是否有一个很好的简单的方法来删除MySQL数据库中的所有表,忽略任何外键约束,可能在那里?


当前回答

这是一个基于游标的解决方案。有点长,但可以作为单个SQL批处理:

DROP PROCEDURE IF EXISTS `drop_all_tables`;

DELIMITER $$
CREATE PROCEDURE `drop_all_tables`()
BEGIN
    DECLARE _done INT DEFAULT FALSE;
    DECLARE _tableName VARCHAR(255);
    DECLARE _cursor CURSOR FOR
        SELECT table_name 
        FROM information_schema.TABLES
        WHERE table_schema = SCHEMA();
    DECLARE CONTINUE HANDLER FOR NOT FOUND SET _done = TRUE;

    OPEN _cursor;

    REPEAT FETCH _cursor INTO _tableName;

    IF NOT _done THEN
        SET @stmt_sql = CONCAT('DROP TABLE ', _tableName);
        PREPARE stmt1 FROM @stmt_sql;
        EXECUTE stmt1;
        DEALLOCATE PREPARE stmt1;
    END IF;

    UNTIL _done END REPEAT;

    CLOSE _cursor;

END$$

DELIMITER ;

call drop_all_tables(); 

DROP PROCEDURE IF EXISTS `drop_all_tables`;

其他回答

谷歌主题总是把我带到这个SO问题,所以这里是工作的mysql代码,删除表和视图:

DROP PROCEDURE IF EXISTS `drop_all_tables`;

DELIMITER $$
CREATE PROCEDURE `drop_all_tables`()
BEGIN
    DECLARE _done INT DEFAULT FALSE;
    DECLARE _tableName VARCHAR(255);
    DECLARE _cursor CURSOR FOR
        SELECT table_name
        FROM information_schema.TABLES
        WHERE table_schema = SCHEMA();
    DECLARE CONTINUE HANDLER FOR NOT FOUND SET _done = TRUE;

    SET FOREIGN_KEY_CHECKS = 0;

    OPEN _cursor;

    REPEAT FETCH _cursor INTO _tableName;

    IF NOT _done THEN
        SET @stmt_sql1 = CONCAT('DROP TABLE IF EXISTS ', _tableName);
        SET @stmt_sql2 = CONCAT('DROP VIEW IF EXISTS ', _tableName);

        PREPARE stmt1 FROM @stmt_sql1;
        PREPARE stmt2 FROM @stmt_sql2;

        EXECUTE stmt1;
        EXECUTE stmt2;

        DEALLOCATE PREPARE stmt1;
        DEALLOCATE PREPARE stmt2;
    END IF;

    UNTIL _done END REPEAT;

    CLOSE _cursor;
    SET FOREIGN_KEY_CHECKS = 1;
END$$

DELIMITER ;

call drop_all_tables();

DROP PROCEDURE IF EXISTS `drop_all_tables`;

下面是修改后的SurlyDre的存储过程,这样外键就被忽略了:

DROP PROCEDURE IF EXISTS `drop_all_tables`;

DELIMITER $$
CREATE PROCEDURE `drop_all_tables`()
BEGIN
    DECLARE _done INT DEFAULT FALSE;
    DECLARE _tableName VARCHAR(255);
    DECLARE _cursor CURSOR FOR
        SELECT table_name 
        FROM information_schema.TABLES
        WHERE table_schema = SCHEMA();
    DECLARE CONTINUE HANDLER FOR NOT FOUND SET _done = TRUE;

    SET FOREIGN_KEY_CHECKS = 0;

    OPEN _cursor;

    REPEAT FETCH _cursor INTO _tableName;

    IF NOT _done THEN
        SET @stmt_sql = CONCAT('DROP TABLE ', _tableName);
        PREPARE stmt1 FROM @stmt_sql;
        EXECUTE stmt1;
        DEALLOCATE PREPARE stmt1;
    END IF;

    UNTIL _done END REPEAT;

    CLOSE _cursor;
    SET FOREIGN_KEY_CHECKS = 1;
END$$

DELIMITER ;

call drop_all_tables(); 

DROP PROCEDURE IF EXISTS `drop_all_tables`;

此解决方案基于@SkyLeach答案,但支持删除带外键的表。

echo "SET FOREIGN_KEY_CHECKS = 0;" > ./drop_all_tables.sql
mysqldump --add-drop-table --no-data -u user -p dbname | grep 'DROP TABLE' >> ./drop_all_tables.sql
echo "SET FOREIGN_KEY_CHECKS = 1;" >> ./drop_all_tables.sql
mysql -u user -p dbname < ./drop_all_tables.sql

只要在这里放上Jonathan Watt所做的一些有用的评论,就可以删除所有表格

MYSQL="mysql -h HOST -u USERNAME -pPASSWORD DB_NAME"
$MYSQL -BNe "show tables" | awk '{print "set foreign_key_checks=0; drop table `" $1 "`;"}' | $MYSQL
unset MYSQL

这对我有帮助,我希望它能有用

只是一个温馨的提醒,

如果可能并且没有其他问题,您可以删除数据库并重新创建它。

删除数据库<database_name> 创建数据库<database_name>