/
  //      original by: Cagri Ekin
  //      improved by: Michael White (http://getsprink.com)
  //      improved by: Jack
  //      improved by: Brett Zamir (http://brett-zamir.me)
  //      bugfixed by: Onno Marsman
  //      bugfixed by: Brett Zamir (http://brett-zamir.me)
  //      bugfixed by: stag019
  //      bugfixed by: Brett Zamir (http://brett-zamir.me)
  //      bugfixed by: MIO_KODUKI (http://mio-koduki.blogspot.com/)
  // reimplemented by: stag019
  //         input by: Dreamer
  //         input by: Zaide (http://zaidesthings.com/)
  //         input by: David Pesta (http://davidpesta.com/)
  //         input by: jeicquest
  //             note: When no argument is specified, will put variables in global scope.
  //             note: When a particular argument has been passed, and the returned value is different parse_str of PHP. For example, a=b=c&d====c
  //             test: skip
  //        example 1: var arr = {};
  //        example 1: parse_str('first=foo&second=bar', arr);
  //        example 1: $result = arr
  //        returns 1: { first: 'foo', second: 'bar' }
  //        example 2: var arr = {};
  //        example 2: parse_str('str_a=Jack+and+Jill+didn%27t+see+the+well.', arr);
  //        example 2: $result = arr
  //        returns 2: { str_a: "Jack and Jill didn't see the well." }
  //        example 3: var abc = {3:'a'};
  //        example 3: parse_str('abc[a][b]["c"]=def&abc[q]=t+5');
  //        returns 3: {"3":"a","a":{"b":{"c":"def"}},"q":"t 5"}

  var strArr = String(str)
    .replace(/^&/, '')
    .replace(/&$/, '')
    .split('&'),
    sal = strArr.length,
    i, j, ct, p, lastObj, obj, lastIter, undef, chr, tmp, key, value,
    postLeftBracketPos, keys, keysLen,
    fixStr = function(str) {
      return decodeURIComponent(str.replace(/\+/g, '%20'));
    };

  if (!array) {
    array = this.window;
  }

  for (i = 0; i < sal; i++) {
    tmp = strArr[i].split('=');
    key = fixStr(tmp[0]);
    value = (tmp.length < 2) ? '' : fixStr(tmp[1]);

    while (key.charAt(0) === ' ') {
      key = key.slice(1);
    }
    if (key.indexOf('\x00') > -1) {
      key = key.slice(0, key.indexOf('\x00'));
    }
    if (key && key.charAt(0) !== '[') {
      keys = [];
      postLeftBracketPos = 0;
      for (j = 0; j < key.length; j++) {
        if (key.charAt(j) === '[' && !postLeftBracketPos) {
          postLeftBracketPos = j + 1;
        } else if (key.charAt(j) === ']') {
          if (postLeftBracketPos) {
            if (!keys.length) {
              keys.push(key.slice(0, postLeftBracketPos - 1));
            }
            keys.push(key.substr(postLeftBracketPos, j - postLeftBracketPos));
            postLeftBracketPos = 0;
            if (key.charAt(j + 1) !== '[') {
              break;
            }
          }
        }
      }
      if (!keys.length) {
        keys = [key];
      }
      for (j = 0; j < keys[0].length; j++) {
        chr = keys[0].charAt(j);
        if (chr === ' ' || chr === '.' || chr === '[') {
          keys[0] = keys[0].substr(0, j) + '_' + keys[0].substr(j + 1);
        }
        if (chr === '[') {
          break;
        }
      }

      obj = array;
      for (j = 0, keysLen = keys.length; j < keysLen; j++) {
        key = keys[j].replace(/^['"]/, '')
          .replace(/['"]$/, '');
        lastIter = j !== keys.length - 1;
        lastObj = obj;
        if ((key !== '' && key !== ' ') || j === 0) {
          if (obj[key] === undef) {
            obj[key] = {};
          }
          obj = obj[key];
        } else { // To insert new dimension
          ct = -1;
          for (p in obj) {
            if (obj.hasOwnProperty(p)) {
              if (+p > ct && p.match(/^\d+$/g)) {
                ct = +p;
              }
            }
          }
          key = ct + 1;
        }
      }
      lastObj[key] = value;
    }
  }
}