var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
当前回答
@softvar的解决方案,但随后包括工作日期选项
/**
* Returns array of working days between two dates.
*
* @param {string} startDate
* The start date in yyyy-mm-dd format.
* @param {string} endDate
* The end date in yyyy-mm-dd format.
* @param {boolean} onlyWorkingDays
* If true only working days are returned. Default: false
*
* @return {array}
* Array of dates in yyyy-mm-dd string format.
*/
function getDates(startDate, stopDate, onlyWorkingDays) {
let doWd = typeof onlyWorkingDays ==='undefined' ? false : onlyWorkingDays;
let dateArray = [];
let dayNr;
let runDateObj = moment(startDate);
let stopDateObj = moment(stopDate);
while (runDateObj <= stopDateObj) {
dayNr = runDateObj.day();
if (!doWd || (dayNr>0 && dayNr<6)) {
dateArray.push(moment(runDateObj).format('YYYY-MM-DD'));
}
runDateObj = moment(runDateObj).add(1, 'days');
}
return dateArray;
}
其他回答
D3js提供了很多方便的函数,包括d3。是时候简单地处理日期了
https://github.com/d3/d3-time
针对您的具体要求:
Utc
var range = d3.utcDay.range(new Date(), d3.utcDay.offset(new Date(), 7));
或当地时间
var range = d3.timeDay.range(new Date(), d3.timeDay.offset(new Date(), 7));
Range将是一个日期对象数组,它位于每一天的第一个可能值上
您可以将timeDay更改为timeHour, timmonth等,在不同的间隔上获得相同的结果
我使用moment.js和Twix.js,它们为日期和时间操作提供了非常好的支持
var itr = moment.twix(new Date('2012-01-15'),new Date('2012-01-20')).iterate("days");
var range=[];
while(itr.hasNext()){
range.push(itr.next().toDate())
}
console.log(range);
我在http://jsfiddle.net/Lkzg1bxb/上运行这个程序
这里有一个不需要任何库的代码行,以防你不想创建另一个函数。只需用变量或日期值替换startDate(在两个地方)和endDate(这是js的日期对象)。当然,如果你愿意,你可以把它包装在一个函数中
Array(Math.floor((endDate - startDate) / 86400000) + 1).fill().map((_, idx) => (new Date(startDate.getTime() + idx * 86400000)))
这可能会帮助到一些人,
您可以从中获得行输出,并根据需要格式化row_date对象。
var from_date = '2016-01-01';
var to_date = '2016-02-20';
var dates = getDates(from_date, to_date);
console.log(dates);
function getDates(from_date, to_date) {
var current_date = new Date(from_date);
var end_date = new Date(to_date);
var getTimeDiff = Math.abs(current_date.getTime() - end_date.getTime());
var date_range = Math.ceil(getTimeDiff / (1000 * 3600 * 24)) + 1 ;
var weekday = ["SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT"];
var months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"];
var dates = new Array();
for (var i = 0; i <= date_range; i++) {
var getDate, getMonth = '';
if(current_date.getDate() < 10) { getDate = ('0'+ current_date.getDate());}
else{getDate = current_date.getDate();}
if(current_date.getMonth() < 9) { getMonth = ('0'+ (current_date.getMonth()+1));}
else{getMonth = current_date.getMonth();}
var row_date = {day: getDate, month: getMonth, year: current_date.getFullYear()};
var fmt_date = {weekDay: weekday[current_date.getDay()], date: getDate, month: months[current_date.getMonth()]};
var is_weekend = false;
if (current_date.getDay() == 0 || current_date.getDay() == 6) {
is_weekend = true;
}
dates.push({row_date: row_date, fmt_date: fmt_date, is_weekend: is_weekend});
current_date.setDate(current_date.getDate() + 1);
}
return dates;
}
https://gist.github.com/pranid/3c78f36253cbbc6a41a859c5d718f362.js
var boxingDay = new Date("12/26/2010");
var nextWeek = boxingDay*1 + 7*24*3600*1000;
function getDates( d1, d2 ){
var oneDay = 24*3600*1000;
for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
d.push( new Date(ms) );
}
return d;
}
getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)