是否有一个简单的方法来转换字符串标题大小写?例如,约翰·史密斯变成了约翰·史密斯。我不是在寻找像John Resig的解决方案那样复杂的东西,只是(希望)一些一两行代码。


当前回答

如果你需要一个语法正确的答案:

这个答案考虑了介词,如“of”,“from”,… 输出将生成您希望在论文中看到的编辑风格的标题。

toTitleCase函数

考虑此处列出的语法规则的函数。 该函数还合并空格和删除特殊字符(根据需要修改regex)

const toTitleCase = (str) => {
  const articles = ['a', 'an', 'the'];
  const conjunctions = ['for', 'and', 'nor', 'but', 'or', 'yet', 'so'];
  const prepositions = [
    'with', 'at', 'from', 'into','upon', 'of', 'to', 'in', 'for',
    'on', 'by', 'like', 'over', 'plus', 'but', 'up', 'down', 'off', 'near'
  ];

  // The list of spacial characters can be tweaked here
  const replaceCharsWithSpace = (str) => str.replace(/[^0-9a-z&/\\]/gi, ' ').replace(/(\s\s+)/gi, ' ');
  const capitalizeFirstLetter = (str) => str.charAt(0).toUpperCase() + str.substr(1);
  const normalizeStr = (str) => str.toLowerCase().trim();
  const shouldCapitalize = (word, fullWordList, posWithinStr) => {
    if ((posWithinStr == 0) || (posWithinStr == fullWordList.length - 1)) {
      return true;
    }

    return !(articles.includes(word) || conjunctions.includes(word) || prepositions.includes(word));
  }

  str = replaceCharsWithSpace(str);
  str = normalizeStr(str);

  let words = str.split(' ');
  if (words.length <= 2) { // Strings less than 3 words long should always have first words capitalized
    words = words.map(w => capitalizeFirstLetter(w));
  }
  else {
    for (let i = 0; i < words.length; i++) {
      words[i] = (shouldCapitalize(words[i], words, i) ? capitalizeFirstLetter(words[i], words, i) : words[i]);
    }
  }

  return words.join(' ');
}

确保正确性的单元测试

import { expect } from 'chai';
import { toTitleCase } from '../../src/lib/stringHelper';

describe('toTitleCase', () => {
  it('Capitalizes first letter of each word irrespective of articles, conjunctions or prepositions if string is no greater than two words long', function(){
    expect(toTitleCase('the dog')).to.equal('The Dog'); // Capitalize articles when only two words long
    expect(toTitleCase('for all')).to.equal('For All'); // Capitalize conjunctions when only two words long
    expect(toTitleCase('with cats')).to.equal('With Cats'); // Capitalize prepositions when only two words long
  });

  it('Always capitalize first and last words in a string irrespective of articles, conjunctions or prepositions', function(){
    expect(toTitleCase('the beautiful dog')).to.equal('The Beautiful Dog');
    expect(toTitleCase('for all the deadly ninjas, be it so')).to.equal('For All the Deadly Ninjas Be It So');
    expect(toTitleCase('with cats and dogs we are near')).to.equal('With Cats and Dogs We Are Near');
  });

  it('Replace special characters with space', function(){
    expect(toTitleCase('[wolves & lions]: be careful')).to.equal('Wolves & Lions Be Careful');
    expect(toTitleCase('wolves & lions, be careful')).to.equal('Wolves & Lions Be Careful');
  });

  it('Trim whitespace at beginning and end', function(){
    expect(toTitleCase(' mario & Luigi superstar saga ')).to.equal('Mario & Luigi Superstar Saga');
  });

  it('articles, conjunctions and prepositions should not be capitalized in strings of 3+ words', function(){
    expect(toTitleCase('The wolf and the lion: a tale of two like animals')).to.equal('The Wolf and the Lion a Tale of Two like Animals');
    expect(toTitleCase('the  three Musketeers  And plus ')).to.equal('The Three Musketeers and Plus');
  });
});

请注意,我从提供的字符串中删除了相当多的特殊字符。您将需要调整正则表达式以满足项目的需求。

其他回答

下面是我的函数,它负责处理重音字符(对法语来说很重要!),并且可以打开/关闭对lower异常的处理。希望这能有所帮助。

String.prototype.titlecase = function(lang, withLowers = false) {
    var i, string, lowers, uppers;

    string = this.replace(/([^\s:\-'])([^\s:\-']*)/g, function(txt) {
        return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase();
    }).replace(/Mc(.)/g, function(match, next) {
        return 'Mc' + next.toUpperCase();
    });

    if (withLowers) {
        if (lang == 'EN') {
            lowers = ['A', 'An', 'The', 'At', 'By', 'For', 'In', 'Of', 'On', 'To', 'Up', 'And', 'As', 'But', 'Or', 'Nor', 'Not'];
        }
        else {
            lowers = ['Un', 'Une', 'Le', 'La', 'Les', 'Du', 'De', 'Des', 'À', 'Au', 'Aux', 'Par', 'Pour', 'Dans', 'Sur', 'Et', 'Comme', 'Mais', 'Ou', 'Où', 'Ne', 'Ni', 'Pas'];
        }
        for (i = 0; i < lowers.length; i++) {
            string = string.replace(new RegExp('\\s' + lowers[i] + '\\s', 'g'), function(txt) {
                return txt.toLowerCase();
            });
        }
    }

    uppers = ['Id', 'R&d'];
    for (i = 0; i < uppers.length; i++) {
        string = string.replace(new RegExp('\\b' + uppers[i] + '\\b', 'g'), uppers[i].toUpperCase());
    }

    return string;
}

如果你想使用NPM库,请查看title-case:

安装:

npm install title-case --save

用法:

import { titleCase } from "title-case";

titleCase("string"); //=> "String"
titleCase("follow step-by-step instructions"); //=> "Follow Step-by-Step Instructions"

我对这个问题的简单版本是:

    function titlecase(str){
    var arr=[];  
    var str1=str.split(' ');
    for (var i = 0; i < str1.length; i++) {
    var upper= str1[i].charAt(0).toUpperCase()+ str1[i].substr(1);
    arr.push(upper);
     };
      return arr.join(' ');
    }
    titlecase('my name is suryatapa roy');

试试这个,最短的方法:

str.replace(/(^[a-z])|(\s+[a-z])/g, txt => txt.toUpperCase());

可以将第一个字符大写,并与其余字符串连接。

Let STR = 'john smith'; Let res = str.split(" "); res.forEach((w, index) => { res[index] = w. charat (0). touppercase ().concat(w。片(1,w.length)) }); Res = Res .join(" "); console.log (res);