这对我很有用……

// Handy JavaScript to measure the size taken to render the supplied text;
// you can supply additional style information too if you have it.

function measureText(pText, pFontSize, pStyle) {
    var lDiv = document.createElement('div');

    document.body.appendChild(lDiv);

    if (pStyle != null) {
        lDiv.style = pStyle;
    }
    lDiv.style.fontSize = "" + pFontSize + "px";
    lDiv.style.position = "absolute";
    lDiv.style.left = -1000;
    lDiv.style.top = -1000;

    lDiv.textContent = pText;

    var lResult = {
        width: lDiv.clientWidth,
        height: lDiv.clientHeight
    };

    document.body.removeChild(lDiv);
    lDiv = null;

    return lResult;
}

如果你可以安装一个包，并且你想要一个更权威或更精确的答案，你可以使用opentype.js(奇怪的是没有人提到这一点):

import { load } from "opentype.js";

const getWidth = async (text = "Hello World") => {
  const font = await load("path/to/some/font");
  const { x1, x2 } = font.getPath(text, 0, 0, 12).getBoundingBox();
  return x2 - x1;
};

当然，您希望每个字体只调用load一次，因此应该根据您的情况将该行拉出到更高的范围。

下面是一个代码沙盒，将OpenType方法与Canvas和DOM方法进行比较: https://codesandbox.io/s/measure-width-of-text-in-javascript-vctst2

在我的机器上，每个100个样品，典型的结果是:

女士的OpenType: 5 女士帆布:3 女士DOM: 4

我发现的另一个软件包是:https://github.com/sffc/word-wrappr

更好的方法是在显示元素之前检测文本是否合适。你可以使用这个函数它不需要元素在屏幕上。

function textWidth(text, fontProp) {
    var tag = document.createElement("div");
    tag.style.position = "absolute";
    tag.style.left = "-999em";
    tag.style.whiteSpace = "nowrap";
    tag.style.font = fontProp;
    tag.innerHTML = text;

    document.body.appendChild(tag);

    var result = tag.clientWidth;

    document.body.removeChild(tag);

    return result;
}

用法:

if ( textWidth("Text", "bold 13px Verdana") > elementWidth) {
    ...
}

var textWidth = (function (el) {
    el.style.position = 'absolute';
    el.style.top = '-1000px';
    document.body.appendChild(el);

    return function (text) {
        el.innerHTML = text;
        return el.clientWidth;
    };
})(document.createElement('div'));

如果有人在这里寻找一种测量字符串宽度的方法，以及一种知道适合特定宽度的最大字体大小的方法，这里有一个基于@Domi的解决方案的函数，使用二进制搜索:

/**
 * Find the largest font size (in pixels) that allows the string to fit in the given width.
 * 
 * @param {String} text - The text to be rendered.
 * @param {String} font - The css font descriptor that text is to be rendered with (e.g. "bold ?px verdana") -- note the use of ? in place of the font size.
 * @param {Number} width - The width in pixels the string must fit in
 * @param {Number} minFontPx - The smallest acceptable font size in pixels
 * @param {Number} maxFontPx - The largest acceptable font size in pixels
 **/
function GetTextSizeForWidth(text, font, width, minFontPx, maxFontPx) {
  for (;;) {
    var s = font.replace("?", maxFontPx);
    var w = GetTextWidth(text, s);
    if (w <= width) {
      return maxFontPx;
    }

    var g = (minFontPx + maxFontPx) / 2;

    if (Math.round(g) == Math.round(minFontPx) || Math.round(g) == Math.round(maxFontPx)) {
      return g;
    }

    s = font.replace("?", g);
    w = GetTextWidth(text, s);
    if (w >= width) {
      maxFontPx = g;
    } else {
      minFontPx = g;
    }
  }
}

下面的代码片段，“计算”span标签的宽度，如果它太长，就添加“…”，并减少文本长度，直到它适合它的父标签(或者直到它尝试了超过1000次)

CSS

div.places {
  width : 100px;
}
div.places span {
  white-space:nowrap;
  overflow:hidden;
}

HTML

<div class="places">
  <span>This is my house</span>
</div>
<div class="places">
  <span>And my house are your house</span>
</div>
<div class="places">
  <span>This placename is most certainly too wide to fit</span>
</div>

JavaScript(使用jQuery)

// loops elements classed "places" and checks if their child "span" is too long to fit
$(".places").each(function (index, item) {
    var obj = $(item).find("span");
    if (obj.length) {
        var placename = $(obj).text();
        if ($(obj).width() > $(item).width() && placename.trim().length > 0) {
            var limit = 0;
            do {
                limit++;
                                    placename = placename.substring(0, placename.length - 1);
                                    $(obj).text(placename + "...");
            } while ($(obj).width() > $(item).width() && limit < 1000)
        }
    }
});