如何从Node.js中的HTTP post方法中提取表单数据(form[method="post"])和文件上传?
我看了文件,谷歌了一下,什么都没找到。
function (request, response) {
//request.post????
}
有图书馆或黑客吗?
如何从Node.js中的HTTP post方法中提取表单数据(form[method="post"])和文件上传?
我看了文件,谷歌了一下,什么都没找到。
function (request, response) {
//request.post????
}
有图书馆或黑客吗?
当前回答
如果你从POST接收到JSON格式的数据。:
import http from 'http';
const hostname = '127.0.0.1';
const port = 3000;
const httpServer: http.Server = http.createServer((req: http.IncomingMessage, res:
http.ServerResponse) => {
if(req.method === 'POST') {
let body: string = '';
req.on('data',(chunck) => {
body += chunck;
});
req.on('end', () => {
const body = JSON.parse(body);
res.statusCode = 200;
res.end('OK post');
});
}
});
httpServer.listen(port, hostname, () => {
console.info(`Server started at port ${port}`);
})
其他回答
如果有人试图淹没你的RAM,一定要杀死连接!
var qs = require('querystring');
function (request, response) {
if (request.method == 'POST') {
var body = '';
request.on('data', function (data) {
body += data;
// 1e6 === 1 * Math.pow(10, 6) === 1 * 1000000 ~~~ 1MB
if (body.length > 1e6) {
// FLOOD ATTACK OR FAULTY CLIENT, NUKE REQUEST
request.connection.destroy();
}
});
request.on('end', function () {
var POST = qs.parse(body);
// use POST
});
}
}
如果你从POST接收到JSON格式的数据。:
import http from 'http';
const hostname = '127.0.0.1';
const port = 3000;
const httpServer: http.Server = http.createServer((req: http.IncomingMessage, res:
http.ServerResponse) => {
if(req.method === 'POST') {
let body: string = '';
req.on('data',(chunck) => {
body += chunck;
});
req.on('end', () => {
const body = JSON.parse(body);
res.statusCode = 200;
res.end('OK post');
});
}
});
httpServer.listen(port, hostname, () => {
console.info(`Server started at port ${port}`);
})
Node.js 18的现代异步方式,零依赖:
server.mjs:
import { createServer } from 'node:http';
const rawReqToString = async (req) => {
const buffers = [];
for await(const chunk of req){
buffers.push(chunk);
}
return Buffer.concat(buffers).toString();
};
const server = createServer(async (req, res) => {
const object = JSON.parse(await rawReqToString(req));
...
});
server.listen(3000, 'localhost', () => {
console.log(`The server is running.`);
})
如果你使用node- terrible,你可以这样做:
var formidable = require("formidable");
var form = new formidable.IncomingForm();
form.parse(request, function (err, fields) {
console.log(fields.parameter1);
console.log(fields.parameter2);
// ...
});
如果它涉及文件上传,浏览器通常以“multipart/form-data”内容类型发送它。 您可以在这种情况下使用它
var multipart = require('multipart');
multipart.parse(req)
参考1
参考2