在PHP中,您可以。。。
range(1, 3); // Array(1, 2, 3)
range("A", "C"); // Array("A", "B", "C")
也就是说,有一个函数可以通过传递上下限来获得一系列数字或字符。
JavaScript本机是否有内置的功能?如果没有,我将如何实施?
在PHP中,您可以。。。
range(1, 3); // Array(1, 2, 3)
range("A", "C"); // Array("A", "B", "C")
也就是说,有一个函数可以通过传递上下限来获得一系列数字或字符。
JavaScript本机是否有内置的功能?如果没有,我将如何实施?
当前回答
使用TypeScript设置(应用程序范围):
declare global {
interface Function {
range(count: number, start_with: number): number[];
}
}
Function.prototype.range = function (
count: number,
start_with: number = 0
): number[] {
return [...Array(count).keys()].map((key) => key + start_with);
};
使用JS设置:
Function.prototype.range = function(count, start_with=0){
return [...Array(count).keys()].map((key) => key + start_with);
}
使用示例:
Function.range(2,0) //Will return [0,1]
Function.range(2,1) //Will return [1,2]
Function.range(2,-1) //Will return [-1,0]
其他回答
标准的Javascript没有生成范围的内置函数。有几个javascript框架添加了对这些功能的支持,或者正如其他人所指出的那样,您可以一直使用自己的功能。
如果您想再次检查,确定的资源是ECMA-262标准。
好的,在JavaScript中,我们没有像PHP那样的range()函数,所以我们需要创建一个非常简单的函数
对于数字:
function numberRange (start, end) {
return new Array(end - start).fill().map((d, i) => i + start);
}
并将其称为:
numberRange(5, 10); //[5, 6, 7, 8, 9]
对于字母:
function alphabetRange (start, end) {
return new Array(end.charCodeAt(0) - start.charCodeAt(0)).fill().map((d, i) => String.fromCharCode(i + start.charCodeAt(0)));
}
并将其称为:
alphabetRange('c', 'h'); //["c", "d", "e", "f", "g"]
简单范围函数:
function range(start, stop, step) {
var a = [start], b = start;
while (b < stop) {
a.push(b += step || 1);
}
return a;
}
要合并BigInt数据类型,可以包括一些检查,以确保所有变量都是相同的开始类型:
function range(start, stop, step) {
var a = [start], b = start;
if (typeof start == 'bigint') {
stop = BigInt(stop)
step = step? BigInt(step): 1n;
} else
step = step || 1;
while (b < stop) {
a.push(b += step);
}
return a;
}
要删除高于停止定义的值,例如范围(0,5,2)将包括6,但不应是。
function range(start, stop, step) {
var a = [start], b = start;
while (b < stop) {
a.push(b += step || 1);
}
return (b > stop) ? a.slice(0,-1) : a;
}
要紧密复制的类型脚本函数
/**
* Create a generator from 0 to stop, useful for iteration. Similar to range in Python.
* See: https://stackoverflow.com/questions/3895478/does-javascript-have-a-method-like-range-to-generate-a-range-within-the-supp
* See: https://docs.python.org/3/library/stdtypes.html#ranges
* @param {number | BigNumber} stop
* @returns {Iterable<number>}
*/
export function range(stop: number | BigNumber): Iterable<number>
/**
* Create a generator from start to stop, useful for iteration. Similar to range in Python.
* See: https://stackoverflow.com/questions/3895478/does-javascript-have-a-method-like-range-to-generate-a-range-within-the-supp
* See: https://docs.python.org/3/library/stdtypes.html#ranges
* @param {number | BigNumber} start
* @param {number | BigNumber} stop
* @returns {Iterable<number>}
*/
export function range(
start: number | BigNumber,
stop: number | BigNumber,
): Iterable<number>
/**
* Create a generator from start to stop while skipping every step, useful for iteration. Similar to range in Python.
* See: https://stackoverflow.com/questions/3895478/does-javascript-have-a-method-like-range-to-generate-a-range-within-the-supp
* See: https://docs.python.org/3/library/stdtypes.html#ranges
* @param {number | BigNumber} start
* @param {number | BigNumber} stop
* @param {number | BigNumber} step
* @returns {Iterable<number>}
*/
export function range(
start: number | BigNumber,
stop: number | BigNumber,
step: number | BigNumber,
): Iterable<number>
export function* range(a: unknown, b?: unknown, c?: unknown): Iterable<number> {
const getNumber = (val: unknown): number =>
typeof val === 'number' ? val : (val as BigNumber).toNumber()
const getStart = () => (b === undefined ? 0 : getNumber(a))
const getStop = () => (b === undefined ? getNumber(a) : getNumber(b))
const getStep = () => (c === undefined ? 1 : getNumber(c))
for (let i = getStart(); i < getStop(); i += getStep()) {
yield i
}
}
---更新(感谢@lokhmakov简化)---
另一个使用ES6发生器的版本(参见伟大的Paolo Moretti回答ES6发生器):
const RANGE = (x,y) => Array.from((function*(){
while (x <= y) yield x++;
})());
console.log(RANGE(3,7)); // [ 3, 4, 5, 6, 7 ]
或者,如果我们只需要可迭代,那么:
const RANGE_ITER = (x,y) => (function*(){
while (x <= y) yield x++;
})();
for (let n of RANGE_ITER(3,7)){
console.log(n);
}
// 3
// 4
// 5
// 6
// 7
---原始代码为:---
const RANGE = (a,b) => Array.from((function*(x,y){
while (x <= y) yield x++;
})(a,b));
and
const RANGE_ITER = (a,b) => (function*(x,y){
while (x <= y) yield x++;
})(a,b);