如何处理POST数据在Node.js?

如何从Node.js中的HTTP post方法中提取表单数据(form[method="post"])和文件上传?

我看了文件，谷歌了一下，什么都没找到。

function (request, response) {
    //request.post????
}

有图书馆或黑客吗?

当前回答

如果你正在使用Express.js，在你可以访问req. js之前。body，你必须添加中间件bodyParser:

app.use(express.bodyParser());

然后你可以要求

req.body.user

2013-08-10 22:46:03

其他回答

如果你从POST接收到JSON格式的数据。：

  import http from 'http';
  const hostname  = '127.0.0.1'; 
  const port = 3000;

  const httpServer:  http.Server = http.createServer((req: http.IncomingMessage, res: 
         http.ServerResponse) => {

        if(req.method === 'POST') {
        let body: string = ''; 
          req.on('data',(chunck) => {
            body += chunck;
          });

          req.on('end', () => {
            const body = JSON.parse(body);
            res.statusCode = 200;
            res.end('OK post');
          });
       }
 
     });

     httpServer.listen(port, hostname, () => {
       console.info(`Server started at port ${port}`);
     })

2021-04-18 21:01:06

如果你使用Express (Node.js的高性能、高级web开发)，你可以这样做:

HTML:

<form method="post" action="/">
    <input type="text" name="user[name]">
    <input type="text" name="user[email]">
    <input type="submit" value="Submit">
</form>

API客户端:

fetch('/', {
    method: 'POST',
    headers: {
        'Content-Type': 'application/json'
    },
    body: JSON.stringify({
        user: {
            name: "John",
            email: "john@example.com"
        }
    })
});

Node.js:(自Express v4.16.0起)

// Parse URL-encoded bodies (as sent by HTML forms)
app.use(express.urlencoded());

// Parse JSON bodies (as sent by API clients)
app.use(express.json());

// Access the parse results as request.body
app.post('/', function(request, response){
    console.log(request.body.user.name);
    console.log(request.body.user.email);
});

Node.js:(对于Express <4.16.0)

const bodyParser = require("body-parser");

/** bodyParser.urlencoded(options)
 * Parses the text as URL encoded data (which is how browsers tend to send form data from regular forms set to POST)
 * and exposes the resulting object (containing the keys and values) on req.body
 */
app.use(bodyParser.urlencoded({
    extended: true
}));

/**bodyParser.json(options)
 * Parses the text as JSON and exposes the resulting object on req.body.
 */
app.use(bodyParser.json());

app.post("/", function (req, res) {
    console.log(req.body.user.name)
});

2010-11-28 10:45:30

要详细说明使用URLSearchParams:

Node.js知识:如何读取POST数据? 类:URLSearchParams .js文档 MDN: URLSearchParams

const http = require('http');

const POST_HTML =
  '<html><head><title>Post Example</title></head>' +
  '<body>' +
  '<form method="post">' +
  'Input 1: <input name="input1"><br>' +
  'Input 2: <input name="input2"><br>' +
  'Input 1: <input name="input1"><br>' +
  '<input type="submit">' +
  '</form>' +
  '</body></html>';

const FORM_DATA = 'application/x-www-form-urlencoded';

function processFormData(body) {
  const params = new URLSearchParams(body);

  for ([name, value] of params.entries()) console.log(`${name}: ${value}`);
}

// req: http.IncomingMessage
// res: http.ServerResponse
//
function requestListener(req, res) {
  const contentType = req.headers['content-type'];
  let body = '';

  const append = (chunk) => {
    body += chunk;
  };
  const complete = () => {
    if (contentType === FORM_DATA) processFormData(body);

    res.writeHead(200);
    res.end(POST_HTML);
  };

  req.on('data', append);
  req.on('end', complete);
}

http.createServer(requestListener).listen(8080);

$ node index.js
input1: one
input2: two
input1: three

2022-05-22 15:40:17

Node.js 18的现代异步方式，零依赖:

server.mjs:

import { createServer } from 'node:http';

const rawReqToString = async (req) => {
    const buffers = [];
    for await(const chunk of req){
        buffers.push(chunk);
    }
    return Buffer.concat(buffers).toString();
};

const server = createServer(async (req, res) => {
    const object = JSON.parse(await rawReqToString(req));
    ...
});

server.listen(3000, 'localhost', () => {
    console.log(`The server is running.`);
})

2022-11-02 14:22:44

如果它涉及文件上传，浏览器通常以“multipart/form-data”内容类型发送它。您可以在这种情况下使用它

var multipart = require('multipart');
multipart.parse(req)

参考1

参考2

2015-08-13 13:52:06

如何处理POST数据在Node.js?

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