我一直在努力创建一个UIAlertView在Swift,但由于某种原因,我不能得到正确的声明,因为我得到这个错误:

无法找到一个超载的'init'接受提供的 参数

我是这样写的:

let button2Alert: UIAlertView = UIAlertView(title: "Title", message: "message",
                     delegate: self, cancelButtonTitle: "OK", otherButtonTitles: nil)

然后我使用:

button2Alert.show()

到目前为止,它正在崩溃,我只是不能得到正确的语法。


当前回答

不要在构造函数中提供otherbuttontitle。

let alertView = UIAlertView(title: "Oops!", message: "Something
happened...", delegate: nil, cancelButtonTitle: "OK")

alertView.show()

但我同意Oscar的观点,这个类在iOS 8中被弃用了,所以如果你只做iOS 8的应用程序,UIAlertView不会没有任何用途。否则上面的代码将工作。

其他回答

通过Swift 2的协议扩展,你可以创建一个为视图控制器提供默认实现的协议:

ShowsAlert.swift

import UIKit

protocol ShowsAlert {}

extension ShowsAlert where Self: UIViewController {
    func showAlert(title: String = "Error", message: String) {
        let alertController = UIAlertController(title: title, message: message, preferredStyle: .Alert)
        alertController.addAction(UIAlertAction(title: "Ok", style: .Default, handler: nil))
        presentViewController(alertController, animated: true, completion: nil)
    }
}

ViewController.swift

class ViewController: UIViewController, ShowsAlert {
    override func viewDidLoad() {
        super.viewDidLoad()
        showAlert(message: "Hey there, I am an error message!")
    }
}

试试这个。 把波纹代码在按钮。

let alert = UIAlertController(title: "Your_Title_Text", message: "Your_MSG", preferredStyle: UIAlertControllerStyle.alert)
alert.addAction(UIAlertAction(title: "Your_Text", style: UIAlertActionStyle.default, handler: nil))
self.present(alert, animated:true, completion: nil)

适用于13.0以上版本 使用SceneDelegate

适用于所有类型的课程

static func showWindowAlert(alertMessage: String, inVC:UIViewController) {
        DispatchQueue.main.async(execute: {
            guard let windowScene = UIApplication.shared.connectedScenes.first as? UIWindowScene,
                let sceneDelegate = windowScene.delegate as? SceneDelegate
              else {
                return
              }
            sceneDelegate.window?.rootViewController = inVC
            sceneDelegate.window?.windowLevel = UIWindow.Level.alert + 1
        
            let alert2 = UIAlertController(title: App_Name, message: alertMessage, preferredStyle: .alert)
            let defaultAction2 = UIAlertAction(title: "OK", style: .default, handler: { action in
            })
            alert2.addAction(defaultAction2)
        
            sceneDelegate.window?.makeKeyAndVisible()
        
            sceneDelegate.window?.rootViewController?.present(alert2, animated: true, completion: nil)
        })
    }

你可以使用标准的构造函数创建一个UIAlert,但是“遗留的”构造函数似乎不起作用:

let alert = UIAlertView()
alert.title = "Alert"
alert.message = "Here's a message"
alert.addButtonWithTitle("Understood")
alert.show()

你可以使用这个简单的扩展与n个按钮和相关的动作swift4以上

extension UIViewController {
    func popupAlert(title: String?, message: String?, actionTitles:[String?], actions:[((UIAlertAction) -> Void)?]) {
        let alert = UIAlertController(title: title, message: message, preferredStyle: .alert)
        for (index, title) in actionTitles.enumerated() {
            let action = UIAlertAction(title: title, style: .default, handler: actions[index])
            alert.addAction(action)
        }
        self.present(alert, animated: true, completion: nil)
    }
}

你可以这样使用它,

self.popupAlert(title: "Message", message: "your message", actionTitles: ["first","second","third"], actions:[
            {action1 in
                //action for first btn click
            },
            {action2 in
                //action for second btn click
            },
            {action3 in
                //action for third btn click
            }, nil])