和在JavaScript中一样。

delete myArray[key];

注意，这将元素设置为undefined。

最好使用Array.prototype.splice函数:

const index = myArray.indexOf(key, 0);
if (index > -1) {
   myArray.splice(index, 1);
}

Let departments是一个数组。您要从此数组中删除一项。

departments: string[] = [];

 removeDepartment(name: string): void {
    this.departments = this.departments.filter(item => item != name);
  }

这对我很管用。

你的数组:

DummyArray: any = [
    { "id": 1, "name": 'A' },
    { "id": 2, "name": 'B' },
    { "id": 3, "name": 'C' },
    { "id": 4, "name": 'D' }
]

功能:

remove() {
    this.DummyArray = this.DummyArray.filter(item => item !== item);
}

注意:这个函数删除数组中的所有对象。如果你想从数组中删除一个特定的对象，那么使用这个方法:

remove(id) {
    this.DummyArray = this.DummyArray.filter(item => item.id !== id);
}

let foo_object; // Itemitem(object here) to remove
this.foo_objects = this.foo_objects.filter(obj => return obj !== foo_object);

我们可以使用筛选器和包含来实现逻辑

const checkAlpha2Code = ['BD', 'NZ', 'IN'] let countryAlpha2Code = ['US', 'CA', 'BD', 'NZ', 'AF' , 'AR' , 'BR'] /** * Returns the modified array countryAlpha2Code * after removing elements which matches with the checkAlpha2Code */ countryAlpha2Code = countryAlpha2Code.filter(alpha2code => { return !checkAlpha2Code.includes(alpha2code); }); console.log(countryAlpha2Code) // Output: [ 'US', 'CA', 'AF', 'AR', 'BR' ] // Resetting the values again countryAlpha2Code = ['US', 'CA', 'BD', 'NZ', 'AF' , 'AR' , 'BR'] /** * Returns the modified array countryAlpha2Code * which only matches elements with the checkAlpha2Code */ countryAlpha2Code = countryAlpha2Code.filter(alpha2code => { return checkAlpha2Code.includes(alpha2code); }); console.log(countryAlpha2Code) // Output: [ 'BD', 'NZ' ]

还有一个使用Typescript的解决方案:

let updatedArray = [];
for (let el of this.oldArray) {
    if (el !== elementToRemove) {
        updated.push(el);
    }
}
this.oldArray = updated;