如何接受文件POST

我正在使用asp.net mvc 4 webapi beta来构建一个休息服务。我需要能够接受张贴的图像/文件从客户端应用程序。这可能使用webapi吗?下面是如何行动，我目前正在使用。有人知道一个例子吗?

[HttpPost]
public string ProfileImagePost(HttpPostedFile profileImage)
{
    string[] extensions = { ".jpg", ".jpeg", ".gif", ".bmp", ".png" };
    if (!extensions.Any(x => x.Equals(Path.GetExtension(profileImage.FileName.ToLower()), StringComparison.OrdinalIgnoreCase)))
    {
        throw new HttpResponseException("Invalid file type.", HttpStatusCode.BadRequest);
    }

    // Other code goes here

    return "/path/to/image.png";
}

当前回答

ASP。NET Core的方式现在在这里:

[HttpPost("UploadFiles")]
public async Task<IActionResult> Post(List<IFormFile> files)
{
    long size = files.Sum(f => f.Length);

    // full path to file in temp location
    var filePath = Path.GetTempFileName();

    foreach (var formFile in files)
    {
        if (formFile.Length > 0)
        {
            using (var stream = new FileStream(filePath, FileMode.Create))
            {
                await formFile.CopyToAsync(stream);
            }
        }
    }

    // process uploaded files
    // Don't rely on or trust the FileName property without validation.

    return Ok(new { count = files.Count, size, filePath});
}

2017-09-28 13:33:40

其他回答

API控制器:

[HttpPost]
public HttpResponseMessage Post()
{
    var httpRequest = System.Web.HttpContext.Current.Request;

    if (System.Web.HttpContext.Current.Request.Files.Count < 1)
    {
        //TODO
    }
    else
    {

    try
    { 
        foreach (string file in httpRequest.Files)
        { 
            var postedFile = httpRequest.Files[file];
            BinaryReader binReader = new BinaryReader(postedFile.InputStream);
            byte[] byteArray = binReader.ReadBytes(postedFile.ContentLength);

        }

    }
    catch (System.Exception e)
    {
        //TODO
    }

    return Request.CreateResponse(HttpStatusCode.Created);
}

2018-11-12 15:41:41

请参阅http://www.asp.net/web-api/overview/formats-and-model-binding/html-forms-and-multipart-mime#multipartmime，尽管我认为这篇文章让它看起来比实际情况更复杂。

基本上,

public Task<HttpResponseMessage> PostFile() 
{ 
    HttpRequestMessage request = this.Request; 
    if (!request.Content.IsMimeMultipartContent()) 
    { 
        throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType); 
    } 

    string root = System.Web.HttpContext.Current.Server.MapPath("~/App_Data/uploads"); 
    var provider = new MultipartFormDataStreamProvider(root); 

    var task = request.Content.ReadAsMultipartAsync(provider). 
        ContinueWith<HttpResponseMessage>(o => 
    { 

        string file1 = provider.BodyPartFileNames.First().Value;
        // this is the file name on the server where the file was saved 

        return new HttpResponseMessage() 
        { 
            Content = new StringContent("File uploaded.") 
        }; 
    } 
    ); 
    return task; 
}

2012-04-26 05:39:03

在我更新webapi mvc4项目中的所有nuget之前，我使用了Mike Wasson的答案。一旦我这样做了，我必须重写文件上传操作:

    public Task<HttpResponseMessage> Upload(int id)
    {
        HttpRequestMessage request = this.Request;
        if (!request.Content.IsMimeMultipartContent())
        {
            throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.UnsupportedMediaType));
        }

        string root = System.Web.HttpContext.Current.Server.MapPath("~/App_Data/uploads");
        var provider = new MultipartFormDataStreamProvider(root);

        var task = request.Content.ReadAsMultipartAsync(provider).
            ContinueWith<HttpResponseMessage>(o =>
            {
                FileInfo finfo = new FileInfo(provider.FileData.First().LocalFileName);

                string guid = Guid.NewGuid().ToString();

                File.Move(finfo.FullName, Path.Combine(root, guid + "_" + provider.FileData.First().Headers.ContentDisposition.FileName.Replace("\"", "")));

                return new HttpResponseMessage()
                {
                    Content = new StringContent("File uploaded.")
                };
            }
        );
        return task;
    }

显然BodyPartFileNames在MultipartFormDataStreamProvider中不再可用。

2013-05-01 18:46:05

这个问题甚至对于。net Core也有很多好的答案。我使用这两个框架提供的代码示例工作良好。我就不重复了。在我的例子中，重要的事情是如何使用Swagger的文件上传动作，就像这样:

以下是我的概述:

2 . asp.net WebAPI

上传文件使用:MultipartFormDataStreamProvider见答案在这里如何使用它与Swagger

net核心

上传文件使用:IFormFile见答案在这里或MS文档如何使用它与Swagger

2018-08-30 14:28:12

我在预览Web API时遇到了类似的问题。还没有将这部分移植到新的MVC 4 Web API，但这可能会有所帮助:

使用HttpRequestMessage或Stream上传REST文件?

请让我知道，可以坐下来，明天再试着实施它。