我在一个正则表达式后，将验证一个完整的复杂的英国邮政编码只在输入字符串。所有不常见的邮政编码形式必须包括以及通常。例如:
匹配
CW3 9不锈钢 SE5 0EG SE50EG Se5 0eg WC2H 7LT
不匹配
aWC2H 7LT WC2H 7LTa WC2H
我怎么解决这个问题?
当前回答
我们得到了一个说明:
UK postcodes must be in one of the following forms (with one exception, see below):
§ A9 9AA
§ A99 9AA
§ AA9 9AA
§ AA99 9AA
§ A9A 9AA
§ AA9A 9AA
where A represents an alphabetic character and 9 represents a numeric character.
Additional rules apply to alphabetic characters, as follows:
§ The character in position 1 may not be Q, V or X
§ The character in position 2 may not be I, J or Z
§ The character in position 3 may not be I, L, M, N, O, P, Q, R, V, X, Y or Z
§ The character in position 4 may not be C, D, F, G, I, J, K, L, O, Q, S, T, U or Z
§ The characters in the rightmost two positions may not be C, I, K, M, O or V
The one exception that does not follow these general rules is the postcode "GIR 0AA", which is a special valid postcode.
我们想出了这个:
/^([A-PR-UWYZ][A-HK-Y0-9](?:[A-HJKS-UW0-9][ABEHMNPRV-Y0-9]?)?\s*[0-9][ABD-HJLNP-UW-Z]{2}|GIR\s*0AA)$/i
但是注意-这允许组之间有任意数量的空格。
其他回答
我需要一个可以在SAS中使用PRXMATCH和相关函数的版本，所以我想到了这个:
^[A-PR-UWYZ](([A-HK-Y]?\d\d?)|(\d[A-HJKPSTUW])|([A-HK-Y]\d[ABEHMNPRV-Y]))\s?\d[ABD-HJLNP-UW-Z]{2}$
测试用例和注意事项:
/*
Notes
The letters QVX are not used in the 1st position.
The letters IJZ are not used in the second position.
The only letters to appear in the third position are ABCDEFGHJKPSTUW when the structure starts with A9A.
The only letters to appear in the fourth position are ABEHMNPRVWXY when the structure starts with AA9A.
The final two letters do not use the letters CIKMOV, so as not to resemble digits or each other when hand-written.
*/
/*
Bits and pieces
1st position (any): [A-PR-UWYZ]
2nd position (if letter): [A-HK-Y]
3rd position (A1A format): [A-HJKPSTUW]
4th position (AA1A format): [ABEHMNPRV-Y]
Last 2 positions: [ABD-HJLNP-UW-Z]
*/
data example;
infile cards truncover;
input valid 1. postcode &$10. Notes &$100.;
flag = prxmatch('/^[A-PR-UWYZ](([A-HK-Y]?\d\d?)|(\d[A-HJKPSTUW])|([A-HK-Y]\d[ABEHMNPRV-Y]))\s?\d[ABD-HJLNP-UW-Z]{2}$/',strip(postcode));
cards;
1 EC1A 1BB Special case 1
1 W1A 0AX Special case 2
1 M1 1AE Standard format
1 B33 8TH Standard format
1 CR2 6XH Standard format
1 DN55 1PT Standard format
0 QN55 1PT Bad letter in 1st position
0 DI55 1PT Bad letter in 2nd position
0 W1Z 0AX Bad letter in 3rd position
0 EC1Z 1BB Bad letter in 4th position
0 DN55 1CT Bad letter in 2nd group
0 A11A 1AA Invalid digits in 1st group
0 AA11A 1AA 1st group too long
0 AA11 1AAA 2nd group too long
0 AA11 1AAA 2nd group too long
0 AAA 1AA No digit in 1st group
0 AA 1AA No digit in 1st group
0 A 1AA No digit in 1st group
0 1A 1AA Missing letter in 1st group
0 1 1AA Missing letter in 1st group
0 11 1AA Missing letter in 1st group
0 AA1 1A Missing letter in 2nd group
0 AA1 1 Missing letter in 2nd group
;
run;
我一直在寻找一个英国邮政编码正则表达式的最后一天左右，无意中发现了这个线程。我尝试了上面的大部分建议，但没有一个对我有用，所以我想出了自己的正则表达式，据我所知，它捕获了截至1月13日的所有有效的英国邮政编码(根据皇家邮政的最新文献)。
The regex and some simple postcode checking PHP code is posted below. NOTE:- It allows for lower or uppercase postcodes and the GIR 0AA anomaly but to deal with the, more than likely, presence of a space in the middle of an entered postcode it also makes use of a simple str_replace to remove the space before testing against the regex. Any discrepancies beyond that and the Royal Mail themselves don't even mention them in their literature (see http://www.royalmail.com/sites/default/files/docs/pdf/programmers_guide_edition_7_v5.pdf and start reading from page 17)!
注意:在皇家邮政自己的文献中(链接以上)，第3和第4位的位置略有模糊，如果这些字符是字母，则例外。我直接联系了皇家邮政，用他们自己的话说，“AANA NAA格式的出境代码的第4个位置的信件没有例外，而第3个位置的例外只适用于ANA NAA格式的出境代码的最后一个字母。”直接从马嘴里说出来的!
<?php
$postcoderegex = '/^([g][i][r][0][a][a])$|^((([a-pr-uwyz]{1}([0]|[1-9]\d?))|([a-pr-uwyz]{1}[a-hk-y]{1}([0]|[1-9]\d?))|([a-pr-uwyz]{1}[1-9][a-hjkps-uw]{1})|([a-pr-uwyz]{1}[a-hk-y]{1}[1-9][a-z]{1}))(\d[abd-hjlnp-uw-z]{2})?)$/i';
$postcode2check = str_replace(' ','',$postcode2check);
if (preg_match($postcoderegex, $postcode2check)) {
echo "$postcode2check is a valid postcode<br>";
} else {
echo "$postcode2check is not a valid postcode<br>";
}
?>
我希望它能帮助其他遇到这条线索寻找解决方案的人。
看起来我们将使用^(GIR ?0AA|[a - pr - uwyz]([0-9]{1,2}|([a - hk - y][0-9]([0-9ABEHMNPRV-Y])?)|[0-9][a - hjkps - uw])? [0-9][ABD-HJLNP-UW-Z]{2})$，这是上面Minglis建议的略有修改的版本。
然而，我们将不得不调查到底是什么规则，因为上面列出的各种解决方案似乎适用于不同的规则，哪些字母是允许的。
经过一番研究，我们找到了更多的信息。显然，“govtalk.gov.uk”上的一个页面会指向邮政编码规范govtalk-postcodes。它指向XML schema中的一个XML模式，该模式提供了邮政编码规则的“伪正则表达式”语句。
我们用它做了一些修改，得到了下面的表达式:
^((GIR &0AA)|((([A-PR-UWYZ][A-HK-Y]?[0-9][0-9]?)|(([A-PR-UWYZ][0-9][A-HJKSTUW])|([A-PR-UWYZ][A-HK-Y][0-9][ABEHMNPRV-Y]))) &[0-9][ABD-HJLNP-UW-Z]{2}))$
这使得空格是可选的，但限制您只能使用一个空格(将'&'替换为'{0，}表示无限空格)。它假定所有文本都必须是大写的。
如果你想要允许小写，任意数量的空格，使用:
^(([gG][iI][rR] {0,}0[aA]{2})|((([a-pr-uwyzA-PR-UWYZ][a-hk-yA-HK-Y]?[0-9][0-9]?)|(([a-pr-uwyzA-PR-UWYZ][0-9][a-hjkstuwA-HJKSTUW])|([a-pr-uwyzA-PR-UWYZ][a-hk-yA-HK-Y][0-9][abehmnprv-yABEHMNPRV-Y]))) {0,}[0-9][abd-hjlnp-uw-zABD-HJLNP-UW-Z]{2}))$
这并不包括海外领土，只是强制执行格式，而不是不同地区的存在。它基于以下规则:
可接受以下格式:
“秋天” A9 9 zz A99 9 zz AB9 9 zz AB99 9 zz A9C 9 zz AD9E 9 zz
地点:
9可以是任何一位数。 A可以是除Q、V或X之外的任何字母。 B可以是除I、J或Z之外的任何字母。 C可以是除I、L、M、N、O、P、Q、R、V、X、Y或Z之外的任何字母。 D可以是除I、J或Z之外的任何字母。 E可以是A, B, E, H, M, N, P, R, V, W, X或Y中的任意一个。 Z可以是C、I、K、M、O或V之外的任何字母。
最好的祝愿
科林
看看本页的python代码:
http://www.brunningonline.net/simon/blog/archives/001292.html
I've got some postcode parsing to do. The requirement is pretty simple; I have to parse a postcode into an outcode and (optional) incode. The good new is that I don't have to perform any validation - I just have to chop up what I've been provided with in a vaguely intelligent manner. I can't assume much about my import in terms of formatting, i.e. case and embedded spaces. But this isn't the bad news; the bad news is that I have to do it all in RPG. :-( Nevertheless, I threw a little Python function together to clarify my thinking.
我用它来处理邮政编码。
根据皇家邮政的程序员指南，检查邮政编码是否为有效格式:
|----------------------------outward code------------------------------| |------inward code-----|
#special↓ α1 α2 AAN AANA AANN AN ANN ANA (α3) N AA
^(GIR 0AA|[A-PR-UWYZ]([A-HK-Y]([0-9][A-Z]?|[1-9][0-9])|[1-9]([0-9]|[A-HJKPSTUW])?) [0-9][ABD-HJLNP-UW-Z]{2})$
uk上的所有邮编都匹配，除了那些不再使用的邮编。
增加一个?空格后，使用不区分大小写的匹配来回答这个问题:
'se50eg'.match(/^(GIR 0AA|[A-PR-UWYZ]([A-HK-Y]([0-9][A-Z]?|[1-9][0-9])|[1-9]([0-9]|[A-HJKPSTUW])?) ?[0-9][ABD-HJLNP-UW-Z]{2})$/ig);
Array [ "se50eg" ]
