我有这样的东西:

$scope.traveler = [
            {  description: 'Senior', Amount: 50},
            {  description: 'Senior', Amount: 50},
            {  description: 'Adult', Amount: 75},
            {  description: 'Child', Amount: 35},
            {  description: 'Infant', Amount: 25 },
];

现在,为了得到这个数组的总数量,我做了这样的事情:

$scope.totalAmount = function(){
       var total = 0;
       for (var i = 0; i < $scope.traveler.length; i++) {
              total = total + $scope.traveler[i].Amount;
            }
       return total;
}

当只有一个数组时,这很容易,但我有其他具有不同属性名的数组,我想要求和。

如果我能做这样的事情,我会更快乐:

$scope.traveler.Sum({ Amount });

但我不知道怎样才能在将来重复使用它:

$scope.someArray.Sum({ someProperty });

当前回答

如何使用Javascript和对象数组

const traveler = [
  {  description: 'Senior', Amount: 50},
  {  description: 'Senior', Amount: 50},
  {  description: 'Adult', Amount: 75},
  {  description: 'Child', Amount: 35},
  {  description: 'Infant', Amount: 25 }
];

Const traveler = [ {描述:'高级',数量:50}, {描述:'高级',数量:50}, {描述:“成人”,数量:75}, {描述:'Child',数量:35}, {描述:“婴儿”,数量:25}, ]; 函数sum(arrayData, key){ 返回arrayData.reduce((a,b) => { 返回{金额:a.金额+ b.金额} }) } console.log(总和(旅行) `

其他回答

只是另一种说法,这就是原生JavaScript函数Map和Reduce的用途(Map和Reduce是许多语言中的强大功能)。

var traveler = [{description: 'Senior', Amount: 50},
                {description: 'Senior', Amount: 50},
                {description: 'Adult', Amount: 75},
                {description: 'Child', Amount: 35},
                {description: 'Infant', Amount: 25}];

function amount(item){
  return item.Amount;
}

function sum(prev, next){
  return prev + next;
}

traveler.map(amount).reduce(sum);
// => 235;

// or use arrow functions
traveler.map(item => item.Amount).reduce((prev, next) => prev + next);

注意:通过创建独立的小函数,我们可以再次使用它们。

// Example of reuse.
// Get only Amounts greater than 0;

// Also, while using Javascript, stick with camelCase.
// If you do decide to go against the standards, 
// then maintain your decision with all keys as in...

// { description: 'Senior', Amount: 50 }

// would be

// { Description: 'Senior', Amount: 50 };

var travelers = [{description: 'Senior', amount: 50},
                {description: 'Senior', amount: 50},
                {description: 'Adult', amount: 75},
                {description: 'Child', amount: 35},
                {description: 'Infant', amount: 0 }];

// Directly above Travelers array I changed "Amount" to "amount" to match standards.

function amount(item){
  return item.amount;
}

travelers.filter(amount);
// => [{description: 'Senior', amount: 50},
//     {description: 'Senior', amount: 50},
//     {description: 'Adult', amount: 75},
//     {description: 'Child', amount: 35}];
//     Does not include "Infant" as 0 is falsey.

您可以使用jscollection库轻松的数据库查询作业,只需一行 https://github.com/somnathpanja/jscollection

var total = List.extend(traveler).select('Amount').sum();

下面是一个使用ES6箭头函数的一行程序。

const sumPropertyValue = (items, prop) => items.reduce((a, b) => a + b[prop], 0);

// usage:
const cart_items = [ {quantity: 3}, {quantity: 4}, {quantity: 2} ];
const cart_total = sumPropertyValue(cart_items, 'quantity');

也可以使用Array.prototype.forEach()

let totalAmount = 0;
$scope.traveler.forEach( data => totalAmount = totalAmount + data.Amount);
return totalAmount;

我想我应该在这一点上发表我的意见:这是那些应该始终是纯函数式的操作之一,不依赖于任何外部变量。有几个已经给出了很好的答案,使用减法是这里要走的路。

既然我们大多数人已经可以使用ES2015语法,下面是我的建议:

const sumValues = (obj) => Object.keys(obj).reduce((acc, value) => acc + obj[value], 0);

我们把它变成了一个不可变函数。reduce在这里所做的很简单: 从累加器的值0开始,并将当前循环项的值加到累加器中。

函数式编程和ES2015太棒了!:)