是否有一个简单的方法来转换字符串标题大小写?例如,约翰·史密斯变成了约翰·史密斯。我不是在寻找像John Resig的解决方案那样复杂的东西,只是(希望)一些一两行代码。
当前回答
如果你需要一个语法正确的答案:
这个答案考虑了介词,如“of”,“from”,… 输出将生成您希望在论文中看到的编辑风格的标题。
toTitleCase函数
考虑此处列出的语法规则的函数。 该函数还合并空格和删除特殊字符(根据需要修改regex)
const toTitleCase = (str) => {
const articles = ['a', 'an', 'the'];
const conjunctions = ['for', 'and', 'nor', 'but', 'or', 'yet', 'so'];
const prepositions = [
'with', 'at', 'from', 'into','upon', 'of', 'to', 'in', 'for',
'on', 'by', 'like', 'over', 'plus', 'but', 'up', 'down', 'off', 'near'
];
// The list of spacial characters can be tweaked here
const replaceCharsWithSpace = (str) => str.replace(/[^0-9a-z&/\\]/gi, ' ').replace(/(\s\s+)/gi, ' ');
const capitalizeFirstLetter = (str) => str.charAt(0).toUpperCase() + str.substr(1);
const normalizeStr = (str) => str.toLowerCase().trim();
const shouldCapitalize = (word, fullWordList, posWithinStr) => {
if ((posWithinStr == 0) || (posWithinStr == fullWordList.length - 1)) {
return true;
}
return !(articles.includes(word) || conjunctions.includes(word) || prepositions.includes(word));
}
str = replaceCharsWithSpace(str);
str = normalizeStr(str);
let words = str.split(' ');
if (words.length <= 2) { // Strings less than 3 words long should always have first words capitalized
words = words.map(w => capitalizeFirstLetter(w));
}
else {
for (let i = 0; i < words.length; i++) {
words[i] = (shouldCapitalize(words[i], words, i) ? capitalizeFirstLetter(words[i], words, i) : words[i]);
}
}
return words.join(' ');
}
确保正确性的单元测试
import { expect } from 'chai';
import { toTitleCase } from '../../src/lib/stringHelper';
describe('toTitleCase', () => {
it('Capitalizes first letter of each word irrespective of articles, conjunctions or prepositions if string is no greater than two words long', function(){
expect(toTitleCase('the dog')).to.equal('The Dog'); // Capitalize articles when only two words long
expect(toTitleCase('for all')).to.equal('For All'); // Capitalize conjunctions when only two words long
expect(toTitleCase('with cats')).to.equal('With Cats'); // Capitalize prepositions when only two words long
});
it('Always capitalize first and last words in a string irrespective of articles, conjunctions or prepositions', function(){
expect(toTitleCase('the beautiful dog')).to.equal('The Beautiful Dog');
expect(toTitleCase('for all the deadly ninjas, be it so')).to.equal('For All the Deadly Ninjas Be It So');
expect(toTitleCase('with cats and dogs we are near')).to.equal('With Cats and Dogs We Are Near');
});
it('Replace special characters with space', function(){
expect(toTitleCase('[wolves & lions]: be careful')).to.equal('Wolves & Lions Be Careful');
expect(toTitleCase('wolves & lions, be careful')).to.equal('Wolves & Lions Be Careful');
});
it('Trim whitespace at beginning and end', function(){
expect(toTitleCase(' mario & Luigi superstar saga ')).to.equal('Mario & Luigi Superstar Saga');
});
it('articles, conjunctions and prepositions should not be capitalized in strings of 3+ words', function(){
expect(toTitleCase('The wolf and the lion: a tale of two like animals')).to.equal('The Wolf and the Lion a Tale of Two like Animals');
expect(toTitleCase('the three Musketeers And plus ')).to.equal('The Three Musketeers and Plus');
});
});
请注意,我从提供的字符串中删除了相当多的特殊字符。您将需要调整正则表达式以满足项目的需求。
其他回答
只是另一个版本的混合。这也将检查字符串是否。长度为0:
String.prototype.toTitleCase = function() {
var str = this;
if(!str.length) {
return "";
}
str = str.split(" ");
for(var i = 0; i < str.length; i++) {
str[i] = str[i].charAt(0).toUpperCase() + (str[i].substr(1).length ? str[i].substr(1) : '');
}
return (str.length ? str.join(" ") : str);
};
如果一个CSS解决方案满足你的需求,你可以应用文本转换CSS样式到你的控件:
text-transform: capitalize;
请注意,这将会改变: hello world到hello world HELLO WORLD到HELLO WORLD(不变) emily-jane o'brien致emily-jane o'brien(不正确) 玛丽亚·冯·特拉普写给玛丽亚·冯·特拉普(不正确)
如果可以的话,我强烈建议使用开源的NPM包,这个包在typescript中工作得很好:
NPM: https://www.npmjs.com/package/title-case
Github: https://github.com/blakeembrey/change-case/tree/master/packages/title-case readme
运行npm install title-case将包添加到项目中。
使用标题大小写npm包的示例代码:
import { titleCase } from "title-case";
titleCase("string"); //=> "String"
titleCase("follow step-by-step instructions"); //=> "Follow Step-by-Step Instructions"
这里有一个紧凑的解决方案:
function Title_Case(phrase)
{
var revised = phrase.charAt(0).toUpperCase();
for ( var i = 1; i < phrase.length; i++ ) {
if (phrase.charAt(i - 1) == " ") {
revised += phrase.charAt(i).toUpperCase(); }
else {
revised += phrase.charAt(i).toLowerCase(); }
}
return revised;
}
瓦尔·弦=“测试” 笨蛋。 var输出=弦。charAt(0) 控制台日志(输出)。 警报(输出)
var string = "tEsT"
string = string.toLowerCase()
string.charAt(0).toUpperCase() + string.slice(1)
string.charAt(0) returns the character at the 0th index of the string. toUpperCase() is a method that returns the uppercase equivalent of a string. It is applied to the first character of the string, returned by charAt(0). string.slice(1) returns a new string that starts from the 1st index (the character at index 0 is excluded) till the end of the string. Finally, the expression concatenates the result of toUpperCase() and string.slice(1) to create a new string with the first character capitalized.
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