我需要删除日期时间的时间部分,或者可能有以下格式的日期在对象形式,而不是在字符串形式。
06/26/2009 00:00:00:000
我不能使用任何字符串转换方法,因为我需要对象形式的日期。
我尝试先将DateTime转换为字符串,从它中删除特定的时间日期,但它添加了12:00:00 AM,只要我将它转换回DateTime对象。
我需要删除日期时间的时间部分,或者可能有以下格式的日期在对象形式,而不是在字符串形式。
06/26/2009 00:00:00:000
我不能使用任何字符串转换方法,因为我需要对象形式的日期。
我尝试先将DateTime转换为字符串,从它中删除特定的时间日期,但它添加了12:00:00 AM,只要我将它转换回DateTime对象。
当前回答
我写了一个DateOnly结构。它在皮肤下使用一个DateTime,但没有时间部分被公开:
using System;
public struct DateOnly : IComparable, IFormattable, IComparable<DateOnly>, IEquatable<DateOnly>
{
private DateTime _dateValue;
public int CompareTo(object obj)
{
if (obj == null)
{
return 1;
}
DateOnly otherDateOnly = (DateOnly)obj;
if (otherDateOnly != null)
{
return ToDateTime().CompareTo(otherDateOnly.ToDateTime());
}
else
{
throw new ArgumentException("Object is not a DateOnly");
}
}
int IComparable<DateOnly>.CompareTo(DateOnly other)
{
return this.CompareToOfT(other);
}
public int CompareToOfT(DateOnly other)
{
// If other is not a valid object reference, this instance is greater.
if (other == new DateOnly())
{
return 1;
}
return this.ToDateTime().CompareTo(other.ToDateTime());
}
bool IEquatable<DateOnly>.Equals(DateOnly other)
{
return this.EqualsOfT(other);
}
public bool EqualsOfT(DateOnly other)
{
if (other == new DateOnly())
{
return false;
}
if (this.Year == other.Year && this.Month == other.Month && this.Day == other.Day)
{
return true;
}
else
{
return false;
}
}
public static DateOnly Now()
{
return new DateOnly(DateTime.Now.Year, DateTime.Now.Month, DateTime.Now.Day);
}
public static bool TryParse(string s, ref DateOnly result)
{
DateTime dateValue = default(DateTime);
if (DateTime.TryParse(s, out dateValue))
{
result = new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
return true;
}
else
{
return false;
}
}
public static DateOnly Parse(string s)
{
DateTime dateValue = default(DateTime);
dateValue = DateTime.Parse(s);
return new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
}
public static DateOnly ParseExact(string s, string format)
{
CultureInfo provider = CultureInfo.InvariantCulture;
DateTime dateValue = default(DateTime);
dateValue = DateTime.ParseExact(s, format, provider);
return new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
}
public DateOnly(int yearValue, int monthValue, int dayValue) : this()
{
Year = yearValue;
Month = monthValue;
Day = dayValue;
}
public DateOnly AddDays(double value)
{
DateTime d = new DateTime(this.Year, this.Month, this.Day);
d = d.AddDays(value);
return new DateOnly(d.Year, d.Month, d.Day);
}
public DateOnly AddMonths(int months)
{
DateTime d = new DateTime(this.Year, this.Month, this.Day);
d = d.AddMonths(months);
return new DateOnly(d.Year, d.Month, d.Day);
}
public DateOnly AddYears(int years)
{
DateTime d = new DateTime(this.Year, this.Month, this.Day);
d = d.AddYears(years);
return new DateOnly(d.Year, d.Month, d.Day);
}
public DayOfWeek DayOfWeek
{
get
{
return _dateValue.DayOfWeek;
}
}
public DateTime ToDateTime()
{
return _dateValue;
}
public int Year
{
get
{
return _dateValue.Year;
}
set
{
_dateValue = new DateTime(value, Month, Day);
}
}
public int Month
{
get
{
return _dateValue.Month;
}
set
{
_dateValue = new DateTime(Year, value, Day);
}
}
public int Day
{
get
{
return _dateValue.Day;
}
set
{
_dateValue = new DateTime(Year, Month, value);
}
}
public static bool operator == (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() == aDateOnly2.ToDateTime());
}
public static bool operator != (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() != aDateOnly2.ToDateTime());
}
public static bool operator > (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() > aDateOnly2.ToDateTime());
}
public static bool operator < (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() < aDateOnly2.ToDateTime());
}
public static bool operator >= (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() >= aDateOnly2.ToDateTime());
}
public static bool operator <= (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() <= aDateOnly2.ToDateTime());
}
public static TimeSpan operator - (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() - aDateOnly2.ToDateTime());
}
public override string ToString()
{
return _dateValue.ToShortDateString();
}
public string ToString(string format)
{
return _dateValue.ToString(format);
}
public string ToString(string fmt, IFormatProvider provider)
{
return string.Format("{0:" + fmt + "}", _dateValue);
}
public string ToShortDateString()
{
return _dateValue.ToShortDateString();
}
public string ToDbFormat()
{
return string.Format("{0:yyyy-MM-dd}", _dateValue);
}
}
这是从VB转换过来的。NET,所以抱歉,如果一些转换不是100%
其他回答
试试这个,如果你使用DateTimeOffset,它也会照顾时区
date1 = date1.LocalDateTime.Date;
如果你需要增加工作时间,可以这样做:
date1 = date1.LocalDateTime.Date;
date1 = date1.AddHours(23).AddMinutes(59).AddSeconds(59);
下面是另一个使用String的方法。格式
DateTime todaysDate = DateTime.UtcNow;
string dateString = String.Format("{0:dd/MM/yyyy}", todaysDate);
Console.WriteLine("Date with Time: "+ todaysDate.ToString());
Console.WriteLine("Date Only : " + dateString);
输出:
Date with Time: 9/4/2016 11:42:16 AM
Date Only : 04/09/2016
如果日期时间存储在数据库中,这也适用。
有关更多日期和时间格式,请检查这些链接:
参考1
参考2
希望有帮助。
我认为你会这样:DateTime onlyDate = DateTime. today . date; 或者,这是相同的DateTime onlyDate = yourDateTime.Date; 所以使用属性Date。
我知道这是一个有很多答案的老帖子,但我还没有见过这种删除时间部分的方法。假设您有一个名为myDate的DateTime变量,其中日期和时间部分。你可以从它创建一个新的DateTime对象,没有时间部分,使用这个构造函数:
public DateTime(int year, int month, int day);
是这样的:
myDate = new DateTime(myDate.Year, myDate.Month, myDate.Day);
通过这种方式,您可以基于旧的DateTime对象创建一个新的DateTime对象,其中00:00:00作为时间部分。
这可以简单地这样做:
var dateOnly = new DateTime(dateTime.Year, dateTime.Month, dateTime.Day)