我想，我有ViewPager的逻辑。

如果我需要刷新一组页面并基于新的数据集显示它们，我调用notifyDataSetChanged()。 然后，ViewPager对getItemPosition()进行多次调用，将Fragment作为对象传递给那里。这个片段可以来自旧数据集(我想要丢弃的数据集)，也可以来自新数据集(我想要显示的数据集)。因此，我重写了getItemPosition()，在那里我必须以某种方式确定我的片段是来自旧数据集还是来自新数据集。

In my case I have a 2-pane layout with a list of top items on the left pane and a swipe view (ViewPager) on the right. So, I store a link to my current top item inside my PagerAdapter and also inside of each instantiated page Fragment. When the selected top item in the list changes, I store the new top item in PagerAdapter and call notifyDataSetChanged(). And in the overridden getItemPosition() I compare the top item from my adapter to the top item from my fragment. And only if they are not equal, I return POSITION_NONE. Then, PagerAdapter reinstantiates all the fragments that have returned POSITION_NONE.

请注意。存储顶部项id而不是引用可能是一个更好的主意。

下面的代码片段有点示意图，但我从实际工作的代码中改编了它。

public class SomeFragment extends Fragment {
  private TopItem topItem;
}

public class SomePagerAdapter extends FragmentStatePagerAdapter {
  private TopItem topItem;

  public void changeTopItem(TopItem newTopItem) {
    topItem = newTopItem;
    notifyDataSetChanged();
  }

  @Override
  public int getItemPosition(Object object) {
    if (((SomeFragment) object).getTopItemId() != topItem.getId()) {
      return POSITION_NONE;
    }
    return super.getItemPosition(object);
  }
}

感谢之前所有的研究人员!

这是一个可怕的问题，我很乐意提出一个极好的解决方案;简单、高效、有效!

如下所示，代码显示了使用一个标志来指示何时返回POSITION_NONE

public class ViewPagerAdapter extends PagerAdapter
{
    // Members
    private boolean mForceReinstantiateItem = false;

    // This is used to overcome terrible bug that Google isn't fixing
    // We know that getItemPosition() is called right after notifyDataSetChanged()
    // Therefore, the fix is to return POSITION_NONE right after the notifyDataSetChanged() was called - but only once
    @Override
    public int getItemPosition(Object object)
    {
        if (mForceReinstantiateItem)
        {
            mForceReinstantiateItem = false;
            return POSITION_NONE;
        }
        else
        {
            return super.getItemPosition(object);
        }
    }

    public void setData(ArrayList<DisplayContent> newContent)
    {
        mDisplayContent = newContent;
        mForceReinstantiateItem = true;
        notifyDataSetChanged();
    }

}

alvarolb给出的答案绝对是最好的方法。基于他的回答，实现这一点的一个简单方法是简单地按位置存储活动视图:

SparseArray<View> views = new SparseArray<View>();

@Override
public Object instantiateItem(View container, int position) {
    View root = <build your view here>;
    ((ViewPager) container).addView(root);
    views.put(position, root);
    return root;
}

@Override
public void destroyItem(View collection, int position, Object o) {
    View view = (View)o;
    ((ViewPager) collection).removeView(view);
    views.remove(position);
    view = null;
}

然后，一旦覆盖notifyDataSetChanged方法，您就可以刷新视图…

@Override
public void notifyDataSetChanged() {
    int key = 0;
    for(int i = 0; i < views.size(); i++) {
       key = views.keyAt(i);
       View view = views.get(key);
       <refresh view with new data>
    }
    super.notifyDataSetChanged();
}

实际上，您可以在instantiateItem和notifyDataSetChanged中使用类似的代码来刷新视图。在我的代码中，我使用了完全相同的方法。

1.首先，您必须在Pageradapter类中设置getItemposition方法 2.您必须阅读您的视图寻呼机的确切位置 3.然后将该位置作为新位置的数据位置发送 4.在setonPageChange监听器中写入更新按钮的点击监听器

我修改了程序代码，只设置了特定的位置元素

public class MyActivity extends Activity {

private ViewPager myViewPager;
private List<String> data;
public int location=0;
public Button updateButton;
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    data = new ArrayList<String>();
    data.add("A");
    data.add("B");
    data.add("C");
    data.add("D");
    data.add("E");
    data.add("F");

    myViewPager = (ViewPager) findViewById(R.id.pager);
    myViewPager.setAdapter(new MyViewPagerAdapter(this, data));

      updateButton = (Button) findViewById(R.id.update);

    myViewPager.setOnPageChangeListener(new ViewPager.OnPageChangeListener() {
        @Override
        public void onPageScrolled(int i, float v, int i2) {
             //Toast.makeText(MyActivity.this, i+"  Is Selected  "+data.size(), Toast.LENGTH_SHORT).show();
        }

        @Override
        public void onPageSelected( int i) {
          // here you will get the position of selected page
            final int k = i;
             updateViewPager(k);

        }

        @Override
        public void onPageScrollStateChanged(int i) {

        }
    });
}

private void updateViewPager(final int i) {  
    updateButton.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {

            Toast.makeText(MyActivity.this, i+"  Is Selected  "+data.size(), Toast.LENGTH_SHORT).show();
            data.set(i, "Replaced "+i);         
            myViewPager.getAdapter().notifyDataSetChanged();
        }
    });

}

private class MyViewPagerAdapter extends PagerAdapter {

    private List<String> data;
    private Context ctx;

    public MyViewPagerAdapter(Context ctx, List<String> data) {
        this.ctx = ctx;
        this.data = data;
    }

    @Override
    public int getCount() {
        return data.size();
    }

    @Override
    public int getItemPosition(Object object) {
        return POSITION_NONE;
    }

    @Override
    public Object instantiateItem(View collection, int position) {          

        TextView view = new TextView(ctx);
        view.setText(data.get(position));
        ((ViewPager)collection).addView(view);            
        return view;
    }

    @Override
    public void destroyItem(View collection, int position, Object view) {
         ((ViewPager) collection).removeView((View) view);
    }

    @Override
    public boolean isViewFromObject(View view, Object object) {
        return view == object;
    }

    @Override
    public Parcelable saveState() {
        return null;
    }

    @Override
    public void restoreState(Parcelable arg0, ClassLoader arg1) {
    }

    @Override
    public void startUpdate(View arg0) {
    }

    @Override
    public void finishUpdate(View arg0) {
    }
}
}

以防任何人使用FragmentStatePagerAdapter的适配器(这将让ViewPager创建显示所需的最小页面，对于我的情况最多2个页面)，@rui。araujo在适配器中覆盖getItemPosition的答案不会造成重大浪费，但仍然可以改进。

在伪代码中:

public int getItemPosition(Object object) {
    YourFragment f = (YourFragment) object;
    YourData d = f.data;
    logger.info("validate item position on page index: " + d.pageNo);

    int dataObjIdx = this.dataPages.indexOf(d);

    if (dataObjIdx < 0 || dataObjIdx != d.pageNo) {
        logger.info("data changed, discard this fragment.");
        return POSITION_NONE;
    }

    return POSITION_UNCHANGED;
}

而不是返回POSITION_NONE并再次创建所有片段，您可以按照我在这里建议的那样做:动态更新ViewPager ?