如何使用JavaScript将日期添加到当前日期?JavaScript是否有像.NET的AddDay()那样的内置函数?
当前回答
我总结了小时和天。。。
Date.prototype.addDays = function(days){
days = parseInt(days, 10)
this.setDate(this.getUTCDate() + days);
return this;
}
Date.prototype.addHours = function(hrs){
var hr = this.getUTCHours() + parseInt(hrs , 10);
while(hr > 24){
hr = hr - 24;
this.addDays(1);
}
this.setHours(hr);
return this;
}
其他回答
我实现的最简单的方法是使用Date()本身。`
const days = 15;
// Date.now() gives the epoch date value (in milliseconds) of current date
nextDate = new Date( Date.now() + days * 24 * 60 * 60 * 1000)
`
setDate()的mozilla文档并不表示它将处理月末场景。看见https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Date
设置日期()
根据当地时间设置指定日期的月份日期(1-31)。
这就是我在需要添加天数时使用setTime()的原因。
同样的答案是:如何将天数添加到今天的日期?
function DaysOfMonth(nYear, nMonth) {
switch (nMonth) {
case 0: // January
return 31; break;
case 1: // February
if ((nYear % 4) == 0) {
return 29;
}
else {
return 28;
};
break;
case 2: // March
return 31; break;
case 3: // April
return 30; break;
case 4: // May
return 31; break;
case 5: // June
return 30; break;
case 6: // July
return 31; break;
case 7: // August
return 31; break;
case 8: // September
return 30; break;
case 9: // October
return 31; break;
case 10: // November
return 30; break;
case 11: // December
return 31; break;
}
};
function SkipDate(dDate, skipDays) {
var nYear = dDate.getFullYear();
var nMonth = dDate.getMonth();
var nDate = dDate.getDate();
var remainDays = skipDays;
var dRunDate = dDate;
while (remainDays > 0) {
remainDays_month = DaysOfMonth(nYear, nMonth) - nDate;
if (remainDays > remainDays_month) {
remainDays = remainDays - remainDays_month - 1;
nDate = 1;
if (nMonth < 11) { nMonth = nMonth + 1; }
else {
nMonth = 0;
nYear = nYear + 1;
};
}
else {
nDate = nDate + remainDays;
remainDays = 0;
};
dRunDate = Date(nYear, nMonth, nDate);
}
return new Date(nYear, nMonth, nDate);
};
使用js-joda。它是一个很棒的javascript不可变日期和时间库。以下是其备忘单的摘录。
为今天增加17天
LocalDate.now().plusDays(17);
您还可以一次从多个操作构建所需的日期。
LocalDate.now()
.plusMonths(1)
.withDayOfMonth(1)
.minusDays(17);
Or:
var d = LocalDate.parse('2019-02-23');
d.minus(Period.ofMonths(3).plusDays(3)); // '2018-11-20'
我对所提出的解决方案的夏令时有问题。
通过改用getUTCDate/setUTCDate,我解决了问题。
// Curried, so that I can create helper functions like `add1Day`
const addDays = num => date => {
// Make a working copy so we don't mutate the supplied date.
const d = new Date(date);
d.setUTCDate(d.getUTCDate() + num);
return d;
}