如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?

在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。


当前回答

这是一个简单的类用于简单的函数计时。下面有一个例子。

public class Stopwatch {
    static long startTime;
    static long splitTime;
    static long endTime;

    public Stopwatch() {
        start();
    }

    public void start() {
        startTime = System.currentTimeMillis();
        splitTime = System.currentTimeMillis();
        endTime = System.currentTimeMillis();
    }

    public void split() {
        split("");
    }

    public void split(String tag) {
        endTime = System.currentTimeMillis();
        System.out.println("Split time for [" + tag + "]: " + (endTime - splitTime) + " ms");
        splitTime = endTime;
    }

    public void end() {
        end("");
    }
    public void end(String tag) {
        endTime = System.currentTimeMillis();
        System.out.println("Final time for [" + tag + "]: " + (endTime - startTime) + " ms");
    }
}

使用示例:

public static Schedule getSchedule(Activity activity_context) {
        String scheduleJson = null;
        Schedule schedule = null;
/*->*/  Stopwatch stopwatch = new Stopwatch();

        InputStream scheduleJsonInputStream = activity_context.getResources().openRawResource(R.raw.skating_times);
/*->*/  stopwatch.split("open raw resource");

        scheduleJson = FileToString.convertStreamToString(scheduleJsonInputStream);
/*->*/  stopwatch.split("file to string");

        schedule = new Gson().fromJson(scheduleJson, Schedule.class);
/*->*/  stopwatch.split("parse Json");
/*->*/  stopwatch.end("Method getSchedule"); 
    return schedule;
}

控制台输出示例:

Split time for [file to string]: 672 ms
Split time for [parse Json]: 893 ms
Final time for [get Schedule]: 1565 ms

其他回答

如果您不使用工具,并且希望对执行时间较短的方法进行计时,那么只需执行多次,每次将执行次数增加一倍,直到达到1秒左右。因此,系统调用的时间。纳米时间等,也没有系统的准确性。nanoTime确实对结果有很大影响。

    int runs = 0, runsPerRound = 10;
    long begin = System.nanoTime(), end;
    do {
        for (int i=0; i<runsPerRound; ++i) timedMethod();
        end = System.nanoTime();
        runs += runsPerRound;
        runsPerRound *= 2;
    } while (runs < Integer.MAX_VALUE / 2 && 1000000000L > end - begin);
    System.out.println("Time for timedMethod() is " + 
        0.000000001 * (end-begin) / runs + " seconds");

当然,使用挂钟也有一些注意事项:jit编译、多线程/进程等的影响。因此,您需要首先执行该方法很多次,以便JIT编译器完成它的工作,然后重复此测试多次,并使用最短的执行时间。

非常好的代码。

http://www.rgagnon.com/javadetails/java-0585.html

import java.util.concurrent.TimeUnit;

long startTime = System.currentTimeMillis();
........
........
........
long finishTime = System.currentTimeMillis();

String diff = millisToShortDHMS(finishTime - startTime);


  /**
   * converts time (in milliseconds) to human-readable format
   *  "<dd:>hh:mm:ss"
   */
  public static String millisToShortDHMS(long duration) {
    String res = "";
    long days  = TimeUnit.MILLISECONDS.toDays(duration);
    long hours = TimeUnit.MILLISECONDS.toHours(duration)
                   - TimeUnit.DAYS.toHours(TimeUnit.MILLISECONDS.toDays(duration));
    long minutes = TimeUnit.MILLISECONDS.toMinutes(duration)
                     - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(duration));
    long seconds = TimeUnit.MILLISECONDS.toSeconds(duration)
                   - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(duration));
    if (days == 0) {
      res = String.format("%02d:%02d:%02d", hours, minutes, seconds);
    }
    else {
      res = String.format("%dd%02d:%02d:%02d", days, hours, minutes, seconds);
    }
    return res;
  }

Spring提供了一个实用工具类org.springframework.util。秒表,根据JavaDoc:

简单的秒表,允许计时多项任务,暴露 每个指定任务的总运行时间和运行时间。

用法:

StopWatch stopWatch = new StopWatch("Performance Test Result");

stopWatch.start("Method 1");
doSomething1();//method to test
stopWatch.stop();

stopWatch.start("Method 2");
doSomething2();//method to test
stopWatch.stop();

System.out.println(stopWatch.prettyPrint());

输出:

StopWatch 'Performance Test Result': running time (millis) = 12829
-----------------------------------------
ms     %     Task name
-----------------------------------------
11907  036%  Method 1
00922  064%  Method 2

方面:

@Around("execution(* my.package..*.*(..))")
public Object logTime(ProceedingJoinPoint joinPoint) throws Throwable {
    StopWatch stopWatch = new StopWatch();
    stopWatch.start();
    Object retVal = joinPoint.proceed();
    stopWatch.stop();
    log.info(" execution time: " + stopWatch.getTotalTimeMillis() + " ms");
    return retVal;
}

纯Java SE代码,不需要添加依赖项,使用TimeTracedExecuter:

public static void main(String[] args) {

    Integer square = new TimeTracedExecutor<>(Main::calculateSquare)
                .executeWithInput("calculate square of num",5,logger);

}
public static int calculateSquare(int num){
    return num*num;
}

会产生这样的结果:

信息:计算num的平方需要3毫秒

自定义可重用类:TimeTracedExecutor

import java.text.NumberFormat;
import java.time.Duration;
import java.time.Instant;
import java.util.function.Function;
import java.util.logging.Logger;

public class TimeTracedExecutor<T,R> {
    Function<T,R> methodToExecute;

    public TimeTracedExecutor(Function<T, R> methodToExecute) {
        this.methodToExecute = methodToExecute;
    }

    public R executeWithInput(String taskDescription, T t, Logger logger){
        Instant start = Instant.now();
        R r= methodToExecute.apply(t);
        Instant finish = Instant.now();
        String format = "It took %s milliseconds to "+taskDescription;
        String elapsedTime = NumberFormat.getNumberInstance().format(Duration.between(start, finish).toMillis());
        logger.info(String.format(format, elapsedTime));
        return r;
    }
}
long startTime = System.currentTimeMillis();
// code goes here
long finishTime = System.currentTimeMillis();
long elapsedTime = finishTime - startTime; // elapsed time in milliseconds