还有一个使用Typescript的解决方案:

let updatedArray = [];
for (let el of this.oldArray) {
    if (el !== elementToRemove) {
        updated.push(el);
    }
}
this.oldArray = updated;

function myFunction(ID){ 
let index = this.myArray.findIndex(d => d.ID === ID); //find index in your array
        console.log('index==',index);
        if (index > -1) {
          console.log('remaving at',index);
          this.myArray.splice(index, 1);//remove element from array
        }
}

注意:你的数组必须有一个名为ID…否则将返回-1，表示未找到

下面是一个简单的一行代码，用于按属性从对象数组中删除对象。

delete this.items[this.items.findIndex(item => item.item_id == item_id)];

or

this.items = this.items.filter(item => item.item_id !== item.item_id);

let foo_object; // Itemitem(object here) to remove
this.foo_objects = this.foo_objects.filter(obj => return obj !== foo_object);

和在JavaScript中一样。

delete myArray[key];

注意，这将元素设置为undefined。

最好使用Array.prototype.splice函数:

const index = myArray.indexOf(key, 0);
if (index > -1) {
   myArray.splice(index, 1);
}

我们可以使用筛选器和包含来实现逻辑

const checkAlpha2Code = ['BD', 'NZ', 'IN'] let countryAlpha2Code = ['US', 'CA', 'BD', 'NZ', 'AF' , 'AR' , 'BR'] /** * Returns the modified array countryAlpha2Code * after removing elements which matches with the checkAlpha2Code */ countryAlpha2Code = countryAlpha2Code.filter(alpha2code => { return !checkAlpha2Code.includes(alpha2code); }); console.log(countryAlpha2Code) // Output: [ 'US', 'CA', 'AF', 'AR', 'BR' ] // Resetting the values again countryAlpha2Code = ['US', 'CA', 'BD', 'NZ', 'AF' , 'AR' , 'BR'] /** * Returns the modified array countryAlpha2Code * which only matches elements with the checkAlpha2Code */ countryAlpha2Code = countryAlpha2Code.filter(alpha2code => { return checkAlpha2Code.includes(alpha2code); }); console.log(countryAlpha2Code) // Output: [ 'BD', 'NZ' ]