是否有一个简单的方法来转换字符串标题大小写?例如,约翰·史密斯变成了约翰·史密斯。我不是在寻找像John Resig的解决方案那样复杂的东西,只是(希望)一些一两行代码。
当前回答
将单个单词转换为标题大小写的简单方法
使用“切片”方法和字符串拼接
str.slice(0, 1).toUpperCase() + str.slice(1, str.length)
*如果你想要小写单词的其余部分,在结尾添加.toLowerCase()
使用ES6扩展操作符、映射和Join
[...str].map((w, i) => i === 0 ? w[0].toUpperCase() : w).join('')
其他回答
如果你需要一个语法正确的答案:
这个答案考虑了介词,如“of”,“from”,… 输出将生成您希望在论文中看到的编辑风格的标题。
toTitleCase函数
考虑此处列出的语法规则的函数。 该函数还合并空格和删除特殊字符(根据需要修改regex)
const toTitleCase = (str) => {
const articles = ['a', 'an', 'the'];
const conjunctions = ['for', 'and', 'nor', 'but', 'or', 'yet', 'so'];
const prepositions = [
'with', 'at', 'from', 'into','upon', 'of', 'to', 'in', 'for',
'on', 'by', 'like', 'over', 'plus', 'but', 'up', 'down', 'off', 'near'
];
// The list of spacial characters can be tweaked here
const replaceCharsWithSpace = (str) => str.replace(/[^0-9a-z&/\\]/gi, ' ').replace(/(\s\s+)/gi, ' ');
const capitalizeFirstLetter = (str) => str.charAt(0).toUpperCase() + str.substr(1);
const normalizeStr = (str) => str.toLowerCase().trim();
const shouldCapitalize = (word, fullWordList, posWithinStr) => {
if ((posWithinStr == 0) || (posWithinStr == fullWordList.length - 1)) {
return true;
}
return !(articles.includes(word) || conjunctions.includes(word) || prepositions.includes(word));
}
str = replaceCharsWithSpace(str);
str = normalizeStr(str);
let words = str.split(' ');
if (words.length <= 2) { // Strings less than 3 words long should always have first words capitalized
words = words.map(w => capitalizeFirstLetter(w));
}
else {
for (let i = 0; i < words.length; i++) {
words[i] = (shouldCapitalize(words[i], words, i) ? capitalizeFirstLetter(words[i], words, i) : words[i]);
}
}
return words.join(' ');
}
确保正确性的单元测试
import { expect } from 'chai';
import { toTitleCase } from '../../src/lib/stringHelper';
describe('toTitleCase', () => {
it('Capitalizes first letter of each word irrespective of articles, conjunctions or prepositions if string is no greater than two words long', function(){
expect(toTitleCase('the dog')).to.equal('The Dog'); // Capitalize articles when only two words long
expect(toTitleCase('for all')).to.equal('For All'); // Capitalize conjunctions when only two words long
expect(toTitleCase('with cats')).to.equal('With Cats'); // Capitalize prepositions when only two words long
});
it('Always capitalize first and last words in a string irrespective of articles, conjunctions or prepositions', function(){
expect(toTitleCase('the beautiful dog')).to.equal('The Beautiful Dog');
expect(toTitleCase('for all the deadly ninjas, be it so')).to.equal('For All the Deadly Ninjas Be It So');
expect(toTitleCase('with cats and dogs we are near')).to.equal('With Cats and Dogs We Are Near');
});
it('Replace special characters with space', function(){
expect(toTitleCase('[wolves & lions]: be careful')).to.equal('Wolves & Lions Be Careful');
expect(toTitleCase('wolves & lions, be careful')).to.equal('Wolves & Lions Be Careful');
});
it('Trim whitespace at beginning and end', function(){
expect(toTitleCase(' mario & Luigi superstar saga ')).to.equal('Mario & Luigi Superstar Saga');
});
it('articles, conjunctions and prepositions should not be capitalized in strings of 3+ words', function(){
expect(toTitleCase('The wolf and the lion: a tale of two like animals')).to.equal('The Wolf and the Lion a Tale of Two like Animals');
expect(toTitleCase('the three Musketeers And plus ')).to.equal('The Three Musketeers and Plus');
});
});
请注意,我从提供的字符串中删除了相当多的特殊字符。您将需要调整正则表达式以满足项目的需求。
这是个测试——>这是个测试
函数大写(str) { Const word = []; For (let char of str.split(' ')) { word.push(char[0].toUpperCase() + char.slice(1)) } 返回的词。加入(' '); } Console.log(大写("this is a test"));
ES 6
str.split(' ')
.map(s => s.slice(0, 1).toUpperCase() + s.slice(1).toLowerCase())
.join(' ')
else
str.split(' ').map(function (s) {
return s.slice(0, 1).toUpperCase() + s.slice(1).toLowerCase();
}).join(' ')
如果你想使用NPM库,请查看title-case:
安装:
npm install title-case --save
用法:
import { titleCase } from "title-case";
titleCase("string"); //=> "String"
titleCase("follow step-by-step instructions"); //=> "Follow Step-by-Step Instructions"
我的一句话解决方案:
String.prototype.capitalizeWords = function() {
return this.split(" ").map(function(ele){ return ele[0].toUpperCase() + ele.slice(1).toLowerCase();}).join(" ");
};
然后,可以在任何字符串上调用方法capitalizeWords()。例如:
var myS = "this actually works!";
myS.capitalizeWords();
>>> This Actually Works
我的另一个解决方案:
function capitalizeFirstLetter(word) {
return word[0].toUpperCase() + word.slice(1).toLowerCase();
}
String.prototype.capitalizeAllWords = function() {
var arr = this.split(" ");
for(var i = 0; i < arr.length; i++) {
arr[i] = capitalizeFirstLetter(arr[i]);
}
return arr.join(" ");
};
然后,可以在任何字符串上调用方法capitalizeWords()。例如:
var myStr = "this one works too!";
myStr.capitalizeWords();
>>> This One Works Too
基于Greg Dean回答的替代解决方案:
function capitalizeFirstLetter(word) {
return word[0].toUpperCase() + word.slice(1).toLowerCase();
}
String.prototype.capitalizeWords = function() {
return this.replace(/\w\S*/g, capitalizeFirstLetter);
};
然后,可以在任何字符串上调用方法capitalizeWords()。例如:
var myString = "yes and no";
myString.capitalizeWords()
>>> Yes And No