我有以下JSON结构:
[{ "id":"10", "class": "child-of-9" }, { "id": "11", "classd": "child-of-10" }]
我如何使用JavaScript迭代它?
我有以下JSON结构:
[{ "id":"10", "class": "child-of-9" }, { "id": "11", "classd": "child-of-10" }]
我如何使用JavaScript迭代它?
当前回答
如果不容易,请告诉我:
var jsonObject = {
name: 'Amit Kumar',
Age: '27'
};
for (var prop in jsonObject) {
alert("Key:" + prop);
alert("Value:" + jsonObject[prop]);
}
其他回答
mootools的例子:
var ret = JSON.decode(jsonstr);
ret.each(function(item){
alert(item.id+'_'+item.classd);
});
如果不容易,请告诉我:
var jsonObject = {
name: 'Amit Kumar',
Age: '27'
};
for (var prop in jsonObject) {
alert("Key:" + prop);
alert("Value:" + jsonObject[prop]);
}
取自jQuery文档:
var arr = [ "one", "two", "three", "four", "five" ];
var obj = { one:1, two:2, three:3, four:4, five:5 };
jQuery.each(arr, function() {
$("#" + this).text("My id is " + this + ".");
return (this != "four"); // will stop running to skip "five"
});
jQuery.each(obj, function(i, val) {
$("#" + i).append(document.createTextNode(" - " + val));
});
如果这是你的数据数组:
var dataArray = [{"id":28,"class":"Sweden"}, {"id":56,"class":"USA"}, {"id":89,"class":"England"}];
然后:
$(jQuery.parseJSON(JSON.stringify(dataArray))).each(function() {
var ID = this.id;
var CLASS = this.class;
});
使用的…:
var mycars = [{name:'Susita'}, {name:'BMW'}]; 对于(MyCars的VaR Car) { document.write(car.name + “<br />”); }
结果:
Susita
BMW