如何处理POST数据在Node.js?

如何从Node.js中的HTTP post方法中提取表单数据(form[method="post"])和文件上传?

我看了文件，谷歌了一下，什么都没找到。

function (request, response) {
    //request.post????
}

有图书馆或黑客吗?

当前回答

Node.js 18的现代异步方式，零依赖:

server.mjs:

import { createServer } from 'node:http';

const rawReqToString = async (req) => {
    const buffers = [];
    for await(const chunk of req){
        buffers.push(chunk);
    }
    return Buffer.concat(buffers).toString();
};

const server = createServer(async (req, res) => {
    const object = JSON.parse(await rawReqToString(req));
    ...
});

server.listen(3000, 'localhost', () => {
    console.log(`The server is running.`);
})

2022-11-02 14:22:44

其他回答

如果你使用node- terrible，你可以这样做:

var formidable = require("formidable");

var form = new formidable.IncomingForm();
form.parse(request, function (err, fields) {
    console.log(fields.parameter1);
    console.log(fields.parameter2);
    // ...
});

2014-05-20 22:59:37

有很多种方法。然而，我所知道的最快的方法是使用带有body-parser的Express.js库。

var express = require("express");
var bodyParser = require("body-parser");
var app = express();

app.use(bodyParser.urlencoded({extended : true}));

app.post("/pathpostdataissentto", function(request, response) {
  console.log(request.body);
  //Or
  console.log(request.body.fieldName);
});

app.listen(8080);

这可以用于字符串，但我要更改bodyParser。urlencoded to bodyParser。如果POST数据包含json数组，则改为json。

更多信息:http://www.kompulsa.com/how-to-accept-and-parse-post-requests-in-node-js/

2015-11-03 22:25:42

下面是一个非常简单的无框架包装，基于这里发布的其他答案和文章:

var http = require('http');
var querystring = require('querystring');

function processPost(request, response, callback) {
    var queryData = "";
    if(typeof callback !== 'function') return null;

    if(request.method == 'POST') {
        request.on('data', function(data) {
            queryData += data;
            if(queryData.length > 1e6) {
                queryData = "";
                response.writeHead(413, {'Content-Type': 'text/plain'}).end();
                request.connection.destroy();
            }
        });

        request.on('end', function() {
            request.post = querystring.parse(queryData);
            callback();
        });

    } else {
        response.writeHead(405, {'Content-Type': 'text/plain'});
        response.end();
    }
}

使用的例子:

http.createServer(function(request, response) {
    if(request.method == 'POST') {
        processPost(request, response, function() {
            console.log(request.post);
            // Use request.post here

            response.writeHead(200, "OK", {'Content-Type': 'text/plain'});
            response.end();
        });
    } else {
        response.writeHead(200, "OK", {'Content-Type': 'text/plain'});
        response.end();
    }

}).listen(8000);

2012-08-18 22:37:14

限制POST大小，避免淹没你的节点应用。有一个很棒的原始模块，适合表达和连接，可以帮助您限制大小和长度的请求。

2015-07-14 10:50:43

要详细说明使用URLSearchParams:

Node.js知识:如何读取POST数据? 类:URLSearchParams .js文档 MDN: URLSearchParams

const http = require('http');

const POST_HTML =
  '<html><head><title>Post Example</title></head>' +
  '<body>' +
  '<form method="post">' +
  'Input 1: <input name="input1"><br>' +
  'Input 2: <input name="input2"><br>' +
  'Input 1: <input name="input1"><br>' +
  '<input type="submit">' +
  '</form>' +
  '</body></html>';

const FORM_DATA = 'application/x-www-form-urlencoded';

function processFormData(body) {
  const params = new URLSearchParams(body);

  for ([name, value] of params.entries()) console.log(`${name}: ${value}`);
}

// req: http.IncomingMessage
// res: http.ServerResponse
//
function requestListener(req, res) {
  const contentType = req.headers['content-type'];
  let body = '';

  const append = (chunk) => {
    body += chunk;
  };
  const complete = () => {
    if (contentType === FORM_DATA) processFormData(body);

    res.writeHead(200);
    res.end(POST_HTML);
  };

  req.on('data', append);
  req.on('end', complete);
}

http.createServer(requestListener).listen(8080);

$ node index.js
input1: one
input2: two
input1: three

2022-05-22 15:40:17

如何处理POST数据在Node.js?

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