我有一个查询,在MySQL工作得很好,但当我在Oracle上运行它时,我得到以下错误:
SQL错误:ORA-00933: SQL命令未正确结束 00933. 00000 - "SQL命令未正确结束"
查询为:
UPDATE table1
INNER JOIN table2 ON table1.value = table2.DESC
SET table1.value = table2.CODE
WHERE table1.UPDATETYPE='blah';
我有一个查询,在MySQL工作得很好,但当我在Oracle上运行它时,我得到以下错误:
SQL错误:ORA-00933: SQL命令未正确结束 00933. 00000 - "SQL命令未正确结束"
查询为:
UPDATE table1
INNER JOIN table2 ON table1.value = table2.DESC
SET table1.value = table2.CODE
WHERE table1.UPDATETYPE='blah';
当前回答
UPDATE ( SELECT t1.value, t2.CODE
FROM table1 t1
INNER JOIN table2 t2 ON t1.Value = t2.DESC
WHERE t1.UPDATETYPE='blah')
SET t1.Value= t2.CODE
其他回答
只是作为一个完整的问题,因为我们谈论的是Oracle,这也可以做到:
declare
begin
for sel in (
select table2.code, table2.desc
from table1
join table2 on table1.value = table2.desc
where table1.updatetype = 'blah'
) loop
update table1
set table1.value = sel.code
where table1.updatetype = 'blah' and table1.value = sel.desc;
end loop;
end;
/
用这个:
MERGE
INTO table1 trg
USING (
SELECT t1.rowid AS rid, t2.code
FROM table1 t1
JOIN table2 t2
ON table1.value = table2.DESC
WHERE table1.UPDATETYPE='blah'
) src
ON (trg.rowid = src.rid)
WHEN MATCHED THEN UPDATE
SET trg.value = code;
UPDATE table1 t1
SET t1.value =
(select t2.CODE from table2 t2
where t1.value = t2.DESC)
WHERE t1.UPDATETYPE='blah';
对table2使用description而不是desc,
update
table1
set
value = (select code from table2 where description = table1.value)
where
exists (select 1 from table2 where description = table1.value)
and
table1.updatetype = 'blah'
;
甲骨文基地在这方面做得很好。
https://oracle-base.com/articles/misc/updates-based-on-queries
从这个链接-我使用了上述查询的修改,这对我来说没有作用(答案来自mathguy,它使用rowid)
MERGE /*+ APPEND PARALLEL(8) */ INTO dest_table tt
USING source_table st
ON (tt.identifier = st.identifier)
WHEN MATCHED THEN
UPDATE SET tt.number = st.number;
这里我有两个表:source和dest,它们都有一个共同的varchar字段,我将源标识字段(PK)添加到dest表中。