要按键在原始JSON中出现的顺序获取键，请使用:

jq 'keys_unsorted' file.json

如果你想要键按字母数字排序，你可以使用:

jq 'keys' file.json

完整的示例

$ cat file.json
{ "Created-By" : "Apache Maven", "Build-Number" : "", "Archiver-Version" : "Plexus Archiver", "Build-Id" : "",  "Build-Tag" : "", "Built-By" : "cporter"}

$ jq 'keys_unsorted' file.json                                         
[
  "Created-By",
  "Build-Number",
  "Archiver-Version",
  "Build-Id",
  "Build-Tag",
  "Built-By"
]

$ jq 'keys' file.json
[
  "Archiver-Version",
  "Build-Id",
  "Build-Number",
  "Build-Tag",
  "Built-By",
  "Created-By"
]

将一行中的键打印为csv格式:

echo '{"b":"2","a":"1"}' | jq -r 'keys | [ .[] | tostring ] | @csv'

输出:

"a","b"

为了csv的完整性…将一行中的值打印为csv格式:

echo '{"b":"2","a":"1"}' | jq -rS . | jq -r '. | [ .[] | tostring ] | @csv'

输出:

"1","2"

Echo '{"ab": 1， "cd": 2}' | jq -r 'keys[]'打印所有键每行一个键，不带引号。

ab
cd

下面是@anubhava在他的回答中给出的JSON示例获得Bash数组的另一种方式:

arr=($(jq --raw-output 'keys_unsorted | @sh' file.json))

echo ${arr[0]}    # 'Archiver-Version'
echo ${arr[1]}    # 'Build-Id'
echo ${arr[2]}    # 'Build-Jdk'

如果你的输入是一个对象数组，

[
  { 
    "a01" : { "name" : "A", "user" : "B" }
  },
  { 
    "a02" : { "name" : "C", "user" : "D" }
  }
]

试一试:

jq '.[] | keys[]'

奇怪的是，公认的答案实际上并没有准确地回答问题，所以作为参考，这里有一个解决方案:

$ jq -r 'keys_unsorted[]' file.json