错误
% javac StringTest.java
StringTest.java:4: variable errorSoon might not have been initialized
errorSoon[0] = "Error, why?";
Code
public class StringTest {
public static void main(String[] args) {
String[] errorSoon;
errorSoon[0] = "Error, why?";
}
}
当前回答
String[] args = new String[]{"firstarg", "secondarg", "thirdarg"};
其他回答
String[] errorSoon = new String[n];
n是它需要容纳的字符串数。
你可以在声明中这样做，或者在以后不使用String[]的情况下这样做，只要是在你尝试使用它们之前。
你可以这样写
String[] errorSoon = {"Hello","World"};
For (int x=0;x<errorSoon.length;x++) // in this way u create a for loop that would like display the elements which are inside the array errorSoon.oh errorSoon.length is the same as errorSoon<2
{
System.out.println(" "+errorSoon[x]); // this will output those two words, at the top hello and world at the bottom of hello.
}
字符串声明:
String str;
字符串初始化
String[] str=new String[3];//if we give string[2] will get Exception insted
str[0]="Tej";
str[1]="Good";
str[2]="Girl";
String str="SSN";
我们可以在String中获取单个字符:
char chr=str.charAt(0);`//output will be S`
如果我想像这样获取单个字符的Ascii值:
System.out.println((int)chr); //output:83
现在我想转换Ascii值为字符/符号。
int n=(int)chr;
System.out.println((char)n);//output:S
我相信你刚刚从c++迁移过来，在java中，你必须初始化一个数据类型(除了原始类型和字符串在java中不被认为是原始类型)来根据它们的规范使用它们，如果你不这样做，那么它就像一个空引用变量(很像c++上下文中的指针)。
public class StringTest {
public static void main(String[] args) {
String[] errorSoon = new String[100];
errorSoon[0] = "Error, why?";
//another approach would be direct initialization
String[] errorsoon = {"Error , why?"};
}
}
String[] arr = {"foo", "bar"};
如果你将一个字符串数组传递给一个方法，执行以下操作:
myFunc(arr);
或做的事:
myFunc(new String[] {"foo", "bar"});
