如何使用JavaScript将日期添加到当前日期?JavaScript是否有像.NET的AddDay()那样的内置函数?
当前回答
我实现的最简单的方法是使用Date()本身。`
const days = 15;
// Date.now() gives the epoch date value (in milliseconds) of current date
nextDate = new Date( Date.now() + days * 24 * 60 * 60 * 1000)
`
其他回答
我总结了小时和天。。。
Date.prototype.addDays = function(days){
days = parseInt(days, 10)
this.setDate(this.getUTCDate() + days);
return this;
}
Date.prototype.addHours = function(hrs){
var hr = this.getUTCHours() + parseInt(hrs , 10);
while(hr > 24){
hr = hr - 24;
this.addDays(1);
}
this.setHours(hr);
return this;
}
Try
var someDate = new Date();
var duration = 2; //In Days
someDate.setTime(someDate.getTime() + (duration * 24 * 60 * 60 * 1000));
使用setDate()添加日期并不能解决您的问题,请尝试在2月份添加一些天,如果您尝试在其中添加新的天,则不会产生您预期的结果。
我试图解决类似的问题,我更喜欢getTime方法,但有一些奇怪的基于时区的副作用。
ofc将“今天”替换为您需要的任何日期,并将时间也输入。关键是获取UTC时间,然后用毫秒来做加法,以避免这些副作用。
var now = new Date(Date.now());
var today = new Date(Date.UTC(now.getFullYear(), now.getMonth(), now.getDate()));
const dayInMs = 86400000; //24 hours
const tomorrow = new Date(today.getTime() + dayInMs);
同样的答案是:如何将天数添加到今天的日期?
function DaysOfMonth(nYear, nMonth) {
switch (nMonth) {
case 0: // January
return 31; break;
case 1: // February
if ((nYear % 4) == 0) {
return 29;
}
else {
return 28;
};
break;
case 2: // March
return 31; break;
case 3: // April
return 30; break;
case 4: // May
return 31; break;
case 5: // June
return 30; break;
case 6: // July
return 31; break;
case 7: // August
return 31; break;
case 8: // September
return 30; break;
case 9: // October
return 31; break;
case 10: // November
return 30; break;
case 11: // December
return 31; break;
}
};
function SkipDate(dDate, skipDays) {
var nYear = dDate.getFullYear();
var nMonth = dDate.getMonth();
var nDate = dDate.getDate();
var remainDays = skipDays;
var dRunDate = dDate;
while (remainDays > 0) {
remainDays_month = DaysOfMonth(nYear, nMonth) - nDate;
if (remainDays > remainDays_month) {
remainDays = remainDays - remainDays_month - 1;
nDate = 1;
if (nMonth < 11) { nMonth = nMonth + 1; }
else {
nMonth = 0;
nYear = nYear + 1;
};
}
else {
nDate = nDate + remainDays;
remainDays = 0;
};
dRunDate = Date(nYear, nMonth, nDate);
}
return new Date(nYear, nMonth, nDate);
};
就这么简单:
new Date((new Date()).getTime() + (60*60*24*1000));