我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
当前回答
Davidg建议使用词典。我想更进一步,使用集合:
months = set('January', 'February', ..., 'December')
现在你可以测试一个值是否与集合中的一个值匹配,如下所示:
if m in months:
但是,像dF,我通常只使用字符串常量来代替枚举。
其他回答
这里是一个实现:
class Enum(set):
def __getattr__(self, name):
if name in self:
return name
raise AttributeError
下面是它的用法:
Animals = Enum(["DOG", "CAT", "HORSE"])
print(Animals.DOG)
遵循Aaron Maenpaa提出的类Java枚举实现,我得出了以下结论。我们的想法是使它具有通用性和可解析性。
class Enum:
#'''
#Java like implementation for enums.
#
#Usage:
#class Tool(Enum): name = 'Tool'
#Tool.DRILL = Tool.register('drill')
#Tool.HAMMER = Tool.register('hammer')
#Tool.WRENCH = Tool.register('wrench')
#'''
name = 'Enum' # Enum name
_reg = dict([]) # Enum registered values
@classmethod
def register(cls, value):
#'''
#Registers a new value in this enum.
#
#@param value: New enum value.
#
#@return: New value wrapper instance.
#'''
inst = cls(value)
cls._reg[value] = inst
return inst
@classmethod
def parse(cls, value):
#'''
#Parses a value, returning the enum instance.
#
#@param value: Enum value.
#
#@return: Value corresp instance.
#'''
return cls._reg.get(value)
def __init__(self, value):
#'''
#Constructor (only for internal use).
#'''
self.value = value
def __str__(self):
#'''
#str() overload.
#'''
return self.value
def __repr__(self):
#'''
#repr() overload.
#'''
return "<" + self.name + ": " + self.value + ">"
def M_add_class_attribs(attribs):
def foo(name, bases, dict_):
for v, k in attribs:
dict_[k] = v
return type(name, bases, dict_)
return foo
def enum(*names):
class Foo(object):
__metaclass__ = M_add_class_attribs(enumerate(names))
def __setattr__(self, name, value): # this makes it read-only
raise NotImplementedError
return Foo()
像这样使用它:
Animal = enum('DOG', 'CAT')
Animal.DOG # returns 0
Animal.CAT # returns 1
Animal.DOG = 2 # raises NotImplementedError
如果你只想要唯一的符号,不关心值,替换这行:
__metaclass__ = M_add_class_attribs(enumerate(names))
用这个:
__metaclass__ = M_add_class_attribs((object(), name) for name in names)
如果你需要数值,这是最快的方法:
dog, cat, rabbit = range(3)
在Python 3中。X你也可以在最后添加一个星号占位符,它将吸收范围内所有剩余的值,以防你不介意浪费内存和无法计数:
dog, cat, rabbit, horse, *_ = range(100)
在答案列表中没有看到这个,这是我想出的一个。它允许使用'in'关键字和len()方法:
class EnumTypeError(TypeError):
pass
class Enum(object):
"""
Minics enum type from different languages
Usage:
Letters = Enum(list('abc'))
a = Letters.a
print(a in Letters) # True
print(54 in Letters) # False
"""
def __init__(self, enums):
if isinstance(enums, dict):
self.__dict__.update(enums)
elif isinstance(enums, list) or isinstance(enums, tuple):
self.__dict__.update(**dict((v,k) for k,v in enumerate(enums)))
else:
raise EnumTypeError
def __contains__(self, key):
return key in self.__dict__.values()
def __len__(self):
return len(self.__dict__.values())
if __name__ == '__main__':
print('Using a dictionary to create Enum:')
Letters = Enum(dict((v,k) for k,v in enumerate(list('abcde'))))
a = Letters.a
print('\tIs a in e?', a in Letters)
print('\tIs 54 in e?', 54 in Letters)
print('\tLength of Letters enum:', len(Letters))
print('\nUsing a list to create Enum:')
Letters = Enum(list('abcde'))
a = Letters.a
print('\tIs a in e?', a in Letters)
print('\tIs 54 in e?', 54 in Letters)
print('\tLength of Letters enum:', len(Letters))
try:
# make sure we raise an exception if we pass an invalid arg
Failure = Enum('This is a Failure')
print('Failure')
except EnumTypeError:
print('Success!')
输出:
Using a dictionary to create Enum:
Is a in e? True
Is 54 in e? False
Length of Letters enum: 5
Using a list to create Enum:
Is a in e? True
Is 54 in e? False
Length of Letters enum: 5
Success!