我有这样一个嵌套列表:
l = [['40', '20', '10', '30'], ['20', '20', '20', '20', '20', '30', '20'], ['30', '20', '30', '50', '10', '30', '20', '20', '20'], ['100', '100'], ['100', '100', '100', '100', '100'], ['100', '100', '100', '100']]
我想把l中的每个元素都转换为float。我有这样的代码:
newList = []
for x in l:
for y in x:
newList.append(float(y))
如何用嵌套的列表理解来解决这个问题?
另请参阅:如何从列表理解而不是嵌套列表中获得平坦的结果?
当前回答
我想分享一下列表推导式实际上是如何工作的，特别是对于嵌套的列表推导式:
new_list= [float(x) for x in l]
其实和:
new_list=[]
for x in l:
new_list.append(float(x))
现在对于嵌套列表的理解:
[[float(y) for y in x] for x in l]
等于:
new_list=[]
for x in l:
sub_list=[]
for y in x:
sub_list.append(float(y))
new_list.append(sub_list)
print(new_list)
输出:
[[40.0, 20.0, 10.0, 30.0], [20.0, 20.0, 20.0, 20.0, 20.0, 30.0, 20.0], [30.0, 20.0, 30.0, 50.0, 10.0, 30.0, 20.0, 20.0, 20.0], [100.0, 100.0], [100.0, 100.0, 100.0, 100.0, 100.0], [100.0, 100.0, 100.0, 100.0]]
其他回答
deck = []
for rank in ranks:
for suit in suits:
deck.append(('%s%s')%(rank, suit))
这可以通过列表理解来实现:
[deck.append((rank,suit)) for suit in suits for rank in ranks ]
如果你不喜欢嵌套的列表推导式，你也可以使用map函数，
>>> from pprint import pprint
>>> l = l = [['40', '20', '10', '30'], ['20', '20', '20', '20', '20', '30', '20'], ['30', '20', '30', '50', '10', '30', '20', '20', '20'], ['100', '100'], ['100', '100', '100', '100', '100'], ['100', '100', '100', '100']]
>>> pprint(l)
[['40', '20', '10', '30'],
['20', '20', '20', '20', '20', '30', '20'],
['30', '20', '30', '50', '10', '30', '20', '20', '20'],
['100', '100'],
['100', '100', '100', '100', '100'],
['100', '100', '100', '100']]
>>> float_l = [map(float, nested_list) for nested_list in l]
>>> pprint(float_l)
[[40.0, 20.0, 10.0, 30.0],
[20.0, 20.0, 20.0, 20.0, 20.0, 30.0, 20.0],
[30.0, 20.0, 30.0, 50.0, 10.0, 30.0, 20.0, 20.0, 20.0],
[100.0, 100.0],
[100.0, 100.0, 100.0, 100.0, 100.0],
[100.0, 100.0, 100.0, 100.0]]
是的，你可以用这样的代码:
l = [[float(y) for y in x] for x in l]
在我看来，最好的方法是使用python的itertools包。
>>>import itertools
>>>l1 = [1,2,3]
>>>l2 = [10,20,30]
>>>[l*2 for l in itertools.chain(*[l1,l2])]
[2, 4, 6, 20, 40, 60]
我想分享一下列表推导式实际上是如何工作的，特别是对于嵌套的列表推导式:
new_list= [float(x) for x in l]
其实和:
new_list=[]
for x in l:
new_list.append(float(x))
现在对于嵌套列表的理解:
[[float(y) for y in x] for x in l]
等于:
new_list=[]
for x in l:
sub_list=[]
for y in x:
sub_list.append(float(y))
new_list.append(sub_list)
print(new_list)
输出:
[[40.0, 20.0, 10.0, 30.0], [20.0, 20.0, 20.0, 20.0, 20.0, 30.0, 20.0], [30.0, 20.0, 30.0, 50.0, 10.0, 30.0, 20.0, 20.0, 20.0], [100.0, 100.0], [100.0, 100.0, 100.0, 100.0, 100.0], [100.0, 100.0, 100.0, 100.0]]
