错误
% javac StringTest.java
StringTest.java:4: variable errorSoon might not have been initialized
errorSoon[0] = "Error, why?";
Code
public class StringTest {
public static void main(String[] args) {
String[] errorSoon;
errorSoon[0] = "Error, why?";
}
}
当前回答
在Java 8中，我们还可以使用流。
String[] strings = Stream.of("First", "Second", "Third").toArray(String[]::new);
如果我们已经有一个字符串列表(stringList)，那么我们可以收集到字符串数组为:
String[] strings = stringList.stream().toArray(String[]::new);
其他回答
String[] arr = {"foo", "bar"};
如果你将一个字符串数组传递给一个方法，执行以下操作:
myFunc(arr);
或做的事:
myFunc(new String[] {"foo", "bar"});
你可以这样写
String[] errorSoon = {"Hello","World"};
For (int x=0;x<errorSoon.length;x++) // in this way u create a for loop that would like display the elements which are inside the array errorSoon.oh errorSoon.length is the same as errorSoon<2
{
System.out.println(" "+errorSoon[x]); // this will output those two words, at the top hello and world at the bottom of hello.
}
您可以使用下面的代码初始化大小并将空值设置为字符串数组
String[] row = new String[size];
Arrays.fill(row, "");
String[] args = new String[]{"firstarg", "secondarg", "thirdarg"};
在Java 8中，我们还可以使用流。
String[] strings = Stream.of("First", "Second", "Third").toArray(String[]::new);
如果我们已经有一个字符串列表(stringList)，那么我们可以收集到字符串数组为:
String[] strings = stringList.stream().toArray(String[]::new);
