从UIAlertView类:

// UIAlertView已弃用。使用UIAlertController 将UIAlertControllerStyleAlert改为preferredStyle

在iOS 8上，你可以这样做:

let alert = UIAlertController(title: "Alert", message: "Message", preferredStyle: UIAlertControllerStyle.Alert)
alert.addAction(UIAlertAction(title: "Click", style: UIAlertActionStyle.Default, handler: nil))
self.presentViewController(alert, animated: true, completion: nil)

UIAlertController是一个单独的类，用于创建和交互我们在ios8中知道的UIAlertViews和UIActionSheets。

编辑:处理动作:

alert.addAction(UIAlertAction(title: "OK", style: .Default, handler: { action in
    switch action.style{
    case .Default:
        print("default")
        
    case .Cancel:
        print("cancel")
        
    case .Destructive:
        print("destructive")
    }
}}))

为Swift 3编辑:

let alert = UIAlertController(title: "Alert", message: "Message", preferredStyle: UIAlertControllerStyle.alert)
alert.addAction(UIAlertAction(title: "Click", style: UIAlertActionStyle.default, handler: nil))
self.present(alert, animated: true, completion: nil)

为Swift 4.x编辑:

let alert = UIAlertController(title: "Alert", message: "Message", preferredStyle: .alert)
alert.addAction(UIAlertAction(title: "OK", style: .default, handler: { action in
    switch action.style{
        case .default:
        print("default")
        
        case .cancel:
        print("cancel")
        
        case .destructive:
        print("destructive")
        
    }
}))
self.present(alert, animated: true, completion: nil)

我得到了以下UIAlertView初始化代码编译没有错误(我认为最后，变量部分可能是棘手的)。但我必须确保类的自我(我传递的委托)采用UIAlertViewDelegate协议编译错误消失:

let alertView = UIAlertView(
                  title: "My Title",
                  message: "My Message",
                  delegate: self,
                  cancelButtonTitle: "Cancel",
                  otherButtonTitles: "OK"
                )

顺便说一下，这是我得到的错误(作为Xcode 6.4):

无法为类型“UIAlertView”找到接受参数的初始化式 类型为'的参数列表(标题:字符串，消息:字符串，委托: MyViewController, cancelButtonTitle: String, otherbuttontitle: 字符串)”

正如其他人提到的，如果你的目标是iOS 8.x+，你应该迁移到UIAlertController。要支持iOS 7，请使用上面的代码(Swift不支持iOS 6)。

显示UIAlertView在swift语言:-

Protocol UIAlertViewDelegate

let alert = UIAlertView(title: "alertView", message: "This is alertView", delegate:self, cancelButtonTitle:"Cancel", otherButtonTitles: "Done", "Delete")
alert.show()

显示UIAlertViewController在swift语言:-

let alert = UIAlertController(title: "Error", message: "Enter data in Text fields", preferredStyle: UIAlertControllerStyle.Alert)
alert.addAction(UIAlertAction(title: "OK", style: UIAlertActionStyle.Default, handler: nil))
self.presentViewController(alert, animated: true, completion: nil)

@IBAction func Alert(sender: UIButton) {

    var alertView:UIAlertView = UIAlertView()
    alertView.title = "Alert!"
    alertView.message = "Message"
    alertView.delegate = self
    alertView.addButtonWithTitle("OK")

    alertView.show()

}

试试这个

  // UIAlertView is deprecated. Use UIAlertController 
  // title = title of the alert view.
  // message = Alert message you want to show.
  // By tap on "OK" , Alert view will dismiss.

 UIAlertView(title: "Alert", message: "Enter Message here.", delegate: nil, cancelButtonTitle: "OK").show()

我已经做了一个单例类，以便从应用程序的任何地方使用:https://github.com/Swinny1989/Swift-Popups

然后你可以创建一个带有多个按钮的弹出窗口，如下所示:

Popups.SharedInstance.ShowAlert(self, title: "Title goes here", message: "Messages goes here", buttons: ["button one" , "button two"]) { (buttonPressed) -> Void in
    if buttonPressed == "button one" { 
      //Code here
    } else if buttonPressed == "button two" {
        // Code here
    }
}

或者弹出一个按钮，像这样:

Popups.SharedInstance.ShowPopup("Title goes here", message: "Message goes here.")