我有以下JSON结构:
[{ "id":"10", "class": "child-of-9" }, { "id": "11", "classd": "child-of-10" }]
我如何使用JavaScript迭代它?
我有以下JSON结构:
[{ "id":"10", "class": "child-of-9" }, { "id": "11", "classd": "child-of-10" }]
我如何使用JavaScript迭代它?
当前回答
从http://www.w3schools.com复制和粘贴,不需要JQuery开销。
var person = {fname:"John", lname:"Doe", age:25};
var text = "";
var x;
for (x in person) {
text += person[x];
}
结果:无名氏25人
其他回答
var jsonString = `{ "schema": { "title": "User Feedback", "description": "so", "type": "object", "properties": { "name": { "type": "string" } } }, "options": { "form": { "attributes": {}, "buttons": { "submit": { "title": "It", "click": "function(){alert('hello');}" } } } } }`; var jsonData = JSON.parse(jsonString); function Iterate(data) { jQuery.each(data, function (index, value) { if (typeof value == 'object') { alert("Object " + index); Iterate(value); } else { alert(index + " : " + value); } }); } Iterate(jsonData); <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
你可以使用像objx - http://objx.googlecode.com/这样的迷你库
你可以这样写代码:
var data = [ {"id":"10", "class": "child-of-9"},
{"id":"11", "class": "child-of-10"}];
// alert all IDs
objx(data).each(function(item) { alert(item.id) });
// get all IDs into a new array
var ids = objx(data).collect("id").obj();
// group by class
var grouped = objx(data).group(function(item){ return item.class; }).obj()
还有更多的“插件”可以让你这样处理数据,请参阅http://code.google.com/p/objx-plugins/wiki/PluginLibrary
使用的…:
var mycars = [{name:'Susita'}, {name:'BMW'}]; 对于(MyCars的VaR Car) { document.write(car.name + “<br />”); }
结果:
Susita
BMW
mootools的例子:
var ret = JSON.decode(jsonstr);
ret.each(function(item){
alert(item.id+'_'+item.classd);
});
对于嵌套对象,可以通过递归函数检索:
function inside(events)
{
for (i in events) {
if (typeof events[i] === 'object')
inside(events[i]);
else
alert(events[i]);
}
}
inside(events);
其中as events是json object。