在我需要合并两行(为了更容易处理)，但允许数据超过特定的情况下，我发现这是有用的

data.txt

string1=x
string2=y
string3
string4

cat data.txt | nawk '$0 ~ /string1=/ { printf "%s ", $0; getline; printf "%s\n", $0; getline } { print }' > converted_data.txt

然后输出如下:

converted_data.txt

string1=x string2=y
string3
string4

粘贴很适合这个工作:

paste -d " "  - - < filename

如果Perl是一个选项，您可以尝试:

perl -0pe 's/(.*)\n(.*)\n/$1 $2\n/g' file.txt

使用vim的另一个解决方案(仅供参考)。

解决方案1:

打开vim vim文件名中的文件，然后执行命令:% normal Jj

这个命令很容易理解:

%:对于所有的行， Normal:执行正常命令 京晶:执行Join命令，然后跳转到线下

然后，保存文件并以:wq退出

解决方案2:

在shell中执行命令，vim -c ":% normal Jj" filename，保存文件并以:wq退出。

nawk '$0 ~ /string$/ {printf "%s ",$0; getline; printf "%s\n", $0}' filename

这读起来是

$0 ~ /string$/  ## matches any lines that end with the word string
printf          ## so print the first line without newline
getline         ## get the next line
printf "%s\n"   ## print the whole line and carriage return

下面是另一种使用awk的方法:

awk 'ORS=NR%2?FS:RS' file

$ cat file KEY 4048:1736 string 3 KEY 0:1772 string 1 KEY 4192:1349 string 1 KEY 7329:2407 string 2 KEY 0:1774 string 1 $ awk 'ORS=NR%2?FS:RS' file KEY 4048:1736 string 3 KEY 0:1772 string 1 KEY 4192:1349 string 1 KEY 7329:2407 string 2 KEY 0:1774 string 1 As indicated by Ed Morton in the comments, it is better to add braces for safety and parens for portability. awk '{ ORS = (NR%2 ? FS : RS) } 1' file ORS stands for Output Record Separator. What we are doing here is testing a condition using the NR which stores the line number. If the modulo of NR is a true value (>0) then we set the Output Field Separator to the value of FS (Field Separator) which by default is space, else we assign the value of RS (Record Separator) which is newline. If you wish to add , as the separator then use the following: awk '{ ORS = (NR%2 ? "," : RS) } 1' file