我有一个查询，在MySQL工作得很好，但当我在Oracle上运行它时，我得到以下错误:
SQL错误:ORA-00933: SQL命令未正确结束 00933. 00000 - "SQL命令未正确结束"
查询为:
UPDATE table1
INNER JOIN table2 ON table1.value = table2.DESC
SET table1.value = table2.CODE
WHERE table1.UPDATETYPE='blah';
当前回答
它工作得很好
merge into table1 t1
using (select * from table2) t2
on (t1.empid = t2.empid)
when matched then update set t1.salary = t2.salary
其他回答
用WHERE子句合并:
MERGE into table1
USING table2
ON (table1.id = table2.id)
WHEN MATCHED THEN UPDATE SET table1.startdate = table2.start_date
WHERE table1.startdate > table2.start_date;
您需要WHERE子句，因为ON子句中引用的列不能更新。
UPDATE table1 t1
SET t1.value =
(select t2.CODE from table2 t2
where t1.value = t2.DESC)
WHERE t1.UPDATETYPE='blah';
它工作得很好
merge into table1 t1
using (select * from table2) t2
on (t1.empid = t2.empid)
when matched then update set t1.salary = t2.salary
如这里所示，Tony Andrews提出的第一个解决方案的通用语法是:
update some_table s
set (s.col1, s.col2) = (select x.col1, x.col2
from other_table x
where x.key_value = s.key_value
)
where exists (select 1
from other_table x
where x.key_value = s.key_value
)
我认为这很有趣，特别是当你想要更新多个字段时。
update table1 a
set a.col1='Y'
where exists(select 1
from table2 b
where a.col1=b.col1
and a.col2=b.col2
)
