我有一个查询，在MySQL工作得很好，但当我在Oracle上运行它时，我得到以下错误:
SQL错误:ORA-00933: SQL命令未正确结束 00933. 00000 - "SQL命令未正确结束"
查询为:
UPDATE table1
INNER JOIN table2 ON table1.value = table2.DESC
SET table1.value = table2.CODE
WHERE table1.UPDATETYPE='blah';
当前回答
UPDATE ( SELECT t1.value, t2.CODE
FROM table1 t1
INNER JOIN table2 t2 ON t1.Value = t2.DESC
WHERE t1.UPDATETYPE='blah')
SET t1.Value= t2.CODE
其他回答
UPDATE ( SELECT t1.value, t2.CODE
FROM table1 t1
INNER JOIN table2 t2 ON t1.Value = t2.DESC
WHERE t1.UPDATETYPE='blah')
SET t1.Value= t2.CODE
用WHERE子句合并:
MERGE into table1
USING table2
ON (table1.id = table2.id)
WHEN MATCHED THEN UPDATE SET table1.startdate = table2.start_date
WHERE table1.startdate > table2.start_date;
您需要WHERE子句，因为ON子句中引用的列不能更新。
如这里所示，Tony Andrews提出的第一个解决方案的通用语法是:
update some_table s
set (s.col1, s.col2) = (select x.col1, x.col2
from other_table x
where x.key_value = s.key_value
)
where exists (select 1
from other_table x
where x.key_value = s.key_value
)
我认为这很有趣，特别是当你想要更新多个字段时。
用这个:
MERGE
INTO table1 trg
USING (
SELECT t1.rowid AS rid, t2.code
FROM table1 t1
JOIN table2 t2
ON table1.value = table2.DESC
WHERE table1.UPDATETYPE='blah'
) src
ON (trg.rowid = src.rid)
WHEN MATCHED THEN UPDATE
SET trg.value = code;
UPDATE (SELECT T.FIELD A, S.FIELD B
FROM TABLE_T T INNER JOIN TABLE_S S
ON T.ID = S.ID)
SET B = A;
A和B是别名字段，不需要指向表。
