// for swift 2.2
// version 1
buttton.addTarget(self, action: #selector(ViewController.tappedButton), forControlEvents: .TouchUpInside)
buttton.addTarget(self, action: #selector(ViewController.tappedButton2(_:)), forControlEvents: .TouchUpInside)

// version 2
buttton.addTarget(self, action: #selector(self.tappedButton), forControlEvents: .TouchUpInside)
buttton.addTarget(self, action: #selector(self.tappedButton2(_:)), forControlEvents: .TouchUpInside)

// version 3
buttton.addTarget(self, action: #selector(tappedButton), forControlEvents: .TouchUpInside)
buttton.addTarget(self, action: #selector(tappedButton2(_:)), forControlEvents: .TouchUpInside)

func tappedButton() {
  print("tapped")
}

func tappedButton2(sender: UIButton) {
  print("tapped 2")
}

// swift 3.x
button.addTarget(self, action: #selector(tappedButton(_:)), for: .touchUpInside)

func tappedButton(_ sender: UIButton) {
  // tapped
}

button.addTarget(self, action: #selector(tappedButton(_:_:)), for: .touchUpInside)

func tappedButton(_ sender: UIButton, _ event: UIEvent) {
  // tapped
}

下面是一个关于如何在Swift上使用Selector类的快速示例:

override func viewDidLoad() {
    super.viewDidLoad()

    var rightButton = UIBarButtonItem(title: "Title", style: UIBarButtonItemStyle.Plain, target: self, action: Selector("method"))
    self.navigationItem.rightBarButtonItem = rightButton
}

func method() {
    // Something cool here   
}

请注意，如果作为字符串传递的方法不起作用，它将在运行时失败，而不是在编译时失败，并使应用程序崩溃

注意在哪里设置触发动作的控件可能会很有用。

例如，我发现当设置一个UIBarButtonItem时，我必须在viewDidLoad内创建按钮，否则我会得到一个无法识别的选择器异常。

override func viewDidLoad() {
    super.viewDidLoad() 

    // add button
    let addButton = UIBarButtonItem(image: UIImage(named: "746-plus-circle.png"), style: UIBarButtonItemStyle.Plain, target: self, action: Selector("addAction:"))
    self.navigationItem.rightBarButtonItem = addButton
}

func addAction(send: AnyObject?) {     
    NSLog("addAction")
}

正如许多人所说，选择器是一种动态调用方法的objective - c方式，已经被带到了Swift中，在某些情况下我们仍然坚持使用它，比如UIKit，可能是因为他们在SwiftUI上工作来取代它，但一些api有更Swift的版本，比如Swift Timer，例如你可以使用

class func scheduledTimer(withTimeInterval interval: TimeInterval, 
                                            repeats: Bool, 
                                              block: @escaping (Timer) -> Void) -> Timer

相反，你可以这样称呼它

Timer.scheduledTimer(withTimeInterval: 1, 
                              repeats: true ) {
    ... your test code here
}

or

Timer.scheduledTimer(withTimeInterval: 1, 
                              repeats: true,
                              block: test)

方法test需要一个Timer参数，或者如果你想test需要一个命名参数

Timer.scheduledTimer(withTimeInterval: 1, 
                              repeats: true,
                              block: test(timer:))

你也应该使用Timer而不是NSTimer因为NSTimer是objective-c的旧名字

斯威夫特4.1 与样本的轻拍手势

let gestureRecognizer = UITapGestureRecognizer()
self.view.addGestureRecognizer(gestureRecognizer)
gestureRecognizer.addTarget(self, action: #selector(self.dismiss(completion:)))

// Use destination 'Class Name' directly, if you selector (function) is not in same class.
//gestureRecognizer.addTarget(self, action: #selector(DestinationClass.dismiss(completion:)))


@objc func dismiss(completion: (() -> Void)?) {
      self.dismiss(animated: true, completion: completion)
}

有关选择器表达式的更多细节，请参阅Apple的文档

objective - c选择器

Selector标识一个方法。

//Compile time
SEL selector = @selector(foo);

//Runtime
SEL selector = NSSelectorFromString(@"foo");

例如

[object sayHello:@"Hello World"];
//sayHello: is a selector

selector是一个来自Objective-C世界的词，你可以从Swift中使用它，有可能从Swift中调用Objective-C，它允许你在运行时执行一些代码

在Swift 2.2之前，语法是:

Selector("foo:")

因为函数名是作为字符串参数("foo")传入Selector的，所以在编译时不可能检查名称。结果你会得到一个运行时错误:

unrecognized selector sent to instance

在Swift 2.2+之后，语法是:

#selector(foo(_:))

Xcode的自动完成功能帮助你调用正确的方法