Curl http://testhost.test.com:8080/application/app/version | jq '。版本' | jq '.[]'
上面的命令只输出如下值:
"madireddy@test.com"
"2323"
"test"
"02-03-2014-13:41"
"application"
我怎样才能得到像下面这样的键名:
email
versionID
context
date
versionName
当前回答
你需要使用jq 'keys[]'。例如:
echo '{"example1" : 1, "example2" : 2, "example3" : 3}' | jq 'keys[]'
将输出一个行分隔的列表:
"example1"
"example2"
"example3"
其他回答
如果你的输入是一个对象数组，
[
{
"a01" : { "name" : "A", "user" : "B" }
},
{
"a02" : { "name" : "C", "user" : "D" }
}
]
试一试:
jq '.[] | keys[]'
下面是@anubhava在他的回答中给出的JSON示例获得Bash数组的另一种方式:
arr=($(jq --raw-output 'keys_unsorted | @sh' file.json))
echo ${arr[0]} # 'Archiver-Version'
echo ${arr[1]} # 'Build-Id'
echo ${arr[2]} # 'Build-Jdk'
你需要使用jq 'keys[]'。例如:
echo '{"example1" : 1, "example2" : 2, "example3" : 3}' | jq 'keys[]'
将输出一个行分隔的列表:
"example1"
"example2"
"example3"
获取JSON中更深层次节点上的键:
echo '{"data": "1", "user": { "name": 2, "phone": 3 } }' | jq '.user | keys[]'
"name"
"phone"
要按键在原始JSON中出现的顺序获取键，请使用:
jq 'keys_unsorted' file.json
如果你想要键按字母数字排序，你可以使用:
jq 'keys' file.json
完整的示例
$ cat file.json
{ "Created-By" : "Apache Maven", "Build-Number" : "", "Archiver-Version" : "Plexus Archiver", "Build-Id" : "", "Build-Tag" : "", "Built-By" : "cporter"}
$ jq 'keys_unsorted' file.json
[
"Created-By",
"Build-Number",
"Archiver-Version",
"Build-Id",
"Build-Tag",
"Built-By"
]
$ jq 'keys' file.json
[
"Archiver-Version",
"Build-Id",
"Build-Number",
"Build-Tag",
"Built-By",
"Created-By"
]
