我试图在MacOS X上使用IPython笔记本,使用Python 2.7.2和IPython 1.1.0。

我无法让matplotlib图形内联显示。

import matplotlib
import numpy as np
import matplotlib.pyplot as plt
%matplotlib inline  

我还尝试了%pylab inline和ipython命令行参数——pylab=inline,但这没有什么区别。

x = np.linspace(0, 3*np.pi, 500)
plt.plot(x, np.sin(x**2))
plt.title('A simple chirp')
plt.show()

而不是内联图形,我得到这个:

<matplotlib.figure.Figure at 0x110b9c450>

matplotlib.get_backend()显示我有'模块://IPython.kernel.zmq.pylab。backend_inline的后端。


当前回答

当我在Jupyter的独立单元中运行绘图命令时,我也遇到了同样的问题:

In [1]:  %matplotlib inline
         import matplotlib
         import matplotlib.pyplot as plt
         import numpy as np
In [2]:  x = np.array([1, 3, 4])
         y = np.array([1, 5, 3])
In [3]:  fig = plt.figure()
         <Figure size 432x288 with 0 Axes>                      #this might be the problem
In [4]:  ax = fig.add_subplot(1, 1, 1)
In [5]:  ax.scatter(x, y)
Out[5]:  <matplotlib.collections.PathCollection at 0x12341234>  # CAN'T SEE ANY PLOT :(
In [6]:  plt.show()                                             # STILL CAN'T SEE IT :(

通过将绘图命令合并到一个单元格中,问题得到了解决:

In [1]:  %matplotlib inline
         import matplotlib
         import matplotlib.pyplot as plt
         import numpy as np
In [2]:  x = np.array([1, 3, 4])
         y = np.array([1, 5, 3])
In [3]:  fig = plt.figure()
         ax = fig.add_subplot(1, 1, 1)
         ax.scatter(x, y)
Out[3]:  <matplotlib.collections.PathCollection at 0x12341234>
         # AND HERE APPEARS THE PLOT AS DESIRED :)

其他回答

Ctrl + Enter

%matplotlib inline

魔线:D

参见:用Matplotlib绘图。

您可以用一个语法错误来模拟这个问题,但是%matplotlib inline不能解决这个问题。

首先是一个创建情节的正确方法的例子。使用eNord9提供的导入和魔法,一切都按照预期工作。

df_randNumbers1 = pd.DataFrame(np.random.randint(0,100,size=(100, 6)), columns=list('ABCDEF'))

df_randNumbers1.ix[:,["A","B"]].plot.kde()

但是,如果将()放在plot类型的末尾,则会收到一个有点模糊的非错误。

Erronious代码:

df_randNumbers1.ix[:,["A","B"]].plot.kde

错误示例:

<bound method FramePlotMethods.kde of <pandas.tools.plotting.FramePlotMethods object at 0x000001DDAF029588>>

除了这一行消息之外,没有堆栈跟踪或其他明显的理由认为您犯了语法错误。情节没有打印出来。

当我在Jupyter的独立单元中运行绘图命令时,我也遇到了同样的问题:

In [1]:  %matplotlib inline
         import matplotlib
         import matplotlib.pyplot as plt
         import numpy as np
In [2]:  x = np.array([1, 3, 4])
         y = np.array([1, 5, 3])
In [3]:  fig = plt.figure()
         <Figure size 432x288 with 0 Axes>                      #this might be the problem
In [4]:  ax = fig.add_subplot(1, 1, 1)
In [5]:  ax.scatter(x, y)
Out[5]:  <matplotlib.collections.PathCollection at 0x12341234>  # CAN'T SEE ANY PLOT :(
In [6]:  plt.show()                                             # STILL CAN'T SEE IT :(

通过将绘图命令合并到一个单元格中,问题得到了解决:

In [1]:  %matplotlib inline
         import matplotlib
         import matplotlib.pyplot as plt
         import numpy as np
In [2]:  x = np.array([1, 3, 4])
         y = np.array([1, 5, 3])
In [3]:  fig = plt.figure()
         ax = fig.add_subplot(1, 1, 1)
         ax.scatter(x, y)
Out[3]:  <matplotlib.collections.PathCollection at 0x12341234>
         # AND HERE APPEARS THE PLOT AS DESIRED :)

我不得不同意foobarbecue的观点(我没有足够的参考资料来简单地在他的帖子下面插入评论):

现在建议不要使用参数——pylab来启动python notebook,根据Fernando Perez (ipythonnb的创建者)的说法,%matplotlib inline应该是初始notebook命令。

请看这里:http://nbviewer.ipython.org/github/ipython/ipython/blob/1.x/examples/notebooks/Part%203%20-%20Plotting%20with%20Matplotlib.ipynb

如果你在Visual Studio Code (VSCode)中使用Jupyter笔记本,那么内联后端似乎无法工作,所以你需要指定widget/ipympl(你可能需要安装支持,例如pip install ipympl):

%matplotlib widget