我在一个正则表达式后,将验证一个完整的复杂的英国邮政编码只在输入字符串。所有不常见的邮政编码形式必须包括以及通常。例如:
匹配
CW3 9不锈钢 SE5 0EG SE50EG Se5 0eg WC2H 7LT
不匹配
aWC2H 7LT WC2H 7LTa WC2H
我怎么解决这个问题?
我在一个正则表达式后,将验证一个完整的复杂的英国邮政编码只在输入字符串。所有不常见的邮政编码形式必须包括以及通常。例如:
匹配
CW3 9不锈钢 SE5 0EG SE50EG Se5 0eg WC2H 7LT
不匹配
aWC2H 7LT WC2H 7LTa WC2H
我怎么解决这个问题?
当前回答
下面的方法将检查邮政编码并提供完整的信息
const isValidUKPostcode = postcode => {
try {
postcode = postcode.replace(/\s/g, "");
const fromat = postcode
.toUpperCase()
.match(/^([A-Z]{1,2}\d{1,2}[A-Z]?)\s*(\d[A-Z]{2})$/);
const finalValue = `${fromat[1]} ${fromat[2]}`;
const regex = /^([Gg][Ii][Rr] 0[Aa]{2})|((([A-Za-z][0-9]{1,2})|(([A-Za-z][A-Ha-hJ-Yj-y][0-9]{1,2})|(([AZa-z][0-9][A-Za-z])|([A-Za-z][A-Ha-hJ-Yj-y][0-9]?[A-Za-z]))))[0-9][A-Za-z]{2})$/i;
return {
isValid: regex.test(postcode),
formatedPostCode: finalValue,
error: false,
message: 'It is a valid postcode'
};
} catch (error) {
return { error: true , message: 'Invalid postcode'};
}
};
console.log(isValidUKPostcode('GU348RR'))
{isValid: true, formattedPostcode: "GU34 8RR", error: false, message: "It is a valid postcode"}
console.log(isValidUKPostcode('sdasd4746asd'))
{error: true, message: "Invalid postcode!"}
valid_postcode('787898523')
result => {error: true, message: "Invalid postcode"}
其他回答
^([A-PR-UWYZ0-9][A-HK-Y0-9][AEHMNPRTVXY0-9]?[ABEHMNPRVWXY0-9]? {1,2}[0-9][ABD-HJLN-UW-Z]{2}|GIR 0AA)$
Regular expression to match valid UK postcodes. In the UK postal system not all letters are used in all positions (the same with vehicle registration plates) and there are various rules to govern this. This regex takes into account those rules. Details of the rules: First half of postcode Valid formats [A-Z][A-Z][0-9][A-Z] [A-Z][A-Z][0-9][0-9] [A-Z][0-9][0-9] [A-Z][A-Z][0-9] [A-Z][A-Z][A-Z] [A-Z][0-9][A-Z] [A-Z][0-9] Exceptions Position - First. Contraint - QVX not used Position - Second. Contraint - IJZ not used except in GIR 0AA Position - Third. Constraint - AEHMNPRTVXY only used Position - Forth. Contraint - ABEHMNPRVWXY Second half of postcode Valid formats [0-9][A-Z][A-Z] Exceptions Position - Second and Third. Contraint - CIKMOV not used
http://regexlib.com/REDetails.aspx?regexp_id=260
根据维基百科的表格
这种模式适用于所有情况
(?:[A-Za-z]\d ?\d[A-Za-z]{2})|(?:[A-Za-z][A-Za-z\d]\d ?\d[A-Za-z]{2})|(?:[A-Za-z]{2}\d{2} ?\d[A-Za-z]{2})|(?:[A-Za-z]\d[A-Za-z] ?\d[A-Za-z]{2})|(?:[A-Za-z]{2}\d[A-Za-z] ?\d[A-Za-z]{2})
当在Android / Java上使用它时,使用\\d
下面是一个基于链接到marcj答案的文档中指定格式的正则表达式:
/^[A-Z]{1,2}[0-9][0-9A-Z]? ?[0-9][A-Z]{2}$/
这和规格之间的唯一区别是,根据规格,最后两个字符不能在[CIKMOV]中。
编辑: 下面是另一个测试末尾字符限制的版本。
/^[A-Z]{1,2}[0-9][0-9A-Z]? ?[0-9][A-BD-HJLNP-UW-Z]{2}$/
下面的方法将检查邮政编码并提供完整的信息
const isValidUKPostcode = postcode => {
try {
postcode = postcode.replace(/\s/g, "");
const fromat = postcode
.toUpperCase()
.match(/^([A-Z]{1,2}\d{1,2}[A-Z]?)\s*(\d[A-Z]{2})$/);
const finalValue = `${fromat[1]} ${fromat[2]}`;
const regex = /^([Gg][Ii][Rr] 0[Aa]{2})|((([A-Za-z][0-9]{1,2})|(([A-Za-z][A-Ha-hJ-Yj-y][0-9]{1,2})|(([AZa-z][0-9][A-Za-z])|([A-Za-z][A-Ha-hJ-Yj-y][0-9]?[A-Za-z]))))[0-9][A-Za-z]{2})$/i;
return {
isValid: regex.test(postcode),
formatedPostCode: finalValue,
error: false,
message: 'It is a valid postcode'
};
} catch (error) {
return { error: true , message: 'Invalid postcode'};
}
};
console.log(isValidUKPostcode('GU348RR'))
{isValid: true, formattedPostcode: "GU34 8RR", error: false, message: "It is a valid postcode"}
console.log(isValidUKPostcode('sdasd4746asd'))
{error: true, message: "Invalid postcode!"}
valid_postcode('787898523')
result => {error: true, message: "Invalid postcode"}
根据皇家邮政的程序员指南,检查邮政编码是否为有效格式:
|----------------------------outward code------------------------------| |------inward code-----|
#special↓ α1 α2 AAN AANA AANN AN ANN ANA (α3) N AA
^(GIR 0AA|[A-PR-UWYZ]([A-HK-Y]([0-9][A-Z]?|[1-9][0-9])|[1-9]([0-9]|[A-HJKPSTUW])?) [0-9][ABD-HJLNP-UW-Z]{2})$
uk上的所有邮编都匹配,除了那些不再使用的邮编。
增加一个?空格后,使用不区分大小写的匹配来回答这个问题:
'se50eg'.match(/^(GIR 0AA|[A-PR-UWYZ]([A-HK-Y]([0-9][A-Z]?|[1-9][0-9])|[1-9]([0-9]|[A-HJKPSTUW])?) ?[0-9][ABD-HJLNP-UW-Z]{2})$/ig);
Array [ "se50eg" ]