如何使用JavaScript将日期添加到当前日期?JavaScript是否有像.NET的AddDay()那样的内置函数?
当前回答
我想我也会给出答案:就我个人而言,我喜欢尝试避免无谓的变量声明、方法调用和构造函数调用,因为它们的性能都很昂贵。(当然是合理的)我本打算在@AnthonyWJones给出的答案下留下评论,但考虑得更好。
// Prototype usage...
Date.prototype.addDays = Date.prototype.addDays || function( days ) {
return this.setTime( 864E5 * days + this.valueOf() ) && this;
};
// Namespace usage...
namespace.addDaysToDate = function( date, days ) {
return date.setTime( 864E5 * days + date.valueOf() ) && date;
};
// Basic Function declaration...
function addDaysToDate( date, days ) {
return date.setTime( 864E5 * days + date.valueOf() ) && date;
};
以上内容将尊重DST。这意味着,如果您添加一个跨越夏令时的天数,则显示的时间(小时)将更改以反映这一点。例子:2014年11月2日02:00是夏令时的结束。
var dt = new Date( 2014, 10, 1, 10, 30, 0 );
console.log( dt ); // Sat Nov 01 2014 10:30:00
console.log( dt.addDays( 10 ) ); // Tue Nov 11 2014 09:30:00
如果你想保留夏令时的时间(所以10:30仍然是10:30)。。。
// Prototype usage...
Date.prototype.addDays = Date.prototype.addDays || function( days ) {
return this.setDate( this.getDate() + days ) && this;
};
// Namespace usage...
namespace.addDaysToDate = function( date, days ) {
return date.setDate( date.getDate() + days ) && date;
};
// Basic Function declaration...
function addDaysToDate( date, days ) {
return date.setDate( date.getDate() + days ) && date;
};
所以,现在你。。。
var dt = new Date( 2014, 10, 1, 10, 30, 0 );
console.log( dt ); // Sat Nov 01 2014 10:30:00
console.log( dt.addDays( 10 ) ); // Tue Nov 11 2014 10:30:00
其他回答
function addDays(n){
var t = new Date();
t.setDate(t.getDate() + n);
var month = "0"+(t.getMonth()+1);
var date = "0"+t.getDate();
month = month.slice(-2);
date = date.slice(-2);
var date = date +"/"+month +"/"+t.getFullYear();
alert(date);
}
addDays(5);
一些扩展Date的实现https://gist.github.com/netstart/c92e09730f3675ba8fb33be48520a86d
/**
* just import, like
*
* import './../shared/utils/date.prototype.extendions.ts';
*/
declare global {
interface Date {
addDays(days: number, useThis?: boolean): Date;
addSeconds(seconds: number): Date;
addMinutes(minutes: number): Date;
addHours(hours: number): Date;
addMonths(months: number): Date;
isToday(): boolean;
clone(): Date;
isAnotherMonth(date: Date): boolean;
isWeekend(): boolean;
isSameDate(date: Date): boolean;
getStringDate(): string;
}
}
Date.prototype.addDays = function(days: number): Date {
if (!days) {
return this;
}
this.setDate(this.getDate() + days);
return this;
};
Date.prototype.addSeconds = function(seconds: number) {
let value = this.valueOf();
value += 1000 * seconds;
return new Date(value);
};
Date.prototype.addMinutes = function(minutes: number) {
let value = this.valueOf();
value += 60000 * minutes;
return new Date(value);
};
Date.prototype.addHours = function(hours: number) {
let value = this.valueOf();
value += 3600000 * hours;
return new Date(value);
};
Date.prototype.addMonths = function(months: number) {
const value = new Date(this.valueOf());
let mo = this.getMonth();
let yr = this.getYear();
mo = (mo + months) % 12;
if (0 > mo) {
yr += (this.getMonth() + months - mo - 12) / 12;
mo += 12;
} else {
yr += ((this.getMonth() + months - mo) / 12);
}
value.setMonth(mo);
value.setFullYear(yr);
return value;
};
Date.prototype.isToday = function(): boolean {
const today = new Date();
return this.isSameDate(today);
};
Date.prototype.clone = function(): Date {
return new Date(+this);
};
Date.prototype.isAnotherMonth = function(date: Date): boolean {
return date && this.getMonth() !== date.getMonth();
};
Date.prototype.isWeekend = function(): boolean {
return this.getDay() === 0 || this.getDay() === 6;
};
Date.prototype.isSameDate = function(date: Date): boolean {
return date && this.getFullYear() === date.getFullYear() && this.getMonth() === date.getMonth() && this.getDate() === date.getDate();
};
Date.prototype.getStringDate = function(): string {
// Month names in Brazilian Portuguese
const monthNames = ['Janeiro', 'Fevereiro', 'Março', 'Abril', 'Maio', 'Junho', 'Julho', 'Agosto', 'Setembro', 'Outubro', 'Novembro', 'Dezembro'];
// Month names in English
// let monthNames = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'];
const today = new Date();
if (this.getMonth() === today.getMonth() && this.getDay() === today.getDay()) {
return 'Hoje';
// return "Today";
} else if (this.getMonth() === today.getMonth() && this.getDay() === today.getDay() + 1) {
return 'Amanhã';
// return "Tomorrow";
} else if (this.getMonth() === today.getMonth() && this.getDay() === today.getDay() - 1) {
return 'Ontem';
// return "Yesterday";
} else {
return this.getDay() + ' de ' + this.monthNames[this.getMonth()] + ' de ' + this.getFullYear();
// return this.monthNames[this.getMonth()] + ' ' + this.getDay() + ', ' + this.getFullYear();
}
};
export {};
对于使用Angular的用户:
只要做到:
$scope.booking.totTijd.setMinutes($scope.booking.totTijd.getMinutes()+15);
$scope.booking.totTijd.setDate($scope.booking.totTijd.getDate() + 1);
我真不敢相信,5年后,这条线索中没有捷径可走!SO:要获得一天中相同的时间,而不考虑夏季的干扰:
Date.prototype.addDays = function(days)
{
var dat = new Date( this.valueOf() )
var hour1 = dat.getHours()
dat.setTime( dat.getTime() + days * 86400000) // 24*60*60*1000 = 24 hours
var hour2 = dat.getHours()
if (hour1 != hour2) // summertime occured +/- a WHOLE number of hours thank god!
dat.setTime( dat.getTime() + (hour1 - hour2) * 3600000) // 60*60*1000 = 1 hour
return dat
or
this.setTime( dat.getTime() ) // to modify the object directly
}
那里完成!
我对所提出的解决方案的夏令时有问题。
通过改用getUTCDate/setUTCDate,我解决了问题。
// Curried, so that I can create helper functions like `add1Day`
const addDays = num => date => {
// Make a working copy so we don't mutate the supplied date.
const d = new Date(date);
d.setUTCDate(d.getUTCDate() + num);
return d;
}