这是一个已知的错误，并不是因为文件太大。由于Android缓存Drawables，它会在使用少量图像后耗尽内存。但我找到了另一种方法，跳过android默认的缓存系统。

解决方案: 移动图像到“assets”文件夹，并使用以下函数来获得BitmapDrawable:

public static Drawable getAssetImage(Context context, String filename) throws IOException {
    AssetManager assets = context.getResources().getAssets();
    InputStream buffer = new BufferedInputStream((assets.open("drawable/" + filename + ".png")));
    Bitmap bitmap = BitmapFactory.decodeStream(buffer);
    return new BitmapDrawable(context.getResources(), bitmap);
}

我尝试了Thomas Vervest的方法，但是当IMAGE_MAX_SIZE为2048时，对于图像大小为2592x1944的图像，它返回1的比例。

根据其他人提供的所有其他评论，这个版本对我来说是有效的:

private Bitmap decodeFile (File f) {
    Bitmap b = null;
    try {
        // Decode image size
        BitmapFactory.Options o = new BitmapFactory.Options ();
        o.inJustDecodeBounds = true;

        FileInputStream fis = new FileInputStream (f);
        try {
            BitmapFactory.decodeStream (fis, null, o);
        } finally {
            fis.close ();
        }

        int scale = 1;
        for (int size = Math.max (o.outHeight, o.outWidth); 
            (size>>(scale-1)) > IMAGE_MAX_SIZE; ++scale);

        // Decode with inSampleSize
        BitmapFactory.Options o2 = new BitmapFactory.Options ();
        o2.inSampleSize = scale;
        fis = new FileInputStream (f);
        try {
            b = BitmapFactory.decodeStream (fis, null, o2);
        } finally {
            fis.close ();
        }
    } catch (IOException e) {
    }
    return b;
}

我使用解码文件描述符，它为我工作:

 FileInputStream  fileInputStream = null;
        try {
            fileInputStream  = new FileInputStream(file);
             FileDescriptor fd = fileInputStream.getFD();
            Bitmap imageBitmap = decodeSampledBitmapFromDescriptor(fd , 612,
                    816);
            imageView.setImageBitmap(imageBitmap);
        } catch (Exception e) {
            e.printStackTrace();
        }finally {
            if(fileInputStream != null){
                try {
                    fileInputStream.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }

从文件描述符解码采样位图的代码:

 /**
     * Decode and sample down a bitmap from a file input stream to the requested width and height.
     *
     * @param fileDescriptor The file descriptor to read from
     * @param reqWidth       The requested width of the resulting bitmap
     * @param reqHeight      The requested height of the resulting bitmap
     * @return A bitmap sampled down from the original with the same aspect ratio and dimensions
     * that are equal to or greater than the requested width and height
     */
    public static Bitmap decodeSampledBitmapFromDescriptor(
            FileDescriptor fileDescriptor, int reqWidth, int reqHeight) {

        // First decode with inJustDecodeBounds=true to check dimensions
        final BitmapFactory.Options options = new BitmapFactory.Options();
        options.inJustDecodeBounds = true;
        BitmapFactory.decodeFileDescriptor(fileDescriptor, null, options);

        // Calculate inSampleSize
        options.inSampleSize = calculateInSampleSize(options, reqWidth, reqHeight);

        // Decode bitmap with inSampleSize set
        options.inJustDecodeBounds = false;
        return BitmapFactory.decodeFileDescriptor(fileDescriptor, null, options);
    }

    /**
     * Calculate an inSampleSize for use in a {@link android.graphics.BitmapFactory.Options} object when decoding
     * bitmaps using the decode* methods from {@link android.graphics.BitmapFactory}. This implementation calculates
     * the closest inSampleSize that will result in the final decoded bitmap having a width and
     * height equal to or larger than the requested width and height. This implementation does not
     * ensure a power of 2 is returned for inSampleSize which can be faster when decoding but
     * results in a larger bitmap which isn't as useful for caching purposes.
     *
     * @param options   An options object with out* params already populated (run through a decode*
     *                  method with inJustDecodeBounds==true
     * @param reqWidth  The requested width of the resulting bitmap
     * @param reqHeight The requested height of the resulting bitmap
     * @return The value to be used for inSampleSize
     */
    public static int calculateInSampleSize(BitmapFactory.Options options,
                                            int reqWidth, int reqHeight) {
        // Raw height and width of image
        final int height = options.outHeight;
        final int width = options.outWidth;
        int inSampleSize = 1;

        if (height > reqHeight || width > reqWidth) {

            // Calculate ratios of height and width to requested height and width
            final int heightRatio = Math.round((float) height / (float) reqHeight);
            final int widthRatio = Math.round((float) width / (float) reqWidth);

            // Choose the smallest ratio as inSampleSize value, this will guarantee a final image
            // with both dimensions larger than or equal to the requested height and width.
            inSampleSize = heightRatio < widthRatio ? heightRatio : widthRatio;

            // This offers some additional logic in case the image has a strange
            // aspect ratio. For example, a panorama may have a much larger
            // width than height. In these cases the total pixels might still
            // end up being too large to fit comfortably in memory, so we should
            // be more aggressive with sample down the image (=larger inSampleSize).

            final float totalPixels = width * height;

            // Anything more than 2x the requested pixels we'll sample down further
            final float totalReqPixelsCap = reqWidth * reqHeight * 2;

            while (totalPixels / (inSampleSize * inSampleSize) > totalReqPixelsCap) {
                inSampleSize++;
            }
        }
        return inSampleSize;
    }

我花了一整天的时间来测试这些解决方案，唯一对我有用的是上面的获取图像和手动调用GC的方法，我知道这是不必要的，但当我把应用程序置于繁重的负载测试下时，这是唯一有效的方法。我的应用程序有一个缩略图列表在列表视图(让说活动a)，当你点击其中一个图像，它带你到另一个活动(让说活动B)，显示该项目的主图像。当我在两个活动之间来回切换时，我最终会得到OOM错误，应用程序将强制关闭。

当我走到列表视图一半的时候它就崩溃了。

现在，当我在活动B中实现以下内容时，我可以毫无问题地遍历整个列表视图，并继续下去……而且速度很快。

@Override
public void onDestroy()
{   
    Cleanup();
    super.onDestroy();
}

private void Cleanup()
{    
    bitmap.recycle();
    System.gc();
    Runtime.getRuntime().gc();  
}

这对我很管用!

public Bitmap readAssetsBitmap(String filename) throws IOException {
    try {
        BitmapFactory.Options options = new BitmapFactory.Options(); 
        options.inPurgeable = true;
        Bitmap bitmap = BitmapFactory.decodeStream(assets.open(filename), null, options);
        if(bitmap == null) {
            throw new IOException("File cannot be opened: It's value is null");
        } else {
            return bitmap;
        }
    } catch (IOException e) {
        throw new IOException("File cannot be opened: " + e.getMessage());
    }
}

嗨，请访问链接http://developer.android.com/training/displaying-bitmaps/index.html

或者只是尝试用给定的函数检索位图

private Bitmap decodeBitmapFile (File f) {
    Bitmap bitmap = null;
    try {
        // Decode image size
        BitmapFactory.Options o = new BitmapFactory.Options ();
        o.inJustDecodeBounds = true;

        FileInputStream fis = new FileInputStream (f);
        try {
            BitmapFactory.decodeStream (fis, null, o);
        } finally {
            fis.close ();
        }

        int scale = 1;
        for (int size = Math.max (o.outHeight, o.outWidth); 
            (size>>(scale-1)) > IMAGE_MAX_SIZE; ++scale);

        // Decode with input-stram SampleSize
        BitmapFactory.Options o2 = new BitmapFactory.Options ();
        o2.inSampleSize = scale;
        fis = new FileInputStream (f);
        try {
            bitmap  = BitmapFactory.decodeStream (fis, null, o2);
        } finally {
            fis.close ();
        }
    } catch (IOException e) {
    }
    return bitmap ;
}