我如何通过一个列表循环，并抓住每一个项目?
我希望输出是这样的:
Console.WriteLine("amount is {0}, and type is {1}", myMoney.amount, myMoney.type);
这是我的代码:
static void Main(string[] args)
{
List<Money> myMoney = new List<Money>
{
new Money{amount = 10, type = "US"},
new Money{amount = 20, type = "US"}
};
}
class Money
{
public int amount { get; set; }
public string type { get; set; }
}
当前回答
低级迭代器操作代码:
List<Money> myMoney = new List<Money>
{
new Money{amount = 10, type = "US"},
new Money{amount = 20, type = "US"}
};
using (var enumerator = myMoney.GetEnumerator())
{
while (enumerator.MoveNext())
{
var element = enumerator.Current;
Console.WriteLine(element.amount);
}
}
其他回答
低级迭代器操作代码:
List<Money> myMoney = new List<Money>
{
new Money{amount = 10, type = "US"},
new Money{amount = 20, type = "US"}
};
using (var enumerator = myMoney.GetEnumerator())
{
while (enumerator.MoveNext())
{
var element = enumerator.Current;
Console.WriteLine(element.amount);
}
}
就像其他系列一样。随着List<T>的添加。ForEach方法。
foreach (var item in myMoney)
Console.WriteLine("amount is {0}, and type is {1}", item.amount, item.type);
for (int i = 0; i < myMoney.Count; i++)
Console.WriteLine("amount is {0}, and type is {1}", myMoney[i].amount, myMoney[i].type);
myMoney.ForEach(item => Console.WriteLine("amount is {0}, and type is {1}", item.amount, item.type));
你也可以使用while循环来实现
int ctr = 0;
while (ctr <= myMoney.Count - 1)
{
var data = myMoney[ctr];
Console.WriteLine($"{data.amount} - {data.type}");
ctr++;
}
这就是我如何用更函数的方式来写。代码如下:
new List<Money>()
{
new Money() { Amount = 10, Type = "US"},
new Money() { Amount = 20, Type = "US"}
}
.ForEach(money =>
{
Console.WriteLine($"amount is {money.Amount}, and type is {money.Type}");
});
为了完整起见，还有一种LINQ/Lambda方式:
myMoney.ForEach((theMoney) => Console.WriteLine("amount is {0}, and type is {1}", theMoney.amount, theMoney.type));
