如何在Java中将字节大小转换为人类可读的格式?
比如1024应该变成“1 Kb”,1024*1024应该变成“1 Mb”。
我有点厌倦了为每个项目写这个实用方法。在Apache Commons中有这样的静态方法吗?
如何在Java中将字节大小转换为人类可读的格式?
比如1024应该变成“1 Kb”,1024*1024应该变成“1 Mb”。
我有点厌倦了为每个项目写这个实用方法。在Apache Commons中有这样的静态方法吗?
当前回答
FileUtils。如果你的项目依赖于org.apache.commons.io, byteCountToDisplaySize(长尺寸)可以工作。
此方法的JavaDoc
其他回答
public static String floatForm (double d)
{
return new DecimalFormat("#.##").format(d);
}
public static String bytesToHuman (long size)
{
long Kb = 1 * 1024;
long Mb = Kb * 1024;
long Gb = Mb * 1024;
long Tb = Gb * 1024;
long Pb = Tb * 1024;
long Eb = Pb * 1024;
if (size < Kb) return floatForm( size ) + " byte";
if (size >= Kb && size < Mb) return floatForm((double)size / Kb) + " Kb";
if (size >= Mb && size < Gb) return floatForm((double)size / Mb) + " Mb";
if (size >= Gb && size < Tb) return floatForm((double)size / Gb) + " Gb";
if (size >= Tb && size < Pb) return floatForm((double)size / Tb) + " Tb";
if (size >= Pb && size < Eb) return floatForm((double)size / Pb) + " Pb";
if (size >= Eb) return floatForm((double)size / Eb) + " Eb";
return "???";
}
字节单位允许你这样做:
long input1 = 1024;
long input2 = 1024 * 1024;
Assert.assertEquals("1 KiB", BinaryByteUnit.format(input1));
Assert.assertEquals("1 MiB", BinaryByteUnit.format(input2));
Assert.assertEquals("1.024 KB", DecimalByteUnit.format(input1, "#.0"));
Assert.assertEquals("1.049 MB", DecimalByteUnit.format(input2, "#.000"));
NumberFormat format = new DecimalFormat("#.#");
Assert.assertEquals("1 KiB", BinaryByteUnit.format(input1, format));
Assert.assertEquals("1 MiB", BinaryByteUnit.format(input2, format));
我写了另一个叫做storage-units的库,它允许你这样做:
String formattedUnit1 = StorageUnits.formatAsCommonUnit(input1, "#");
String formattedUnit2 = StorageUnits.formatAsCommonUnit(input2, "#");
String formattedUnit3 = StorageUnits.formatAsBinaryUnit(input1);
String formattedUnit4 = StorageUnits.formatAsBinaryUnit(input2);
String formattedUnit5 = StorageUnits.formatAsDecimalUnit(input1, "#.00", Locale.GERMAN);
String formattedUnit6 = StorageUnits.formatAsDecimalUnit(input2, "#.00", Locale.GERMAN);
String formattedUnit7 = StorageUnits.formatAsBinaryUnit(input1, format);
String formattedUnit8 = StorageUnits.formatAsBinaryUnit(input2, format);
Assert.assertEquals("1 kB", formattedUnit1);
Assert.assertEquals("1 MB", formattedUnit2);
Assert.assertEquals("1.00 KiB", formattedUnit3);
Assert.assertEquals("1.00 MiB", formattedUnit4);
Assert.assertEquals("1,02 kB", formattedUnit5);
Assert.assertEquals("1,05 MB", formattedUnit6);
Assert.assertEquals("1 KiB", formattedUnit7);
Assert.assertEquals("1 MiB", formattedUnit8);
如果你想强制某个单位,可以这样做:
String formattedUnit9 = StorageUnits.formatAsKibibyte(input2);
String formattedUnit10 = StorageUnits.formatAsCommonMegabyte(input2);
Assert.assertEquals("1024.00 KiB", formattedUnit9);
Assert.assertEquals("1.00 MB", formattedUnit10);
如果在Android上,你可以简单地调用Android .text. format . formatter的一个静态方法。
https://developer.android.com/reference/android/text/format/Formatter
下面是从aioobe转换到Kotlin的转换:
/**
* https://stackoverflow.com/a/3758880/1006741
*/
fun Long.humanReadableByteCountBinary(): String {
val b = when (this) {
Long.MIN_VALUE -> Long.MAX_VALUE
else -> abs(this)
}
return when {
b < 1024L -> "$this B"
b <= 0xfffccccccccccccL shr 40 -> "%.1f KiB".format(Locale.UK, this / 1024.0)
b <= 0xfffccccccccccccL shr 30 -> "%.1f MiB".format(Locale.UK, this / 1048576.0)
b <= 0xfffccccccccccccL shr 20 -> "%.1f GiB".format(Locale.UK, this / 1.073741824E9)
b <= 0xfffccccccccccccL shr 10 -> "%.1f TiB".format(Locale.UK, this / 1.099511627776E12)
b <= 0xfffccccccccccccL -> "%.1f PiB".format(Locale.UK, (this shr 10) / 1.099511627776E12)
else -> "%.1f EiB".format(Locale.UK, (this shr 20) / 1.099511627776E12)
}
}
创建接口:
public interface IUnits {
public String format(long size, String pattern);
public long getUnitSize();
}
创建StorageUnits类:
import java.text.DecimalFormat;
public class StorageUnits {
private static final long K = 1024;
private static final long M = K * K;
private static final long G = M * K;
private static final long T = G * K;
enum Unit implements IUnits {
TERA_BYTE {
@Override
public String format(long size, String pattern) {
return format(size, getUnitSize(), "TB", pattern);
}
@Override
public long getUnitSize() {
return T;
}
@Override
public String toString() {
return "Terabytes";
}
},
GIGA_BYTE {
@Override
public String format(long size, String pattern) {
return format(size, getUnitSize(), "GB", pattern);
}
@Override
public long getUnitSize() {
return G;
}
@Override
public String toString() {
return "Gigabytes";
}
},
MEGA_BYTE {
@Override
public String format(long size, String pattern) {
return format(size, getUnitSize(), "MB", pattern);
}
@Override
public long getUnitSize() {
return M;
}
@Override
public String toString() {
return "Megabytes";
}
},
KILO_BYTE {
@Override
public String format(long size, String pattern) {
return format(size, getUnitSize(), "kB", pattern);
}
@Override
public long getUnitSize() {
return K;
}
@Override
public String toString() {
return "Kilobytes";
}
};
String format(long size, long base, String unit, String pattern) {
return new DecimalFormat(pattern).format(
Long.valueOf(size).doubleValue() /
Long.valueOf(base).doubleValue()
) + unit;
}
}
public static String format(long size, String pattern) {
for(Unit unit : Unit.values()) {
if(size >= unit.getUnitSize()) {
return unit.format(size, pattern);
}
}
return ("???(" + size + ")???");
}
public static String format(long size) {
return format(size, "#,##0.#");
}
}
叫它:
class Main {
public static void main(String... args) {
System.out.println(StorageUnits.format(21885));
System.out.println(StorageUnits.format(2188121545L));
}
}
输出:
21.4kB
2GB